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Subsets of the Cantor set

A copy of the Cantor set is a space homeomorphic to $2^{\omega}$. Suppose that $X$ is a Hausdorff space that contains a copy $C^{\prime}$ of the Cantor set. Let $U$ be a nonempty subset open in $C^{\...
gaam2296's user avatar
1 vote
1 answer
143 views

Is the Rudin-Keisler ordering a continuous relation?

If $X, Y$ are topological, and $R\subseteq X\times Y$ we say that $R$ is continuous (from $X$ to $Y$) if for every $V\subseteq Y$ with $V$ open, we have $$R^{-1}(V) = \{u\in U: \exists v\in V:(u,v)\...
Dominic van der Zypen's user avatar
1 vote
2 answers
176 views

Connected Hausdorff spaces with large collection of disjoint open sets

Is there for every infinite cardinal $\kappa$ a connected Hausdorff space $(X,\tau)$ with $|X| = \kappa$ and a collection ${\cal D}$ of mutually disjoint open sets with $|{\cal D}| = \kappa$?
Dominic van der Zypen's user avatar
1 vote
1 answer
136 views

A permutation group inducing a topologically transitive action without dense orbits on $\omega^*$

Let $G$ be a subgroup of the permutation group $S_\omega$ of the countable infinite set $\omega$. Each bijection $g\in G$ admits a unique extension to a homeomorphism $\bar g$ of the Stone-Cech ...
Taras Banakh's user avatar
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1 vote
1 answer
117 views

Does there exist a starcompact space which is not star-$K$-compact?

A space $X$ is said to be starcompact if for every open cover $\mathcal U$ of $X$ there exists a finite subset $\mathcal V\subseteq\mathcal U$ such that $St(\cup\mathcal V,\mathcal U)=X$. A space $X$ ...
Nur Alam's user avatar
  • 505
1 vote
1 answer
217 views

Connected Hausdorff spaces with different cardinalities of open sets

Given an infinite cardinal $\kappa$, is there a connected Hausdorff space $(X,\tau)$ with $|X|=\kappa$, and for every infinite cardinal $\lambda \leq \kappa$ there is an open set $U\in \tau$ with $|U| ...
Dominic van der Zypen's user avatar
1 vote
1 answer
124 views

Is there some characterization of $\omega^\omega$-base related to $S_\omega$?

For a topological space $X$ and one point $x\in X$, we call the cofinal type of neighborhood bases of $x$ are cofinally finer than $\omega^\omega$-base if for any neighborhood base $\mathfrak{N}$ of $...
Leijie Wang's user avatar
1 vote
1 answer
149 views

Descending almost-contained subsets of $\omega$ [closed]

Let $A$ be an infinite subset of $\omega$ such that $\omega\setminus A$ is also infinite. Under the Continuum Hypothesis is there a sequence $(A_\alpha)_{\alpha<\omega_1}$ of subsets of $\omega$ ...
Forever Mozart's user avatar
1 vote
2 answers
223 views

Covering dimension of uncountable union of compact spaces

It is well-known that the (covering) dimension of countable union of compact spaces is the superium dimension of these spaces. I would like to understand certain uncountable union of compact spaces as ...
user119197's user avatar
1 vote
1 answer
278 views

Borel hierarchy and tail sets

Let $A$ be a finite set, and let $A^\infty$ be the set of all sequences $(a_n)_{n=1}^\infty$ of elements of $A$. A set $B \subseteq A^\infty$ is a tail set if for every two sequences $\vec a, \vec b \...
Eilon's user avatar
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1 vote
0 answers
70 views

A ZFC example of a star-$K$-Menger space which is not star-$K$-Hurewicz

An open cover $\mathcal U$ of a space $X$ is said to be $\gamma$-cover if $\mathcal U$ is infinite and for each $x\in X$, the set $\{U\in\mathcal U : x\notin U\}$ is finite. A space $X$ is said to be ...
Nur Alam's user avatar
  • 505
1 vote
0 answers
84 views

Terminology for the property: "Each uncountable disjoint open family is locally countable"

Suppose that a topological space $X$ satisfies the following property (P): "Each uncountable disjoint open family is locally countable", where a family $\mathcal U$ of subsets of $X$ is ...
Nur Alam's user avatar
  • 505
1 vote
0 answers
88 views

Are there results on cardinal function using o-tightness?

Recall that a space $X$ has countable $o$-tightness, if for every family $\mathcal U$ of open sets of $X$ and for each $x \in X$ with $x \in \overline{\bigcup \mathcal U}$, there exists a countable ...
Paul's user avatar
  • 621
1 vote
0 answers
155 views

$f:Y\to X$ continuous with $f^{-1}(x)$ compact for $x\in X$, does there exist a Borel measurable map $g:X\to Y$?

Let $X,Y$ be Polish, metric spaces. $f:Y\to X$ is a continuous, surjective map and for any $x\in X$, $f^{-1}(x)\subset Y$ is compact. Is it true that there is a injective, Borel measurable map $g:X \...
mathmetricgeometry's user avatar
1 vote
0 answers
289 views

About Whitehead's problem

Hi I am new to proofs of consistency and independence with ZFC of some claims. I have read "The uses of set theory" by Judith Roitman, in that article it is mentioned that the Whitehead ...
Gabriel Medina's user avatar
1 vote
0 answers
102 views

Functions preserving almost disjoint of partitions

A collection $\mathcal{A}\subseteq \omega^\omega$ is almost disjoint iff $\bigcap_{X\in \mathcal{A}}X^{-1}(j)$ is finite for all $j\in\omega$. A function $\Gamma:2^\omega\rightarrow 2^\omega$ is ...
Jiayi Liu's user avatar
  • 909
1 vote
0 answers
280 views

