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14
votes
2
answers
664
views
What is a model category from an $\infty$ point of view?
a dense generator, so we can see $\infty$-categories as presheaves on $\Delta$
Simplicially enriched categories: Simplicial enrichment is a proxy for enrichment in $\mathrm{Cat}_{(\infty, 0)}$
Simplicial … mathrm{Cat}_{(1,1)}$
Complete segal spaces: These look to be inspired by models in $\mathrm{Cat}_{(\infty, 0)}$ of the finite limit sketch defining categories
Relative categories: A pair $(C,W)$ is a proxy …
7
votes
0
answers
212
views
Moduli in semialgebraic geometry
If there is no development along these lines, then I would also be happy if anyone knows a good proxy that appears in the literature. …
2
votes
1
answer
2k
views
Bounds on the eigenvalues of the covariance matrix of a sub-Gaussian vector
Suppose that $\boldsymbol{x}\in\mathbb{R}^n$ is subgaussian random vector of variance proxy $\sigma^2$, i.e.,
$$\forall \boldsymbol{\alpha}\in\mathbb{R}^n: \quad \quad \mathbb{E}\left[ \exp\right(\boldsymbol …
3
votes
0
answers
81
views
How can we use Martingales to identify an unknown particle?
This gives $Y_N$ with subgaussian proxy $\Sigma_N = \sum_i \sigma_i^2$. Then we can guess positive charge if $Y_N > 1/2$ and negative if $Y_N \le 1/2$. … The subgaussian proxy says the guess is correct with probability $O(e^{-K \Sigma_n})$ for some fixed $K >0$.
So far so good. But what if we are instead interested in tail bounds for the guesses. …
2
votes
1
answer
85
views
The number of Hamiltonian circuits on a convex polytope embedded in $\mathbb{R}^N$
After some reflection it occurred to me that the number of distinct Hamiltonian cycles on a convex polytope may be a useful proxy measure. …
1
vote
1
answer
159
views
Optimum control of a probabilistic automaton
We could assign proxy weights to each state based on what overall payoff the states seem to offer and choose strategies which maximize this but how would one prove such a "greedy" approach is optimal. …
102
votes
6
answers
11k
views
Is there an analogue of curvature in algebraic geometry?
This reminds me a little bit of tropical geometry wherein one replaces an algebraic variety with a simple combinatorial proxy, but from what little I know the analogy seems to stop there. …
1
vote
1
answer
1k
views
Coupon Collector Problem for Non-Uniform Coupons: Bound on the number of missed Coupons
.
$$$$
$$$$
Old description:
Topic: Multinomial proxy variables: Bound on probability of their sums
Suppose $(X_1,X_2,..X_i,..,X_b)$ as multinomial vector of random variables with $N=\sum_{i=1}^b … Therefore let us define a non-negative penalty function (a truncated proxy random variable) for each tube as follows:
$$
y(X_i) =
\begin{cases}
X_i-1 &,~for~ X_i \geq 2\\
0 &,~else\\
\end{cases}
$$ …
5
votes
1
answer
531
views
What is the correct definition of semisimple linear category?
However, I have an issue with their (and by proxy, Müger's) approach. Namely, they require that the category has finite biproducts (direct sums). …
2
votes
0
answers
298
views
Maps between graphs defined through laplacian operations
As such, we can define an operation which maps a graph onto another, by proxy. …
7
votes
2
answers
1k
views
The (Sigma) Algebra of Convex Sets
This is a question-by-proxy for a colleague from computer science. …
6
votes
Accepted
Uncountable model of bounded arithmetic with an elementary end extension
a conclusion about what is true in the original universe, nevertheless one may omit it by taking a countable elementary substructure of a suitable $H_\theta$, in effect replacing $M$ with a countable proxy … Applying the theorem to the proxy, you get that the proxy satisfies $\text{PA}$, and so $M\models\text{PA}$ as well. …
2
votes
Expected rank - computable approximations
This norm is the "closest" convex proxy to the rank function (in the same sense as $\|x\|_1$ is the convex proxy to $\|x\|_0$, the cardinality function. …
2
votes
0
answers
218
views
Characterizing non-zero polynomials on semialgebraic sets: a kind of positivstellensatz gene...
One way out of this is to search among all polynomials of the form $q = \sigma_0 + \sum_i \sigma_i f_i$, and try to find a $q$ whose symmetric positive semidefinite Gram matrix is of rank one, a convex proxy …
18
votes
4
answers
915
views
Arrow's theorem and the postseason
Is there a function from such multigraphs to ordered lists of size $n$ (N.B. that the order isn't meant to represent the relative strength of the teams, but is just a proxy for the extra structure of the …