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Banach spaces, function spaces, real functions, integral transforms, theory of distributions, measure theory.
2
votes
Accepted
Coincidence of sequential weak star closure and weak star closure
For question (1), weakly Lindelöf determined spaces (WLD spaces, for short) does it. A WLD space is characterised by the dual ball, modulo the weak-star topology, being a Corson compactum (i.e., for s …
4
votes
Scottish Book Problem 172
The answer to both Q1 (in the context given) and Q2 is yes.
Regarding the weak closure of an arbitrary set of linear functional being linear that appears to me to be sequential weak-star convergence — …
2
votes
Convex set with no interior contained in hyperplane?
Let $T\colon\mathcal{X}\to\mathcal{X}$ be a compact operator with a dense range on an infinite-dimensional separable Banach space $\mathcal{X}$ $.^{*}$ Then $K:=\overline{T(B_1(0))}$, where $B_1(0)$ i …
8
votes
2
answers
798
views
Strict topology between weak and norm topologies
I want to believe that this has an easy answer, but I’ve never considered it before and can’t seem to answer it now either.
Does every infinite-dimensional Banach space admit a locally convex vector …
0
votes
0
answers
128
views
Certain decompositions of decomposable Banach spaces
Let $\mathcal{X}$ be a decomposable Banach space (i.e. a topological direct sum of infinite-dimensional subspaces, say $\mathcal{X}=\mathcal{A}\oplus\mathcal{B}$). Can one always obtain another decom …
2
votes
Accepted
Is a mixture of $\ell_p$-norms $\eta(x):=\lVert x\rVert_2 + r\lVert x\rVert_p$ always dimens...
This is impossible unless the following holds:
$q=2$ and either $p=2$ or $r=0$.
The above exception is due to the fact that it implies $\frac{1}{1+r}\eta(\cdot)=\|\cdot\|_q=\|\cdot\|_2$, for which t …
1
vote
Inclusion of infinite intersection
While attempting to answer this question, I recalled that the term “bounded” can be pretty confusing in normed vector spaces if not clarified; in general they all take the form $$\|Tx\|\le L\|x\|+M\,, …
11
votes
Accepted
Subtracting the weak limit reduces the norm in the limit
The property you indicate is known as (strict) Opial’s Property (see https://en.m.wikipedia.org/wiki/Opial_property). It fails generally in reflexive spaces; in fact, it fails generally even for unifo …
4
votes
0
answers
195
views
Double commutant of compact operators
So my question is straightforward. Let $\mathfrak{X}$ be a (complex, if necessary) Banach space and $K\colon\mathfrak{X}\to\mathfrak{X}$ a nonzero compact operator. Denote by $\mathcal{C}(K)$ the comm …
7
votes
Accepted
On a certain norm of the identity operator on $\mathbb R^2$
Simply observe that
$$\|x\|_{a,b}=\|x_1a+x_2b\|_1\,.$$
Thus, by orthogonality of $a,b$ and the easily-derived inequality $\|y\|_2\le\|y\|_1\le\sqrt{n}\|y\|_2$ for any $y\in\mathbb{R}^n$, we have
\begi …