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Continuum theory, point-set topology, spaces with algebraic structure, foundations, dimension theory, local and global properties.
1
vote
Can we describe open cover compactness of a space in how the space relates to other spaces?
The Sierpinski topology allows us to reformulate open sets an thus any topological property in terms of continuous functions.
The Sierpinski topology is the topology on $\{0,1\}$ where the sets $\empt …
20
votes
Why are extremally disconnected spaces so hard to give examples of?
We can always get non-principal ultrafilters on sets from non-discrete extremally disconnected spaces.
Let $X$ be a topological space. Let $\text{Clo}(X)$ denote the Boolean algebra of clopen subsets …
2
votes
Description of atomless complete Boolean algebras with a countable $\pi$-base
Yes. The complete atomless Boolean algebra with a countable $\pi$-base is unique up to isomorphism. For a proof, we observe that if $B$ has a countable $\pi$-base $A$, then the Boolean algebra $C$ gen …
2
votes
Compact-open Topology for Partial Maps?
There is a way to promote function space topologies so that convergence of nets behaves the way that one would expect it to behave. There are probably other ways of getting a topology for spaces of pa …
5
votes
Does there exist a topological space $X$ such that $X^2$ and $[0,1]$ are homeomorphic?
I can think of a few proofs of the fact that there is no space $X$ with $[0,1]$ homeomorphic to $X^2$. There are probably more proofs in addition to the proofs in the other answers.
Proof 1-1: Suppose …
2
votes
Topological characterisations of properties of posets
Recall that an Alexandrov space is a topological space where the intersection of arbitrary collection of open sets is open. Alexandrov duality states that the category of Alexandrov spaces is equivale …
2
votes
Accepted
Homeomorphisms of the projective cover of the Cantor set
I claim that every autohomeomorphism of $M$ is conjugate to an extension of an autohomeomorphism of the Cantor space.
Let $B$ be the Stone space of the Cantor space. Let $\overline{B}$ denote its Bool …
2
votes
Accepted
Polish space isometric to its hyperspace
It is much easier to deal with zero dimensional spaces and ultrametrics than connected metrics. $\omega^\omega$ with the standard ultrametric is isometrically isomorphic to its own hyperspace.
In part …
2
votes
Simple proof that downward intersections of simply connected compact sets are simply connected
Several commenters observed that the topologist's sine curve is a non-path connected subspace of $\mathbb{R}^2$ that can be written as an intersection of countably many simply connected spaces. One ca …
4
votes
Accepted
A question about regular closed sets
The answer to both of these questions is Yes. And this result can generalize to point-free topology and I consider this result to be more natural in the context of point-free topology.
The following o …
5
votes
Homeomorphic extension of a discrete function
Yes. We can always extend a permutation $f:\{0,1\}^n\rightarrow\{0,1\}^n$ to a homeomorphism $F:[0,1]^n\rightarrow[0,1]^n$ whenever $n\geq 3$ or $n=1$.
Proposition: Suppose that $X$ is a connected reg …
4
votes
Accepted
When can we find a net, defined on a totally ordered index set, converging to a non-isolated...
Yes. For every non-isolated $p\in X$, there is a well-ordered net in $X\setminus\{p\}$ converging to $p$ as long as $X$ is compact and Hausdorff. This result was observed in the 1992 paper Convergent …
8
votes
Do germs of open sets around a point form a frame?
This is generally not a frame nor is it a complete lattice. For example, consider $\omega+1$ which is the one-point compactification of the countable discrete space $\omega$. Then the set of all germs …
7
votes
Fixed point theorem for the uncountable power of an interval
By collapsing cardinals with forcing, one can derive Brouwer's fixed point theorem for $[0,1]^\kappa$ where $\kappa$ is uncountable from Brouwer's fixed point theorem for $[0,1]^{\aleph_0}$.
Suppose t …
4
votes
Accepted
A stronger version of paracompactness
Lemma: Let $(U_{\alpha})_{\alpha\in A}$ be a finitely intersecting open cover of a space $X$. Then there is some partition $P$ of $A$ where $(\bigcup_{\alpha\in R}U_\alpha)_{R\in P}$ is a partition of …