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Banach spaces, function spaces, real functions, integral transforms, theory of distributions, measure theory.

2 votes
Accepted

Coincidence of sequential weak star closure and weak star closure

For question (1), weakly Lindelöf determined spaces (WLD spaces, for short) does it. A WLD space is characterised by the dual ball, modulo the weak-star topology, being a Corson compactum (i.e., for s …
Jack L.'s user avatar
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4 votes

Scottish Book Problem 172

The answer to both Q1 (in the context given) and Q2 is yes. Regarding the weak closure of an arbitrary set of linear functional being linear that appears to me to be sequential weak-star convergence — …
Jack L.'s user avatar
  • 1,453
2 votes

Convex set with no interior contained in hyperplane?

Let $T\colon\mathcal{X}\to\mathcal{X}$ be a compact operator with a dense range on an infinite-dimensional separable Banach space $\mathcal{X}$ $.^{*}$ Then $K:=\overline{T(B_1(0))}$, where $B_1(0)$ i …
Jack L.'s user avatar
  • 1,453
8 votes
2 answers
798 views

Strict topology between weak and norm topologies

I want to believe that this has an easy answer, but I’ve never considered it before and can’t seem to answer it now either. Does every infinite-dimensional Banach space admit a locally convex vector …
Jack L.'s user avatar
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0 votes
0 answers
128 views

Certain decompositions of decomposable Banach spaces

Let $\mathcal{X}$ be a decomposable Banach space (i.e. a topological direct sum of infinite-dimensional subspaces, say $\mathcal{X}=\mathcal{A}\oplus\mathcal{B}$). Can one always obtain another decom …
Jack L.'s user avatar
  • 1,453
2 votes
Accepted

Is a mixture of $\ell_p$-norms $\eta(x):=\lVert x\rVert_2 + r\lVert x\rVert_p$ always dimens...

This is impossible unless the following holds: $q=2$ and either $p=2$ or $r=0$. The above exception is due to the fact that it implies $\frac{1}{1+r}\eta(\cdot)=\|\cdot\|_q=\|\cdot\|_2$, for which t …
Jack L.'s user avatar
  • 1,453
1 vote

Inclusion of infinite intersection

While attempting to answer this question, I recalled that the term “bounded” can be pretty confusing in normed vector spaces if not clarified; in general they all take the form $$\|Tx\|\le L\|x\|+M\,, …
Jack L.'s user avatar
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11 votes
Accepted

Subtracting the weak limit reduces the norm in the limit

The property you indicate is known as (strict) Opial’s Property (see https://en.m.wikipedia.org/wiki/Opial_property). It fails generally in reflexive spaces; in fact, it fails generally even for unifo …
Jack L.'s user avatar
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4 votes
0 answers
195 views

Double commutant of compact operators

So my question is straightforward. Let $\mathfrak{X}$ be a (complex, if necessary) Banach space and $K\colon\mathfrak{X}\to\mathfrak{X}$ a nonzero compact operator. Denote by $\mathcal{C}(K)$ the comm …
Jack L.'s user avatar
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7 votes
Accepted

On a certain norm of the identity operator on $\mathbb R^2$

Simply observe that $$\|x\|_{a,b}=\|x_1a+x_2b\|_1\,.$$ Thus, by orthogonality of $a,b$ and the easily-derived inequality $\|y\|_2\le\|y\|_1\le\sqrt{n}\|y\|_2$ for any $y\in\mathbb{R}^n$, we have \begi …
Jack L.'s user avatar
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