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Complex, contact, Riemannian, pseudo-Riemannian and Finsler geometry, relativity, gauge theory, global analysis.
7
votes
Complex manifolds whose tangent and cotangent bundles are isomorphic as complex vector bundles
There are many such examples, for instance, all complex nilmanifolds (and most complex solvmanifolds) have tangent bundle which is topologically trivial. The Hopf manifolds also have topologically tri …
4
votes
Accepted
Cohomology of invariant differential forms
There is no such thing: any $\phi$-invariant exact
1-form is a differential of $\phi$-invariant function.
Indeed, let $\alpha$ be an exact $\phi$-invariant
form, $\alpha=df$, where $f$ is not $\phi$-i …
3
votes
Accepted
Bott-Chern cohomology for singular complex spaces
closed (1,1)-forms and currents on X
are not necessary locally $dd^c$-exact in general
What makes it different when X is singular?
The obstruction to local $dd^c$-lemma
is $R^1\pi_*(O_{X'})$, where
…
8
votes
Coincide between Chern-connection and Levi-Civita connection
It is easier to prove this result for 1-forms, instead of vector fields. On (1,0)-forms, $\nabla^{0,1}=\bar\partial$ because the Levi-Civita connection is torsion-free, hence $\bigwedge(\nabla(\eta))= …
2
votes
0
answers
82
views
3-Sasakian manifolds and contact Fano Kähler-Einstein manifolds
Let $(M,g)$ be a Riemannian manifold. The Riemannian cone
of $M$ is $C(M) = M \times {\Bbb R}^{>0}$ with the metric $t^2 g + dt\otimes dt$.
A manifold is called Sasakian if its cone is Kähler, with t …
1
vote
Curvature forms of holomorphic line bundles
Sure, any closed 2-form $\eta$ with integer cohomology
can serve as the curvature of a connection
on a line bundle. This can be seen if you take a line bundle with
the same Chern class and connection …
6
votes
1
answer
441
views
Holonomy bounded in terms of area and the curvature
I suppose the following result follows
from Ambrose-Singer theorem, but I cannot
find a reference, and the arguments I found
in the literature are usually weaker. The idea
is that holonomy over a null …
2
votes
Is a linear vector field a geodesible vector field?
This observation seems to be very easy,
but it takes care of many examples.
Suppose that $A$ corresponds to a contraction
(that is, all eigenvalues are $< 1$ in absolute value).
Decompose ${\Bbb R}^n …
8
votes
Hodge dual of de Rham cohomology and singular cohomology
The Hodge * operator action on cohomology is generally speaking
metric-dependent, hence * is not well-defined without fixing the metric.
There are some caveats. On complex curves, for example, the
Hod …
1
vote
Holomorphic retraction $\implies$ holomorphic tubular neighbourhood?
Question. Is there a holomorphic
tubular neighbourhood of S in M?
I have a counterexample. Let $\phi:\; Z^2 \to Aut(C^n)$
be a group homomorphism, with $Aut(B)$ denote the group
of holomorphic autom …
3
votes
Holomorphic version of Darboux's theorem
To put it differently, is it true that X locally looks like a cotangent bundle?
This is false. Indeed, take an elliptic curve $C$ inside an elliptic
K3 surface. If it had a neighbourhood $U$ which is …
1
vote
HKT manifolds with non trivial canonical bundle
For $SU(3)$ and Hopf it is the anticanonical
bundle which has many sections. In other
examples of Joyce, it is also the anticanonical
bundle or its powers. For nilmanifolds, the
canonical bundle is ho …
8
votes
1
answer
332
views
reference to a theorem about a product of harmonic and parallel forms
Let $\alpha$ be an exterior product of a harmonic and a parallel form on a Riemannian manifold. Then $\alpha$ is known to be harmonic. I have heard that this is an old result due to R. Bott, but I cou …
9
votes
2
answers
724
views
Bieberbach theorem for compact, flat Riemannian orbifolds
In his thesis, Bieberbach solved Hilbert 18 problem and
proved that any compact, flat Riemannian manifold is a
quotient of a torus. I need a reference to an orbifold version
of this result: any comp …
12
votes
1
answer
403
views
Compact quaternionic Kahler manifolds of negative curvature: examples
There is a well known problem of LeBrun-Salamon:
are there any non-symmetric compact quaternionic-Kahler
manifolds of positive scalar (and Ricci) curvature?
It is hard and still unsolved:
Quaternionic …