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A symmetric space is a connected Riemannian manifold in which at every point there exists a global self-isometry whose differential at the given point is minus identity.

22 votes
Accepted

Algebraic characterization of the curvature operator of symmetric spaces

I suppose that $S^2_B(\Lambda^2(\mathbb{R}^n))$ means the subspace of $S^2(\Lambda^2(\mathbb{R}^n))$ that satisfies the Bianchi identity, i.e., the kernel of the natural map $S^2(\Lambda^2(\mathbb{R}^ …
Robert Bryant's user avatar
16 votes

Curvature of the Cayley projective plane

I'm not sure what you'll count as 'elegant' or as a 'description', but here's something you may find interesting or useful: Recall that the space of curvature tensors $\mathcal{K}(V)$ on an inner pro …
Robert Bryant's user avatar
15 votes

Invariant differential operators on real Grassmannians

In this particular case, the invariant theory is pretty simple, so there is an explicit description. Recall that, in general, for a homogeneous space $M=G/H$, a $G$-invariant, $m$-th order linear d …
Robert Bryant's user avatar
10 votes

Almgren's regularity Theorem ; a simple example?

As I mentioned in my comment, a pair of orthogonal $2$-discs in $\mathbb{R}^4$ is known to be minimizing among all orientable $2$-currents with the same boundary by the technique of calibrations: One …
Robert Bryant's user avatar
8 votes
Accepted

Can all hermitian symmetric spaces be realised as coadjoint orbits?

This is true. One can use a few facts from Helgason's Differential Geometry, Lie Groups, and Symmetric Spaces to show that, indeed, $K = \mathrm{Stab}_G(Z)$. Since $M=G/K$ is an irreducible Hermitian …
Robert Bryant's user avatar
7 votes
Accepted

The automorphism group of a symplectic symmetric space

The affine group of $(M,\nabla)$ is a Lie group $G$ by Kobayashi's theorem that shows that the automorphism group of any affine connection is a Lie group (see Kobayashi and Nomizu's Foundations of Dif …
Robert Bryant's user avatar
7 votes

Jacobi fields on non-symmetric spaces

A particularly simple non-homogeneous example in which one can explicitly integrate the Jacobi equations is the complete metric on $\mathbb{R}^2$ given by $$ g = (x^2{+}y^2{+}2)\bigl(\mathrm{d}x^2+\ma …
Robert Bryant's user avatar
7 votes

Does $\mathrm{E}_7/(\mathrm{SU}_8/(\mathbb{Z}/2))$ carry an almost complex structure?

I'm sorry if this is obvious to everyone, but I thought that it was worth mentioning: I don't know the answer to the question asked, but the answer to the easier question, "Does the space $\mathrm{E} …
Robert Bryant's user avatar
6 votes
Accepted

Tori in Compact Riemannian Symmetric Spaces

I think that this is treated in Helgason's Differential Geometry, Lie Groups and Symmetric Spaces. The point is that, for any Riemannian symmetric space $G/K$, one has the notion of the rank $r$ of t …
Robert Bryant's user avatar
6 votes

Do there exist non-totally geodesic isometric minimal immersions $\mathbb{H}^2\rightarrow G/K.$

Below, I have added an answer to your question about the case of a complex semi-simple Lie group. It turns out that the answer is 'no' even in this case. The answer to your general question is 'no'. …
Robert Bryant's user avatar
6 votes
Accepted

Invariants for the isotropy representation of a Riemannian symmetric space

One reference is in Helgason's 1984 book Groups and Geometric Analysis. The result you want appears there as Corollary 5.12. The notation he uses is $X=G/K$ is a symmetric space where $G$ is connecte …
Robert Bryant's user avatar
5 votes
Accepted

Non-flat totally geodesic surfaces

Actually, I just remembered that your question is addressed in Helgason's Differential Geometry, Lie Groups, and Symmetric Spaces. Look at Theorem 11.1 of Chapter VII, which implies what you want, sin …
Robert Bryant's user avatar
2 votes
Accepted

Variation of Hodge structures associated to a hermitian symmetric domain

You might want to look at the book "Mumford-Tate Groups and Domains: Their Geometry and Arithmetic", by Mark Green, Phillip Griffiths, and Matt Kerr. You should also look at the recent work of Collee …
Robert Bryant's user avatar
1 vote

Holonomy of a triangle in an affine symmetric space

There is a general formula, essentially due to Cartan: For each $p\in G/H$, let $\iota_p:G/H\to G/H$ be the geodesic inversion through $p$, i.e., the map that reverses all geodesics through $p$. Of c …
Robert Bryant's user avatar