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Questions about the branch of algebra that deals with groups.
2
votes
$C'(\lambda)$ small cancellation for $\lambda < \frac{1}{6}$
Greendlinger's Lemma is about the geometry of disk diagrams. If we instead consider annular diagrams, the assumption that $\lambda<1/8$ gives an improved structural result.
Annular diagrams encode the …
5
votes
Accepted
Units of the group algebra of a free group
A group $G$ is locally indicable if every nontrivial finitely generated subgroup surjects onto the infinite cyclic group $\mathbb{Z}$.
The following theorem was proven by Higman in 1940 [1]:
Theorem. …
4
votes
Groups acting non-properly cocompactly on hyperbolic spaces
Bass-Serre theory is the classical theory of groups acting on trees. Trees are hyperbolic, so this theory fits nicely into the context of this question.
Standard examples of groups acting on trees co- …
4
votes
Words which are not inverted by any endomorphism
This partial answer just covers the case of $\psi$ non-surjective, i.e. not an automorphism.
Just to set some notation: Define $A=\langle w_1, w_2\rangle=\operatorname{im}(\phi)\leq F_2$. We will show …
7
votes
0
answers
100
views
A group, all of whose non-trivial mapping tori are finitely presentable?
By a mapping tori of $G$, I mean a semidirect product $G\rtimes\mathbb{Z}$, and by a trivial mapping tori I mean one isomorphic to $G\times\mathbb{Z}$.
If $G$ is finitely generated but not finitely pr …
15
votes
Classes of groups with polynomial time isomorphism problem
A two-generator, one-relator group with torsion is a group with presentation of the form $\langle a, b\mid R^n\rangle$, $R\in F(a, b)$ and $n>1$. Their isomorphism problem is decidable in quadratic ti …
3
votes
2
answers
176
views
Subsets of free groups contained in $2$-generated subgroups
$\DeclareMathOperator\rank{rank}$Let $F$ be a non-cyclic free group.
For which finitely generated subgroups $H< F$ such that $H$ is not of finite index in a free factor of $F$ does there exist a two- …
12
votes
Accepted
Torsion-free virtually free-by-cyclic groups
The group $$G=\langle a, b, x, y\mid [a, b]^2=[x, y]^2\rangle$$
is a torsion-free group which is not free by cyclic. However, $G$ is free-by-$D_{\infty}$ and so virtually free-by-cyclic (containing an …
3
votes
Results from abstract algebra which look wrong (but are true)
That there exist finitely presentable non-Hopfian groups. [I still remember my shock when I was first learned this result!]
A group G is Hopfian if every surjective homomorphism $\phi:G\to G$ is in fa …
6
votes
Accepted
Nontriviality of one-relator products
Here is a partial answer: The Kervaire-Laudenbach Conjecture states that, for any group $A$, $(A\ast\mathbb{Z})/\operatorname{ncl}(w)$ is non-trivial. This was proven by Klyachko for torsion free grou …
4
votes
1
answer
427
views
When is a generalised Baumslag-Solitar group linear?
$\DeclareMathOperator\BS{BS}$The linearity of the Baumslag-Solitar groups $\BS(m, n)=\langle a, t\mid t^{-1}a^mt=a^n\rangle$ is completely understood, and it may be phrased as: $\BS(m, n)$ is linear i …
5
votes
1
answer
261
views
Finite generation of intersections of free subgroups
Let $G$ be a finitely generated group, and let $F_1, F_2$ be two subgroups of $G$ which are free of finite rank at least 2. I am wondering what conditions can be placed on $G$ so that $F_1\cap F_2$ is …
17
votes
1
answer
751
views
Are groups with every proper, non-trivial subgroup infinite cyclic simple?
In the 1970s Ol'shanskii constructed a non-cyclic finitely generated group $G$ with the following properties:
Every proper, non-trivial subgroup of $G$ is infinite cyclic.
If $X^m=Y^n$ for $X, Y\in G …
3
votes
Centralizers in amalgamated free products
I wanted to answer this question to give a solid journal citation (as requested in the comments to HJRW's answer), but also I feel there is some historical interest here.
It seems that the result you …
8
votes
0
answers
273
views
Subgroups of torsion-free hyperbolic groups versus subgroups of hyperbolic groups
Let $\mathcal{S}$ be the class of finitely presented torsion-free groups which occur as the subgroup of some hyperbolic group (so for every $G\in \mathcal{S}$ there exists a hyperbolic group $H$ such …