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Complex, contact, Riemannian, pseudo-Riemannian and Finsler geometry, relativity, gauge theory, global analysis.

4 votes
Accepted

Geodesic flows and Killing fields

If we have a Killing tensor field $K$ of type $(0,d)$, the function $$I:SM\to \mathbb{R}, \ I(v)= K(v,\dots, v) \ \ \ \ \ \ (\ast )$$ is constant along geodesic flow. This is a well-known knowled …
Vladimir S  Matveev's user avatar
6 votes
2 answers
453 views

How many minimal surfaces do we have if the metric in the target space is not flat

It is trivial that there are a lot of minimal surfaces in the flat $R^3$: for example, for any point, any 2-plane containing this point, and any two othogonal vectors in this plane, and any neg …
7 votes
Accepted

Conformal maps between two given domains

Any conformal map in dimensions $\ge 3$ is necessary a superposition of inversions and isometries (see e.g. the link suggested by Daniele Tampieri in his comment), so it takes the boundary of $D_1$ to …
Vladimir S  Matveev's user avatar
2 votes
Accepted

Obstructions to maximal number of independent constants of motion in a given symplectic mani...

Any symplectic 2n-dimensional manifold admits a systems of Poisson-commuting functions $f_1,..,f_n$ whose differentials are linearly independent on an open subset of full measure. The result is prove …
Vladimir S  Matveev's user avatar
4 votes

If there exists a function on a Riemannian manifold such that its Hessian matrix is the iden...

If a manifold is complete, the existence of the function $\phi$ such that $\nabla_i \nabla_j\phi = g_{ij}$ implies that the metric is flat and that in a `flat' coordinate system such that the metric …
Vladimir S  Matveev's user avatar
15 votes
6 answers
2k views

Does for every vector field there always exist a volume form for which the vector field is a...

Let $v$ be a vector field. Does there exists a volume form $\Omega$ such that its Lie derivative is proportional to itself with a constant coefficient: $$\mathcal{L}_v \Omega= C \cdot \Omega? \ \ \ …
8 votes

Questions on smoothness of Riemann metrics

I confirm the Anton's answer (No, and the phenomenon is essentially local), but I suggest another explanation which works for C^1 2-dimensional metrics. We will look for a counterexample in the clas …
Martin Sleziak's user avatar
3 votes

Curvature of singular Riemannian metric

Under stronger regularity assumptions, an analog of the curvature exists in the weak sense, i.e., in the sense of generalized functions. The stronger regularity assumption is that the metric (in your …
Vladimir S  Matveev's user avatar
5 votes
Accepted

Vector fields $X$ and $Y$ commute on a closed set $K$. Do there exist commuting $\tilde X,\t...

The picture above gives a counterexample to your hope. It is in dimension 2 but there is no problem to make it in any higher dimension. The commuting vector fields are red and blue, the compact is n …
LSpice's user avatar
  • 12.9k
7 votes
Accepted

Can the exponential map be used to define geodesics (and hence, generalisations of geodesics)?

Exponential map in your definition is closely related to the smooth family of smooth curves smoothly depending on the position such that in every point in every direction there exists precisely one …
Vladimir S  Matveev's user avatar
2 votes

Comparing diffusion processes in different metrics

The generator of the diffusion corresponding to a Riemannian metric (i.e., the diffusion process which the limit of the random walks such that their increments go along geodesics and the distributi …
Vladimir S  Matveev's user avatar
7 votes
1 answer
487 views

Smoothness of coordinates in the rectification theorem for ODE

The rectification theorem says that near a regular point every vector field $v$ is standard, that is, there exists a local coordinate system such that $v=\frac{\partial }{\partial x_1}$. In the textb …
22 votes
1 answer
1k views

Can an Einstein metric have the same Levi-Civita connection with a non-Einstein one?

We say that two metrics are affinely equivalent if their Levi-Civita connections coincide. Is it possible that an Einstein (=Ricci tensor is proporional to the metric) is affinely equivalent to a metr …
15 votes
Accepted

Alternative Almost Complex Structures

Let us first deal with linear algebra. Assume a matrix $J$ satisfies $J^k= -Id$. Then, there exists a poylnomial $P$ whose coefficients depend on the eigenvalues of your $J$ such that $P(J)$ is a …
Vít Tuček's user avatar
  • 8,597
10 votes
Accepted

Smoothing of the distance function on a Riemannian manifold

You function $d_p$ is a Lipschitz function (w.r.t. to the Riemannian distance) with the Lipschitz constant $1$ and it is possibly, for every $\varepsilon>0$, to $\varepsilon$-approximate it by a smoot …
Vladimir S  Matveev's user avatar

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