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Lie Groups are Groups that are additionally smooth manifolds such that the multiplication and the inverse maps are smooth.
0
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0
answers
84
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Can we extend a function from the diagonal matrices to an orthogonally-invariant function on...
This is a cross-post.
Let $g:(0,\infty)^n \to [0,\infty)$ be a symmetric function -i.e. $g(\sigma_1,\dots,\sigma_n)$ does not depend on the order of the $\sigma_i$, with $g(1,\dots,1)=0$.
We identif …
3
votes
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answers
81
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Is there a transitive Lie group action on the space of matrices with rank bigger than $k$?
$\newcommand{\GL}{\operatorname{GL}}$
Let $H_{>k}$ be the space of real $d \times d$ matrices of rank bigger than $k$, for some fixed $k$. $H_{>k}$ is an open connected submanifold of $ \mathbb{R}^{d …
9
votes
1
answer
858
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Proofs that the conformal group in dimension $\ge 3$ is a Lie group
Let $M$ be a smooth manifold of dimension $\ge 3$, equipped with a conformal structure (or a Riemannian metric). Then, the group of conformal diffeomorphisms is a finite dimensional Lie group.
A proo …
3
votes
References for metrics in matrix groups
This paper might give you some ideas on how to calculate the geodesics. It is about left invariant metrics on $GL_n(\mathbb{R})$. The geodesics are calculated using their characterization as critical …
0
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Accepted
Characterizing left invariant and right-$O_n$ invariant distances on $GL_n$
$\newcommand{\al}{\alpha}$
The answer is no, there are many more such metric which are not induced by a Riemannian metric.
(This answer is based on the comments above, made by user89334).
Examples:
…
2
votes
1
answer
109
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Characterizing left invariant and right-$O_n$ invariant distances on $GL_n$
Consider the group $GL_n(\mathbb{R})$ with its standard topology.
It is not hard to show that there exists Riemannian metrics on it which are left-$GL_n$ and right-$O_n$ invariant. (In fact it's pos …
11
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1
answer
715
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Strong equivalence between intrinsic and extrinsic metrics on $GL_n^+$?
$\newcommand{\til}{\tilde}$
Lately, I have become interested in comparing intrinsic and extrinsic metrics on Riemannian manifolds.
Consider $GL_n^+$ (invertible matrices , $\det >0$) as an open Riem …
6
votes
1
answer
792
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Totally geodesic subgroups in Lie groups
Let $G$ be a Lie group with a left invariant metric $g$.
Let $H$ be a (closed) Lie subgroup of $G$, and assume $g$ is right-$H$-invariant. (That is $d(R_h)_e:T_eG \to T_hG$ is an isometry for every $ …
6
votes
Which norms have rich isometry groups?
Sorry to join so late to the party, but I couldn't help noticing there is a missing class of rich matrix norms (which are not operator norms).
These are the p-Schatten norms on $R^{n^2}$, which see …
2
votes
Action of the group of isometries on a manifold
Your original approach for extending the geodesic is in fact possible, after a slight modification. (Credint: I heard this Idea from Eran Assaf).
(You do not pushforward the original geodesic, but i …