Comparing two $\sigma$-algebras

Let $X$ be a set. We denote $P(X)$ by the family of all subsets of $X$. We also denote $P(X)\otimes_{\sigma}P(X)$ by the $\sigma$-algebra generated by $\{A\times B: A,B \subseteq X\}$. Q. For which ...
ABB's user avatar
  • 4,058
1 vote
0 answers
126 views

Partition refinement of a clopen covering in $\Box (\omega+1)^\omega$

Consider $\omega+1$ with the interval topology, that is $U\subseteq (\omega+1)$ is open if and only if $U\subseteq\omega$ or $(\omega+1)\setminus U$ is finite. We write $(\omega+1)^\omega$ for the ...
Dominic van der Zypen's user avatar
1 vote
0 answers
321 views

Type I subspaces of the Stone Cech compactification of $\omega$

EDIT: I found a construction, see below. I decided not to delete the question in case someone is interested. A space $X$ is of Type I if $X=\cup_{\alpha<\omega_1} X_\alpha$, where each $X_\alpha$ ...
Mathieu Baillif's user avatar
1 vote
0 answers
150 views

Follow up question on the measure of the difference between a partial selector and a selector...

This is a different question from my previous question Difference between a partial selector and a selector, however I am going to repeat the preamble... In Kharazishvili's "Nonmeasurable Sets and ...
George Lazou's user avatar
0 votes
1 answer
176 views

What does mean by "$\omega +1$ is convergent sequence"? [closed]

Let $X=\omega +1$ be convergent sequence. Then what does mean by "$X$ is convergent sequence"?
Nur Alam's user avatar
  • 505
0 votes
1 answer
501 views

$\aleph_1$-calibre

The square of X which is $\aleph_1$-calibre is still $\aleph_1$-calibre?
Paul's user avatar
  • 654
0 votes
1 answer
157 views

Does there exist a star-Lindelöf space which is not star-$L$-Lindelöf?

A space $X$ is said to be star-Lindelöf if for every open cover $\mathcal U$ of $X$ there exists a countable subset $\mathcal V\subseteq\mathcal U$ such that $St(\cup\mathcal V,\mathcal U)=X$. A ...
Nur Alam's user avatar
  • 505
0 votes
1 answer
103 views

(Seeking Definition) What Does it Mean for a Space to have Rim-Type $\alpha$? Or the 'derivative' of a Countable Set?

I've encountered a definition in several papers, but literally none of them define the term. They all instead reference a book by Menger that has never been printed in English. The term is "rim-...
John Samples's user avatar
0 votes
1 answer
170 views

P-filter property?

Let $\mathcal{F}$ be a $P$-filter on $\omega$. Denote by $\Omega=\bigsqcup \omega_i$ where $\omega_i=\omega$. Consider the $P$-filter $\mathcal{S}$ on $\Omega$ whose base is as follows $(\bigsqcup_i ...
Alexander Osipov's user avatar
0 votes
1 answer
278 views

On the compactness of a certain chain topology [closed]

Let $X$ be a non-empty set and $I$ a collection of some nested subsets of $X$ indexed by a linearly ordered set $(\Lambda,\le)$ such that $I$ always contains the void set $\emptyset$ and the whole set ...
K A Khan's user avatar
  • 243
0 votes
1 answer
163 views

Is there a Tychonoff space $X$ such that ....?

$X$ is not a separable submetrizable, i.e.($iw(X)>\omega$) $X$ has not a countable injective weight. There is a Baire isomorphism 1-class between $X$ and a separable metrizable space $Y$.
Alexander Osipov's user avatar
0 votes
0 answers
94 views

Is the space of affine continuous functions a Baire space

Let $\Omega$ be a compact convex set in q linear normed space. Let $A(\Omega)$ be the space of affine continuous real-valued functions. My question is whether the space $A(\Omega)$ is a Baire space? ...
user119197's user avatar
0 votes
0 answers
162 views

A ``1-soft'' improvement of the Parovichenko theorem

This is a ``1-soft'' modification of this problem. We start with the necessary definitions. Definition 1. A compactification $c\mathbb N$ of the discrete space $\mathbb N$ is called 1-soft if for any ...
Taras Banakh's user avatar
  • 41.9k
0 votes
0 answers
643 views

A new generalization of the dimension?

During my research, I came a cross on these notions : Definition 1: A structure $S$, is a pair $(X, \mathcal T)$ with $X$ a set and $\mathcal T$ a set of subsets of $X$, stable by arbitrary ...
Dattier's user avatar
  • 4,074
0 votes
1 answer
194 views

Difference between a partial selector and a selector...

In Kharazishvili's "Nonmeasurable Sets and Functions" there is the following theorem: There exists a subset $X$ of $\mathbb{R}$ which is a Vitali set and a Bernstein set. The proof is as follows: ...
George Lazou's user avatar
-1 votes
1 answer
122 views

Injective choice function for non-separable $T_2$-spaces

For any set $X$ and cardinal $\kappa$ let $[X]^\kappa$ be the collection of all subsets of $X$ of cardinality $\kappa$. I was looking for $T_2$-spaces $(X,\tau)$ with the property that $(P)$ ...
Dominic van der Zypen's user avatar
-3 votes
2 answers
314 views

Dispensing with the notion of infinity for the sake of coverings [closed]

Instead of taking a one to one correspondence meaning each set has the same number of elements. why not use the concept of coverings of topology? The irrational numbers covers the whole numbers but ...
user4904's user avatar
  • 117

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