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Ordinary or partial differential equations. Delay differential equations, neutral equations, integro-differential equations. Well-posedness, asymptotic behavior, and related questions.
7
votes
2
answers
1k
views
First order Elliptic operator
Assume that there exists a first order elliptic operator $D$ acting on functions from $\mathbb{R}^n$ to some vector space $V$. What can we conclude about $V$?
For example, is the dimension of $V$ alw …
5
votes
1
answer
1k
views
Exponential mapping versus flow
In Hamilton's article on the Nash-Moser Theorem, he gives the map that maps a vector field $X$ to its flow $e^{tX}$ in $\mathrm{Diff}(M)$ as an example where the implicit function theorem in Frechet s …
3
votes
1
answer
379
views
First order PDE, singular at a point
I am pretty sure this should be text book material, but I couldn't find this anywhere; maybe I just don't know where to look.
Problem: Suppose we have a smooth vector field $X = a_i x^i \partial_i + …
2
votes
1
answer
652
views
Geodesics and harmonic map heat flow
I believe the answer to my question is well-known, but as I do not know too much about harmonic map flows, here it goes:
Let $M$ be a complete Riemannian manifold. For a curves $c: [0,1] \longrightar …
1
vote
Fredholm index vs. Limit cycle theory
The linearization of the vector field $X$ at the singular point zero is
$$DX|_0 = \begin{pmatrix} 1 & 1\\ -1 & 0\end{pmatrix},$$
the eigenvalues of which are
$$ \lambda_{1, 2} = \frac{1}{2} \pm \frac{ …
1
vote
Existence, uniqueness, and smoothness of a solution to a first order PDE on Riemannian M
Let $\Phi_t(x)$ be the flow of your vector field $\nabla d_{\mathcal{A}}$, starting at $x \in \mathcal{A}$. It will exist until the time $t_0(x)$, when it hits the set where $\nabla d_{\mathcal{A}}$ i …
1
vote
Linearization of vector fields
The result of Poincaré is in fact not about the real case but about the complex case. Suppose a vector field of the form
$$ X = \sum_i\lambda_i x^i \partial_i + \text{higher order terms}$$
Then there …
0
votes
Accepted
Solving the geodesic equation for a singularity crossing curve
This is probably a longer comment, but let me make this into an answer.
Suppose $\gamma$ is a curve in your manifold and we are asking if it satisfies the geodesic equation in some sense. Then either …
0
votes
The spectrum of Schrodinger Equation
Since $u$ tends to $0$ as $x$ goes to infinity and it is apparently supposed to be $C^1$, it is bounded. Since the Laplace operator is a negative operator, the operator $L = \Delta - u$ is bounded fro …