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Spectrum, resolvent, numerical range, functional calculus, operator semigroups. Special classes of operators: compact, Fredholm, dissipative, differential, integral, pseudodifferential, etc.
0
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A possible generalization of Pitt's theorem
Inspired by Pitt's theorem and this post we ask the following question:
First we remind the Pitt's theorem and also introduce a particular Banach space as averaging of $\ell^p$ spaces for $1\leq p …
1
vote
1
answer
125
views
Trace class operators in the unit ball of a finite dimensional subvector space of $B(H)$
Let $F\subset B(H)$ be a finite dimensional subvector space of the space of all bounded operators on a Hilbert space.
Question: Is there an upper bound for $$\{|tr(T)| \text{where} \quad T\in …
2
votes
1
answer
181
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A Possible characterization of F.D or AF commutative $C^{*}$ algebras
By F.D or AF $C^{*}$ algebra,we mean finite dimensional or approximately finite dimensional $C^{*}$ algebra.
Let $A$ be a unital commutative $C^{*}$ algebra with the property that for every …
7
votes
Accepted
A matrix norm inequality II
No the norm of the left side can be very large.
For example $\left\| X^{-1}AXB \right\| $ is an unbounded function in $(x,y)$ where $A,X,B$ are the following matrices:
Put $A=B= \begi …
2
votes
0
answers
684
views
Universal $C^*$ algebra generated by two self adjoint elements with $x^2+y^2=1+{(xy-yx)}^2$
Is there universal $C^*$ algebra generated by self adjoint elements $x,y$ subject to relation $x^2+y^2=1+{(xy-yx)}^2$?
What is a precise description of such algebra?
4
votes
0
answers
100
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A bounded operator associated with a principal bundle
Assume that $(X, B, G)$ is a $G$- principal bundle where $G$ is a compact topological or Lie group.
The normalized Haar measure of (each fiber of ) $X$ is denoted by $\mu$.
The space of continuos comp …
3
votes
1
answer
173
views
Obstructions for $C^\star$ algebras to contain a $Z^\star$ algebra
As the comment of Andreas Thom indicated here, a separable $C^\star$ algebra $A$ can not contain a $Z^\star$ algebra.(A $Z^\star$ algebra is a $C^\star$ algebra which all elements are zero divis …
3
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1
answer
161
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Simple $Z^{*}$ algebra
What is an example of a simple $C^{*}$ algebra which all elements are (two sided or equivalently one sided) zero divisor?
6
votes
3
answers
981
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Invertible operator with countable spectrum
Let $H$ be a separable Hilbert space and $A$ is an invertible bounded operator on $H$. Can we approximate $A$ with an invertible operator $B$ such that $sp(B)$ is a countable set?
Motivation: …
4
votes
2
answers
442
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$C^{*}$ algebras which do not admit nontrivial idempotent morphism
In this question which I flag it as a community wiki, I search for a big list of $C^{*}$ algebras(and a big list of criterions) which do not admit a non trivial idempotent $C^{*}-$morphism.
I kno …
6
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For what kind of $C^*$ algebra $A$ every normal element $y\in A$ has a normal lift for every...
Is there a terminology for the following property of $C^*$ algebra $A$:
For every $C^*$ algebra $B$ and surjective $C^*$ morphism $\phi: B\to A$, every normal element $y\in A$ admits a normal ele …
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vote
2
answers
435
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Fredholm $C^*$-algebras
Let $H$ be a Hilbert space. A vector subspace $W\subset B(H)$ is called a Fredholm subspace if there is an upper bound for the absolute value of Fredholm index of all Fredholm operators $T$ in $W$.
…
1
vote
2
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397
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A question on unbounded operators
Assume that $H$ is a separable Hilbert space.
Is there a polynomial $p(z)\in \mathbb{C}[x]$ with $deg(p)>1$ with the following property?:
Every densely defined operator $A:D(A)\to D(A),\;D(A)\subs …
4
votes
2
answers
394
views
The closure of all periodic homeomorphisms of circle
Let $X$ be the space of all continuous maps from $S^{1}$ to $S^{1}$. $X$ is equipped with $C^{0}$ topology. Let $Y\subset X$ be the union of all finite order homeomorphisms i.e: all homeomorphi …
4
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1
answer
300
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Fredholm subvector spaces of $B(\mathcal{H})$
Let $\mathcal{H}$ be a separable Hilbert space with orthonormal base $\{e_i\}\;\;i\in \mathbb{N}$.
Definition: We say a subvector space $W\subset B(\mathcal{H})$ is a Fredholm subspace if the …