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Enumerative combinatorics, graph theory, order theory, posets, matroids, designs and other discrete structures. It also includes algebraic, analytic and probabilistic combinatorics.

1 vote

A non-associative three-valued logic

It sounds like you are describing a situation where $a$ is more true than $b$, $b$ is more true than $c$, but nevertheless $c$ is more true than $a$. I am not sure about the best starting point in loo …
The Amplitwist's user avatar
11 votes
Accepted

Generalising the union-closed sets conjecture from lattice to a larger class of posets

Here is a counterexample of size 23. Let $m=6$ and let $$P=\{0,a_1,\dots,a_m,1\}\cup\{b_{ij}: 1\le i<j\le m\}$$ where $0<a_i<b_{jk}<1$ whenever $i$ is distinct from $j$ and $k$. The cardinality of $P$ …
Bjørn Kjos-Hanssen's user avatar
2 votes
Accepted

Non-summable subsets of $[\omega]^{<\omega}$

Theorem: There is no such $E$. Claim: for each $a\in E$ there exists $b\in E$ with $|b\setminus a|\ge 2$. Proof of Claim: Let $a$ be a counterexample. Then all $b\ne a$ contain exactly one element eac …
Bjørn Kjos-Hanssen's user avatar
2 votes

Characterizing and counting boolean functions with all influences 1/2

We are looking at functions where each variable has a 50% chance of mattering. Let $c_n$ be the number of such functions. I'll just prove that $4^n\le c_n$ (of course $c_n\le 2^{2^n}$) for $n\ge 3$. T …
Bjørn Kjos-Hanssen's user avatar
1 vote

Counting sparse union-closed families

Of course all subfamilies of $2^{[n/2-1]}$ are sparse. For any $k$, the number of union-closed families $\mathcal F\subseteq 2^{[k]}$ is $u(k)=2^{\binom{k}{\lfloor k/2\rfloor}(1+o(1))}$ (link), where …
Bjørn Kjos-Hanssen's user avatar
0 votes

Sequences with 3 letters

It is perhaps equally natural to consider sequences wrapping around cyclically, like a de Bruijn sequence. In that case there is a simple reason why it won't work for $n=3$. Clearly 000111222, or cycl …
Bjørn Kjos-Hanssen's user avatar
2 votes
Accepted

"Arithmetically diverse" infinite binary string

Let $s$ consist of $2^{2^k}$ zeros, followed by the same number of ones, for increasing $k$: $$0^21^2\, 0^{16}1^{16}\, 0^{256}1^{256}\,0^{65536}1^{65536}\dots$$ Observe that all but finitely many bloc …
Bjørn Kjos-Hanssen's user avatar
1 vote

Can someone please help me understand the concept of twins?

You can use this: if $u\ne x$, $$dist(u,x)=1+\min\{dist(w,x):uw\in E\}.$$
Bjørn Kjos-Hanssen's user avatar
1 vote

Probability of a given string being a substring of another string

Let $A_t$ be the event that $S_1$ is a substring of $S_2$, $S_2=pS_1q$, where the length of $p$ is $t$. Then the probability of $\cup_t A_t$ can be found by inclusion-exclusion as $$\sum P(A_t)-\sum P …
Bjørn Kjos-Hanssen's user avatar
9 votes
Accepted

Is Van der Waerden's function elementary

Yes, this should follow from the elementary bound. The point is that having a Kalmar elementary time bound is "closed under" searches through exponentially large collections. Suppose $N=W(r,k)$ is lea …
Bjørn Kjos-Hanssen's user avatar
9 votes
2 answers
382 views

A cubefree-preserving morphism from 5 to 2?

A word is cubefree if it cannot be written as $xyyyz$ where $y$ has positive length. Let $h$ be the morphism from $\{0,1,2,3,4\}^*$ to $\{0,1\}^*$ given for words of length 1 as follows ($a\to h(a)$) …
2 votes

NE-Lattice paths from $(0,0)$ to $(n,n)$ with $k$ peaks

Imagine that you lay out the N (0) and E (1) moves as follows ($n=4$ shown): $$0000$$ $$1111$$ As you go along the path, color $\color{red}{red}$ the ones you have used, so that after reading either 0 …
Bjørn Kjos-Hanssen's user avatar
2 votes

Is $ \{ \frac{1}{n} + \frac{1}{m} : n,m \in \mathbb{N} \}$ dense in some interval of $\mathb...

We may assume $n\le m$ throughout. Let $y>x>0$. There are only finitely many $n$ with $$ 1/n\ge x/2. $$ For each such $n$, the set of $1/n+1/m$ as $m$ varies is not dense in any subinterval of $(x,y …
Bjørn Kjos-Hanssen's user avatar
5 votes
Accepted

An infinite version of the Dilworth theorem

This is studied in Reverse Mathematics as the Chain Antichain Principle (CAC) and it is observed that it follows from Ramsey's theorem.
Bjørn Kjos-Hanssen's user avatar
2 votes

Covering subset with large probability

It is true. Let $k=\binom{N}{N/2-c\sqrt N}$ and let $K$ be a randomly* selected subset of $k$ of size $k\lambda$. Then conditionally on $|X|>N/2-c\sqrt N$, the difference $|X|-(N/2-c\sqrt N)$ is unbou …
Bjørn Kjos-Hanssen's user avatar

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