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Questions where the notion matrix has an important or crucial role (for the latter, note the tag matrix-theory for potential use). Matrices appear in various parts of mathematics, and this tag is typically combined with other tags to make the general subject clear, such as an appropriate top-level tag ra.rings-and-algebras, co.combinatorics, etc. and other tags that might be applicable. There are also several more specialized tags concerning matrices.

30 votes
Accepted

Matrix equation $XAXBXC=I$

Here is an argument showing that the answer is 'yes'. I'll let you check the details and that this result generalizes to all higher degrees. Consider the map $f_{ABC}:\mathrm{U}(n)\to\mathrm{U}(n) …
Robert Bryant's user avatar
28 votes

Is the linear span of special orthogonal matrices equal to the whole space of $N\times N$ ma...

For $n>2$, the span of the matrices in $\mathrm{SO}(n)$ is the full space $M_n(\mathbb{R})$ of $n$-by-$n$ matrices with real entries. …
Robert Bryant's user avatar
27 votes
Accepted

Alternate and symmetric matrices

I feel that framing this question in terms of matrices rather than bilinear forms on a vector space obscures what is actually going on and makes it harder to understand what needs to be proved. …
Robert Bryant's user avatar
26 votes
Accepted

Square root of doubly positive symmetric matrices

No. If $$A = \begin{pmatrix}10&-1&5\\-1&10&5\\5&5&10\end{pmatrix},$$ then $A$ is positive definite but does not have all entries positive, while $$ A^2 = \begin{pmatrix}126&5&95\\5&126&95\\95&95&150\ …
Robert Bryant's user avatar
23 votes
Accepted

Existence of double eigenvalue

The generic pair $A$ and $B$ of $4$-by-$4$ Hermitian symmetric matrices will not have any nonzero real linear combination that has a double eigenvalue. … Added Remark: To see the claim that this property holds for a generic linearly independent pair of Hermitian symmetric $4$-by-$4$ matrices $A$ and $B$, it is only necessary to observe the following: …
Robert Bryant's user avatar
15 votes
Accepted

$2 \times 2$ matrix question

Now consider the map $F$ from $\mathbb{R}^4$ into $\mathbb{R}^3$ (regarded as the traceless Hermitian $2$-by-$2$ matrices) defined by $$ F(x) = \left[A +BV(x) + V(x)^*B^* + V(x)^*CV(x)\right]_0\,, $$ where … For use below, define the norm on traceless Hermitian $2$-by-$2$-matrices $M$ by the rule $|M|^2 = \tfrac12 \mathrm{tr}(M^2)$. …
Robert Bryant's user avatar
15 votes
Accepted

What it is the volume of the unit ball section of the cone of positive definite matrices?

Using the operator norm, as you have defined it, the fraction of the unit ball in real symmetric $n$-by-$n$ matrices that consists of positive definite matrices is $2^{-n(n+1)/2}$. … 0.2493898621\ . $$ Thus, nearly one-quarter of the unit ball in this case consists of positive definite matrices. …
Robert Bryant's user avatar
15 votes

Parametrization of positive semidefinite matrices

To get a parameterization of the kind you want, the space $S_{n,r}$ of positive semidefinite symmetric $n$-by-$n$ matrices of rank $r$ (with ($0<r<n$) would have to be contractible, but it is not. … For example, in the first nontrivial case $r=1$, this is the space $S_{n,1}$ of rank $1$ symmetric $n$-by-$n$ matrices, and every $A\in S_{n,1}$ can be written in the form $A = vv^T$ where $v$ is a nonzero …
Robert Bryant's user avatar
12 votes
Accepted

Is there any connection between this matrices

I assume that the problem is to try to determine which pairs $(P_1,P_2)$ of positive definite Hermitian symmetric $N$-by-$N$ matrices can be written in the above form for some pair $(H_1,H_2)$ of positive … semi-definite Hermitian symmetric $N$-by-$N$ matrices. …
Robert Bryant's user avatar
12 votes
Accepted

Explicit Isomorphism between $Cl(8)$ and $\mathbb{R}(16)$

Here's a standard explicit formula: Let $\mathbb{O}\simeq\mathbb{R}^8$ denote the algebra of octonions, and for $x\in\mathbb{O}$, let $L_x$ (respectively $R_x)$ denote the linear map from $\mathbb{O} …
Robert Bryant's user avatar
11 votes

Diagonalizing quaternionic unitary matrices

This follows from the general fact that, in a compact connected Lie group, every element is conjugate to an element in a maximal torus (and all maximal tori are conjugate). This result is proved in j …
Robert Bryant's user avatar
11 votes
Accepted

Maximal compact subgroup of $\mathrm{SL}(2,\mathbb{H})$

Consider the mapping $\sigma:\GL(2,\mathbb{H})\to M_2(\mathbb{H})$ given by $$ \sigma(A) = A^* A $$ where $A^*$ is the conjugate transpose of $A$ in $M_2(\mathbb{H})$, the $2$-by-$2$ matrices with entries … Consequently, the image of $\sigma$ lies in the $6$-dimensional real subspace $S_2(\mathbb{H})$, consisting of the matrices $s\in M_2(\mathbb{H})$ that satisfy $s = s^*$. …
Robert Bryant's user avatar
10 votes

The probability for a symmetric matrix to be positive definite

If you use the fact that the group $\mathrm{SO}(n)$ acts on the symmetric matrices in the obvious way and parametrize the 'hemisphere' of symmetric matrices of positive trace and norm $1$ by the symmetric … matrices of zero trace via the $\mathrm{SO}(n)$-equivariant mapping $$ P = \frac{(I+z)}{(1+|z|^2)^{1/2}}, $$ then you can cover the symmetric matrices of trace zero by acting by $\mathrm{SO}(n)$ on the …
Robert Bryant's user avatar
10 votes
Accepted

Characteristic polynomial of an $8 \times 8$ symmetric matrix with indeterminate entries rel...

, it follows that $L$ is conjugate in $\mathrm{SO}(8)$ to an element of the maximal torus ${\mathrm{SO}(2)}^4$, i.e., a blocked diagonal matrix where the diagonal elements are the $2$-by-$2$ rotation matrices
Robert Bryant's user avatar
10 votes
Accepted

$SO(N^2-1)$ and the adjoint representation of $SU(N)$

Actually, it does not look like that. Take the case $N=3$. The representation of $\mathrm{SU}(3)$ on ${\frak{so}}(8)$ breaks up into the $8$-dimensional subspace ${\frak{su}}(3)$ and an irreducible …
Robert Bryant's user avatar

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