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Complex, contact, Riemannian, pseudo-Riemannian and Finsler geometry, relativity, gauge theory, global analysis.

23 votes

Manifolds admitting flat connections

I did not understand the first question Question 1 Are there manifolds with the property that each connection on is never flat? Because one of course can construct, on any manifold, a connectio …
Vladimir S  Matveev's user avatar
22 votes
1 answer
1k views

Can an Einstein metric have the same Levi-Civita connection with a non-Einstein one?

We say that two metrics are affinely equivalent if their Levi-Civita connections coincide. Is it possible that an Einstein (=Ricci tensor is proporional to the metric) is affinely equivalent to a metr …
Vladimir S  Matveev's user avatar
18 votes

Is there a global obstruction for a diffeomorphism to be an isometry?

The answer is ``no'', the pointwise condition is not enough. The example exists in dimension 1 already and can be generalized and made arbitrary weird for all dimensions. Consider a smooth functi …
Vladimir S  Matveev's user avatar
15 votes
6 answers
2k views

Does for every vector field there always exist a volume form for which the vector field is a...

Let $v$ be a vector field. Does there exists a volume form $\Omega$ such that its Lie derivative is proportional to itself with a constant coefficient: $$\mathcal{L}_v \Omega= C \cdot \Omega? \ \ \ …
Vladimir S  Matveev's user avatar
15 votes
Accepted

Is there a way to define a Lie derivative of a connection?

Of course, yes. Lie derivative is defined for any geometric object (= when it is defined what happends when we change a coordinate system): take the flow $\phi_t$ of the vector field, consider the …
Vladimir S  Matveev's user avatar
15 votes
Accepted

Alternative Almost Complex Structures

Let us first deal with linear algebra. Assume a matrix $J$ satisfies $J^k= -Id$. Then, there exists a poylnomial $P$ whose coefficients depend on the eigenvalues of your $J$ such that $P(J)$ is a …
Vladimir S  Matveev's user avatar
12 votes

Does positively curved sphere admit an isometric embedding as hypersurface in Euclidean space?

The answer of j.c. given prior to mine is of course correct but let me give a trivial reason why (in big dimensions) every Riemannian metric after an arbitrary small perturbation is not isometr …
Vladimir S  Matveev's user avatar
11 votes
Accepted

Perimeter of ellipse: Combination of two geometries

No, because otherwise we will have this property also for degenerate ellipses, which are intervals, which would imply that the euclidean distance between two (sufficiently close) points is $\lambda …
Vladimir S  Matveev's user avatar
11 votes

Can one recover a metric from geodesics?

I hope that my ``answer'' will not be understood solely as a propaganda of my survey http://arxiv.org/abs/1101.2069 where I discussed (1) how, given geodesics, to reconstruct a connection (in both …
Vladimir S  Matveev's user avatar
10 votes
Accepted

Riemannian metrics preserved by diffeomorphisms

The answer depends on the diffeomorphism. Let me give two examples, both on the standard torus $\mathbb{R}^2/_{\mathbb{Z}^2}$ with coordinates $x,y$. (Example 1:) $$\phi(x,y)= (x+ 1/2,y).$$ Fo …
Vladimir S  Matveev's user avatar
10 votes
Accepted

Smoothing of the distance function on a Riemannian manifold

You function $d_p$ is a Lipschitz function (w.r.t. to the Riemannian distance) with the Lipschitz constant $1$ and it is possibly, for every $\varepsilon>0$, to $\varepsilon$-approximate it by a smoot …
Vladimir S  Matveev's user avatar
8 votes
Accepted

What does it mean that the Hessian is proportional to the metric?

It is known (say, Y. Tashiro, Complete Riemannian manifolds and some vector fields, Trans.Amer.Math.Soc. 117(1965) 251– 275; I am not sure that Tashiro is the first who proved it and there were many …
Vladimir S  Matveev's user avatar
8 votes

Vector Fields in a Riemannian Manifold

I give a geometric explanation of the calculations of Willie, which simultaneously elaborates the suggestion of Deane. The flow of a vector field commuting with Laplacian preserves the Laplacian an …
Vladimir S  Matveev's user avatar
8 votes

Are compact, complex, affinely flat manifolds geodesically complete?

Let me give a standard example of a closed incomplete manifold with flat affine structure, whose 2-dimensional version is essentially the example from the comment of Misha. Consider $R^n\setminus 0$ …
Vladimir S  Matveev's user avatar
8 votes

Do sufficiently regular distances on manifolds come from riemannian metrics?

The Riemannian distance has the following property: it is the so called length space. I recall (one of) the definitions of the length space. Having a distance function $d$, we can define the length o …
Vladimir S  Matveev's user avatar

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