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This tag is used if a reference is needed in a paper or textbook on a specific result.

11 votes
Accepted

Extending state space to make a process Feller

Yes, it is possible to extend the state space with respect to which $Y$ is a Feller process. Then, $X$ will be a dense open subset of the extension $\hat X$. Furthermore, for any initial distribution …
YCor's user avatar
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2 votes
Accepted

Stieltjes convolution with white noise

This is just an application of Ito's formula. Normally, Brownian motion $W(t)$ is only defined for nonnegative times $t$, so I'm assuming that $W(t)=0$ for $t\le0$, although it doesn't really matter m …
jeq's user avatar
  • 1,228
13 votes
Accepted

The functional equation $f(f(x))=x+f(x)^2$

Having thought about this question some more, including making some plots of the trajectories of points under iterated applications of $f$ (see Gottfried's circular trajectories), it is possible to de …
jeq's user avatar
  • 1,228
2 votes

Hilbert transforms of measures

Showing that the two definitions agree almost everywhere is easy! Using the truncated transform $$ \mathcal{H}\_\epsilon\mu(x)=\frac1\pi\int_{\lvert y-x\rvert > \epsilon}\frac{d\mu(y)}{x-y} $$ then, b …
George Lowther's user avatar
3 votes
Accepted

Limit connected with a periodic function

No, convergence does not hold for all irrational $x$. I posted a full answer to the question at math.stackexchange and I'll summarize the result here. There are uncountably many values of $x$ for whi …
Community's user avatar
  • 1
10 votes

Does there exist an event independent of a given sigma-algebra?

No. If the probability space contains atoms then you can easily construct sub-$\sigma$-algebras which are not independent to any nontrivial events. However, we can still construct examples, even for …
George Lowther's user avatar
11 votes

Uniformization theorem for Riemann surfaces

I learned the proof from this paper, Uniformization of Riemann Surfaces. They actually provide three methods of proof, and I found the first of these the easiest to follow. Its not too difficult to go …
George Lowther's user avatar