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The study of the properties of real and complex matrices that are more close to analysis and operator theory. For instance: the properties of positive definite matrices, matrix inequalities, perturbation analysis, matrix functions, inequalities between eigenvectors and singular values, majorization.
3
votes
Logarithms of matrices in the disk-algebra
It seems that $\Delta(z)$ is the exponential of an holomorphic $M(z)$. Using the eigenvalues and eigenvectors of $\Delta$, I find
$$M(z)=\frac\mu{\sqrt{z(z+4)}}\begin{pmatrix} -z & 2 \\ 2z & z \end{pm …
9
votes
Triangularizing a matrix with function entries
You cannot triangularize smoothly the parametrized matrix
$$A(z)=\begin{pmatrix} 0 & 1 \\\\ z & 0 \end{pmatrix}$$
about $z=0$. The eigenvalues, square roots of $z$ aren't smooth and, above all, cannot …
2
votes
Matrix-convexity of inverse of the cofactor matrix
Well, this is not an answer. But I cannot resist to mention the following equivalent property. Let $A\mapsto \hat A$ denote the cofactor map, and $B\mapsto \check B$ its inverse. For positive definite …
2
votes
How much redundancy resides in an $n \times n$ orthogonal matrix?
The fact that $\frac{n(n-1)}2$ well chosen coefficients determine the other ones is supported by the Schur parametrization : let $U$ be unitary (it works as well for real orthogonal matrices) and Hess …
8
votes
Accepted
A matrix inequality involving the Hilbert-Schmidt norm
Suppose $Q$ is such a form. Write that the mean value of $Q$ over the unit sphere is non-negative. You obtain
$$-\frac12\sum_ia_{ii}^2+\frac12\sum_{i < j}a_{ii}a_{jj}-9\sum_{i < j}a_{ij}^2\ge0.$$
This …
3
votes
Accepted
A sum of eigenvalues
The answer is yes, because your function (let me call it $f$) is the maximum of convex functions. As such, it is convex. The formula :
$$f(X)=\max\left(0,\max_{1\le r\le n}\sum_{j=1}^r\lambda_j(X)\rig …
2
votes
Show that the eigenvalues of a non-symmetric matrix built from positive matrices have positi...
Since there is not much progress on this question, let me give a partial result and a direct consequence.
Denote $S=C-B^TA^{-1}B$ the Schur complement of $A$ in $N$, which is positive definite. Then $ …
0
votes
Cofactor an geometrical mean in $\mathit{SPD}_3$: a Gårding-like inequality
Because of the lack of answers, I continued my investigations, and eventually got it !
Notation : because some expressions are too long for the command widehat, I'll sometimes denote ${\rm Cof}A$ for …
7
votes
Accepted
When are two binary matrices simultaneously equivalent to their transpose?
Clearly, a necessary condition is that for every word $w$ in two letters, one has
$${\rm Tr}\,w(A^t,B^t)={\rm Tr}\,w(A,B).$$
Equivalently,
$${\rm Tr}\,\hat w(A,B)={\rm Tr}\,w(A,B),$$
where $\hat w$ is …
4
votes
Fast Upper Triangular Matrix Exponentiation
When I teach the exponential of matrices, I tell the students that the converging series is not a practical tool for calculation. It is way better to solve the differential equation. This turns out to …
3
votes
system of homogeneous matrix equations
A partial answer: Let $\Sigma$ denote the manifold $x^n+y^n=0$. Away from $\Sigma$, the equation and the fact that the roots of the polynomial $X^n-x^n-y^n$ are simple, tell you that $xA+yB$ is diagon …
5
votes
A question of invertibility of matrices
What about
$$A=\begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix},\qquad B=\begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix}\quad ?$$
7
votes
Accepted
Argument principle for matrices
You can write instead
$$\frac1{2i\pi}\int_Cg(z){\rm tr}(f'(z)f(z)^{-1})dz.$$
Now use the formula
$${\rm tr}(f'(z)f(z)^{-1})=\frac1{\det f(z)}\,(\det f(z))'.$$
And conclude with the formula of residues …
4
votes
Accepted
Relation between Frobenius norm, infinity norm and sum of maxima
The answer is Yes. This is not really a problem about matrices. The best way to analyse it is to rewrite it in terms of the row vectors $u_i\in{\mathbb C}^n$. Let me denote $\|\cdot\|_p$ the $\ell^p$- …
17
votes
Accepted
Counting eigenvalues without diagonalizing a matrix
Here is an efficient method.
First of all, I must quote that diagonalizing $M$ is not a method, because there is no explicit way to carry this out. It amounts to calculating the roots of a polynomial …