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Spatially localised solution to the Schrödinger equation with potential is a combination of eigenfunctions

In this Terry Tao's blog post, he claims that if one has a solution to the Schrödinger equation $$i\,\partial_t u +\Delta u=Vu $$ with a "reasonably smooth and localised $V$", $u$ has ...
Earl Jones's user avatar
1 vote
1 answer
263 views

Physical relevancy of two curious PDE's

My research has brought me to the following linear parabolic second order PDE: $$ \frac{\partial^2}{\partial x^2}\Psi(t,x)=c(t,x)\frac{\partial}{\partial t}\Psi(t,x) $$ for $c(t,x)=-\frac{t}{x}$ and $...
John McManus's user avatar
1 vote
0 answers
126 views

Reference for global theory of Schrödinger operators

Question. What is a good reference to learn about the spectral properties of Schrödinger operators in $\mathbf{R}^n$? I am specifically interested in references that discuss examples where the ...
Leo Moos's user avatar
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4 votes
0 answers
117 views

Looking for an electronic copy of Lebeau's paper

I would like to know if anyone has an electronic copy of the paper "Gilles Lebeau - Contrôle De L'Équation De Schrödinger"? This article appeared in Journal de Mathématiques Pures et ...
Math's user avatar
  • 509
2 votes
0 answers
145 views

When does a one-dimensional Schrödinger operator have a threshold resonance?

Consider the operator $$ L = -\partial_x^2 + V(x),$$ for some bounded, decaying potential, i.e. $V(x)\to 0$ as $x\to \pm \infty$. I'm interested in the $L^2(\mathbb R)$ spectrum of $L$. We know that $...
user's user avatar
  • 21
3 votes
0 answers
78 views

Logarithmic Sobolev growth of time-space-periodic Schrödinger solutions

Consider the following Schrödinger equation $$i\partial_t \psi (t,x) + \Delta \psi - V(t,x) \psi = 0 \, ,$$ where $x\in \mathbb{T}^d$ and $V(t,\cdot)$ is real, smooth, and periodic (with a diophantine ...
Amir Sagiv's user avatar
  • 3,574
1 vote
0 answers
45 views

Delta function propogation in the NLS regime

consider the $(1+1)D$ or $(2+1)D$ NLS: $$ i\psi _t (t,{\bf x}) + \Delta \psi + |\psi|^2\psi = 0 \, ,$$ $$ \psi (t,|{\bf x}|\to \infty) =0 \, , \quad \psi(t=0,{\bf x}) = \psi_0 ({\bf x}) \, , $$ with $...
Amir Sagiv's user avatar
  • 3,574
3 votes
1 answer
206 views

Bounded solutions for Schrödinger equation at the edge of the essential spectrum

Let $V:R^d\to R_+$ be with a compact support. The Schrödinger operator $H_a=-\Delta - a V$ acting in $L^2(R^d)$ has then (at most) finitely many negative eigenvalues. Denote the number of negative ...
poupy's user avatar
  • 175
12 votes
3 answers
2k views

Connection between solution for Schrödinger equation and solution for heat equation

It's known, that if you write imaginary unit into a heat equation you'll get time-dependent Schrödinger equation. Recently one guy discovered a connection between solutions for these two equations (...
Glinka's user avatar
  • 381
6 votes
1 answer
357 views

Travelling waves for nonlinear Schrödinger equation

Consider the following nonlinear Schrödinger equation: $$ -\Delta \Phi - i\frac{\partial \Phi}{\partial t} = f(|\Phi|^2)\Phi, $$ where $\Delta$ is the Laplacian on $\mathbb{R}^n$, $f$ gives the ...
user84867's user avatar
2 votes
0 answers
223 views

A construction of the fundamental solution for Schroedinger equations

Does someone know some book or lecture notes useful for the reading of the paper "A construction of the fundamental solution for the Schrödinger equation", Fujiwara, Daisuke, J. Analyse Math. 35 (...
Stan's user avatar
  • 21
7 votes
2 answers
641 views

Decay of solutions to Schrodinger equation with local minimum in potential

Consider the one-dimensional Schrodinger operator on the real line $\mathbb{R}$ given by $$ L = - \partial_x^2 + V $$ where $V$ is a potential with the following properties: $V$ is non-negative, and ...
Willie Wong's user avatar
4 votes
1 answer
355 views

(Ref req) Schrödinger heat kernel is a weak solution of parabolic Schrödinger equation

If we have nonnegative $V \in L^1_{\textrm{loc}}(\mathbb{R}^{n})$, then the operator $H = -\Delta + V$ can be defined on $L^{2}(\mathbb{R}^{n})$ via quadratic form methods. This is done by, for ...
Michael Tinker's user avatar