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10 votes
2 answers
926 views

Is there a volume-preserving diffeomorphism of the disk with prescribed singular values?

This is a cross-post. While working on a variational problem, I have reached to the following question. Let $0<\sigma_1<\sigma_2$ satisfy $\sigma_1\sigma_2=1$, and let $D \subseteq \mathbb{R}^2$...
Asaf Shachar's user avatar
  • 6,741
20 votes
5 answers
2k views

Smoothness of the closest point on a submanifold

Let $(M,g)$ be a smooth Riemannian manifold, and let $S \subseteq M$ be a compact submanifold. Assume that for each $p \in M$, there exist a unique closest point on $S$, i.e a unique point $\tilde s(...
Asaf Shachar's user avatar
  • 6,741
16 votes
1 answer
967 views

Are isospectral manifolds necessarily homeomorphic?

It's known that there are pairs of closed Riemannian manifolds which are isospectral but not isometric. Is it known if there are closed Riemannian manifolds which are isospectral but not homeomorphic?...
Dmitri Gekhtman's user avatar
16 votes
1 answer
1k views

Is there an area-preserving diffeomorphism of the disk which is nowhere conformal?

This question is a cross-post. Let $D \subseteq \mathbb{R}^2$ be the closed unit disk. Does there exist a smooth area-preserving diffeomorphism $f:D \to D$ that does not have conformal points? I ...
Asaf Shachar's user avatar
  • 6,741
14 votes
2 answers
1k views

What are the important geometric-topological consequences of 4-dimensional version of Gauss-Bonnet-Chern theorem?

The Gauss–Bonnet theorem in differential geometry is an important statement about surfaces which connects their geometry to their topology and has very important applications to Riemann surface theory....
C.F.G's user avatar
  • 4,195
7 votes
1 answer
368 views

Does complexified isometry group act transitively on tangent bundle of compact Riemannian manifold?

$\DeclareMathOperator\SL{SL}\DeclareMathOperator\SO{SO}\DeclareMathOperator\SU{SU}\DeclareMathOperator\O{O}\DeclareMathOperator\Iso{Iso}$Let $ g $ be the round metric on the sphere $ S^n $. Since $ S^...
Ian Gershon Teixeira's user avatar
7 votes
1 answer
2k views

existence of totally geodesic hypersurfaces

Assume we are on a smooth, complete Riemannian manifold $(M,g), dim(M) \geq 3$. What are the specific geometric/topological constraints for such a manifold to admit complete, totally geodesic ...
Uche Opara's user avatar
6 votes
4 answers
3k views

Does every smooth manifold of infinite topological type admit a complete Riemannian metric?

To elaborate a bit, I should say that the question of the existence of a complete metric is only of interest in the case of manifolds of infinite topological type; if a manifold is compact, any metric ...
Gordon Craig's user avatar
  • 1,665
5 votes
1 answer
597 views

A vector field whose flow has constant singular values

$\newcommand{\tr}{\operatorname{tr}}$ $\renewcommand{\div}{\operatorname{div}}$ Let $D \subseteq \mathbb{R}^2$ be the closed unit disk. Given a vector field $X$ on $D$, let $\psi_t$ be its flow. Does ...
Asaf Shachar's user avatar
  • 6,741
5 votes
1 answer
1k views

Does every smooth manifold admit a metric with bounded geometry and uniform growth?

Let $M$ be a smooth manifold, $g_M$ a Riemannian metric, and consider for $x\in M$ the volume growth function, $gr_x$ that maps $r>0$ to the volume $vol_{g_M}(B(x,r))$. My interest is to see ...
user44172's user avatar
  • 541
3 votes
0 answers
615 views

Estimates of eigenvalues of elliptic operators on compact manifolds

The classical Weyl law says that if $\Delta$ is the Laplace operator on functions on a compact Riemannian manifold $(M^n,g)$, $n>2$, then its $k$th eigenvalue satisfies the asymptotic formula $$\...
asv's user avatar
  • 21.8k
3 votes
2 answers
380 views

Is this a submanifold?

Let $(M,g)$ be a compact Riemannian manifold with an isometric action $\rho : G \to \mathrm{Iso}(M)$ by a compact Lie group $G$. There is a natural extension of $\rho$ to $TM$ given by: $$\psi : G \...
L.F. Cavenaghi's user avatar
2 votes
1 answer
256 views

Equidistant points on a compact Riemannian manifold

Let $(M,g)$ be a compact Riemannian manifold. To this Riemannian manifold, we associate a natural number $K(M,g)$ as follows: $K(M,g)$ is the maximum of all $n\in \mathbb{N}$ such that we have at ...
Ali Taghavi's user avatar