Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 22758

Banach spaces, function spaces, real functions, integral transforms, theory of distributions, measure theory.

9 votes
2 answers
307 views

Local-to-global inequalities for measures: Brunn-Minkowski, Ahlswede-Daykin, what else?

This question is motivated by an obvious formal analogy between two well-known inequalities: Log-concavity and Brunn-Minkowski inequality Let $\mu(dx) := m(x) dx$ be an absolutely continuous …
Alexander Shamov's user avatar
8 votes
2 answers
582 views

Does every operator from a Hilbert space to $L^0$ factor through a canonical one?

Let $A:H\to L^0(S, \mu)$ be a continuous operator from a Hilbert space to the space of (equivalence classes of) measurable functions on a probability measure space $S$ with convergence in measure. Let …
Alexander Shamov's user avatar
7 votes
Accepted

Is the ideal of functions vanishing at a set complementable in $C(X)$?

Not in general. It's well-known in Banach space theory that the ideal $c_0$ in $\ell^\infty$ is not complemented (see e.g. Albiac & Kalton). By the Gelfand representation, $\ell^\infty \simeq C(\bet …
Alexander Shamov's user avatar
7 votes

When $L^\infty$ is 1-injective

For a compact Hausdorff space $K$ the algebra $C(K)$ is $1$-injective iff $K$ is extremally disconnected iff its Boolean algebra of idempotents is complete. So to construct a counterexample we need an …
Alexander Shamov's user avatar
7 votes
1 answer
242 views

Is there a nice "minimum" of two symmetric operators?

Let $A$ and $B$ be two bounded symmetric positive operators in Hilbert space, such that $A-B$ is trace class. If needed, $A$ and $B$ may be assumed reasonably "small", let's say, Hilbert-Schmidt. Doe …
Alexander Shamov's user avatar
7 votes
1 answer
652 views

Compactness of Sobolev embedding for domains of finite measure

Let $\Omega \subset \mathbb{R}^d$ be a domain of finite Lebesgue measure, not assumed to be smooth or bounded. Is it true that the embedding of, say, $W^{1,p}_0(\Omega)$ (Sobolev functions with zero b …
Alexander Shamov's user avatar
7 votes
1 answer
439 views

Is an infinite-dimensional "Lebesgue measure" uniquely determined by a set of positive finit...

Let $\mu$ be a probability measure on a subset $C \subset \mathbb{R}^\infty$ of the space of sequences, and assume, for simplicity, that $C$ is closed and convex. We say that $\mu$ admits shifts if f …
Alexander Shamov's user avatar
6 votes
0 answers
242 views

Operator arithmetic-harmonic mean inequality with operator-valued weights

Let $\Lambda_1,\dots,\Lambda_n$ be strictly positive definite operators in the Euclidean space $\mathbb{R}^d$. By an operator arithmetic-harmonic mean inequality with weights $\Lambda_i$ I mean the fo …
Alexander Shamov's user avatar
6 votes
1 answer
290 views

Does the topological Varopoulos algebra consist of functions that are continuous and Varopou...

Let $X_1,\dots,X_n$ be compact Hausdorff spaces. Let's define the Varopoulos algebra as the projective tensor product: $$V(X_1,\dots,X_n) := C(X_1) \hat{\otimes} \dots \hat{\otimes} C(X_n),$$ i.e. the …
Alexander Shamov's user avatar
5 votes
0 answers
119 views

L^1 maximal inequalities for the Ornstein-Uhlenbeck semigroup in infinite dimension

For an infinite-dimensional Gaussian random vector $X$ consider the Ornstein-Uhlenbeck maximal operator: $M f(X) := \sup_{\rho \in [0,1]} \mathsf{E} [f(\rho X + (1-\rho^2)^{1/2} X^\prime) \mid X]$ ( …
Alexander Shamov's user avatar
5 votes
0 answers
161 views

$L^p$ estimates for Ornstein-Uhlenbeck: what is known beyond hypercontractivity?

Consider an infinite-dimensional Gaussian random vector $X$, and a positive random variable $f(X) \in L^p, p > 1$. Let $f(X) \sim \sum_n f_n(X)$ be its (formal) chaos expansion. Let $(U_\rho, \rho \in …
Alexander Shamov's user avatar
5 votes
Accepted

If Gaussian measures on a Hilbert space converge weakly to 0, how do their covariance operat...

Denote the Gaussian random vectors by $X(n)$. Clearly, $\mathrm{tr} \, S(n) = \mathsf{E} \, \Vert X(n) \Vert^2$, so $\mathrm{tr} \, S(n) \to 0$ is certainly sufficient for weak convergence to $0$. An …
Alexander Shamov's user avatar
4 votes
Accepted

Convergence a.e and $L^1$ boundedness implies convergence in which sense?

There is convergence in some non-locally convex spaces, e.g. $L^p, 0 < p < 1$. More generally, for any concave function $\Psi : \mathbb{R}_+ \to \mathbb{R}_+$, such that $\Psi(0) = 0$ and $\Psi(x) / …
Alexander Shamov's user avatar
4 votes
1 answer
155 views

For Hilbert spaces, does weak analyticity with respect to a dense subspace of functionals im...

Let $i : X \hookrightarrow Y$ be a dense embedding of complex Hilbert spaces. Let $f : \mathbb{D} \to X$ be a function, such that $i \circ f$ is holomorphic ($\mathbb{D}$ is the open unit disk). I …
Alexander Shamov's user avatar
4 votes

Do semi-continuous functions generate bounded Borel measurable functions as a $C^*$-algebra?

Any upper or lower semicontinuous function is continuous almost everywhere in the sense of Baire category (since it is a pointwise limit of a sequence of continuous functions, at least when $\Omega$ i …
Alexander Shamov's user avatar

15 30 50 per page