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5 votes
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Expansion of the associated Legendre polynomials $P^m_l(\cos\vartheta)$ for $\vartheta \righ...

In view the Rodrigues formula for the associated Legendre polynomials, one finds $$a_{nm}=\lim_{\vartheta\rightarrow 0} \vartheta^{-m}P^m_n(\cos\vartheta)= (-1)^m\frac{1}{2^n n!} \lim_{x\rightarrow 1} …
Carlo Beenakker's user avatar
2 votes
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How are the Legendre Polynomials of second kind for negative degrees defined?

It helps to rewrite the expression from Gradshteyn, $$Q_\nu^0(z)=\frac{ \Gamma \left(\frac{1}{2}\right) \Gamma (\nu+1)\, _2F_1\left(\frac{\nu}{2}+1,\frac{\nu}{2}+\frac{1}{2};\nu+\frac{3}{2};\frac{1}{z …
Carlo Beenakker's user avatar
3 votes

Proof of spherical harmonic addition theorem

The OP asks for a group theoretic derivation that is also elementary. I have not found one which combines these two properties (unless one considers the rotation operator as "elementary"). Considered …
Carlo Beenakker's user avatar
10 votes

How to obtain the asymptotics of Legendre polynomials directly from their generating function

As described in Analytic Combinatorics by Flajolet and Sedgewick, page 4, the pole $t_0$ of the generating function $F(t)$ of smallest absolute value governs the exponential asymptotics $P_n\sim (1/t_ …
Carlo Beenakker's user avatar
6 votes
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Legendre Polynomial Integral over half space

Integration of Equation (34) in MathWorld gives the integral $I_{nm}$ as a sum $$I_{nm}=\sum _{q=0}^m \frac{2^{-q}}{q+1} \binom{-m-1}{q} \binom{m}{q} \, _3F_2\left(-n,n+1,q+1;1,q+2;\tfrac{1}{2}\right …
Carlo Beenakker's user avatar
1 vote

Integral with Legendre polynomial

I don't have a general expression as a function of $n$, but there is one in terms of harmonic numbers $H_k$ as a function of $k\in\mathbb{R}^+$ for given $n$; for example $$I_{2,k}=\tfrac{1}{2}\Gamm …
Carlo Beenakker's user avatar
1 vote

Integral formula involving Legendre polynomial

Not a derivation (yet), but at least a reduction to a more familiar form: $$\int_{-1}^{1}\sqrt{\frac{1-x}{2}} P_n(x) \text{d}{x}=4\int_0^1 z^2\,P_n(1-2z^2)\,dz$$ which is a special case, $\mu=3/2$, …
Carlo Beenakker's user avatar
3 votes
Accepted

Symmetric matrix formula for Gauss-Legendre quadrature

This is a particular implementation of a more general method, described in John Boyd's Why Eigenvalues Are Roots: A Derivation of the One-Dimensional Companion Matrix for General Orthogonal Polynomial …
Carlo Beenakker's user avatar
4 votes
Accepted

Reference for the exponential decay of Legendre coefficients

This is theorem 2.1 in On the convergence rates of Legendre approximation (2012) [yes, with a proof in English]
Carlo Beenakker's user avatar