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Step back step forward algorithm for A108442

Let $a(n)$ be A108442. Here generating function is $\frac{1}{1-zA(z)}$ where $$ A(z) = 1 + z(A(z))^2 + z(A(z))^3. $$ Also $$ a(n) = \sum\limits_{k=1}^{n}\frac{k}{2n-k}\sum\limits_{i=0}^{n-k} \binom{2n-...
Notamathematician's user avatar
1 vote
0 answers
82 views

Generating functions related to generating function of Catalan numbers

Let $C_n$ be A000108 (i.e., Catalan numbers). Here generating function is $C(x)$ such that $$ C(x) = \frac{1-\sqrt{1-4x}}{2x}. $$ Let $a(n)$ be an integer sequence with generating function $A(x)$ such ...
Notamathematician's user avatar
2 votes
0 answers
51 views

Recursion for A129179 similar to recursion for Pascal's triangle

Let $T(n,k)$ be A129179 (i.e., triangle read by rows: $T(n, k)$ is the number of Schroeder paths of semilength $n$ such that the area between the $x$-axis and the path is $k$ ($n \geqslant 0, 0 \...
Notamathematician's user avatar
2 votes
1 answer
310 views

Generating function for A300483 (related to Chebyshev polynomial of first kind)

Let $a(n)$ be A300483. Here $$ a(n) = 2\int\limits_{t \geqslant 0}T_n\left(\frac{t+1}{2}\right)\exp(-t)\,dt. $$ where $T_n(x)$ is $n$-th Chebyshev polynomial of first kind. Let $b(n)$ be an integer ...
Notamathematician's user avatar
10 votes
1 answer
625 views

Generating function for A261041

Let $a(n)$ be A261041 (i.e., number of partitions of subsets of $\{1,2,\dotsc,n\}$, where consecutive integers are required to be in different parts). Let $b(n)$ be an integer sequence with generating ...
Notamathematician's user avatar
2 votes
0 answers
64 views

On a $\sum\limits_{n=0}^{\infty}c_n x^n=\sum\limits_{n=0}^{\infty}a(n)x^n\prod\limits_{k=1}^{n+1}(1-f(k)x^k)$ (slightly different question)

Please note that this question differs from one of the previous questions of mine. Let $f(n)$ be an arbitrary function with integer values. Let $c_n$ be an arbitrary integer sequence. Let $a(n)$ be ...
Notamathematician's user avatar
5 votes
1 answer
168 views

On a generating function and vector $\nu$ of length $n$

Let $f(n)$ be an arbitrary function with integer values. Let $a(n)$ be an integer sequence such that $$ \frac{1}{1-x}=\sum\limits_{n=0}^{\infty}a(n)x^n\prod\limits_{k=1}^{n+1}(1-f(k)x) $$ Start with ...
Notamathematician's user avatar
1 vote
0 answers
63 views

On a A162326 and vector $\nu$ of length $n$

Let $a(n)$ be A162326. Here $$ a(n) = \frac{1}{n}(2(5n-7)a(n-1) - 9(n-2)a(n-2)), \\ a(0) = a(1) = 1. $$ Also ordinary generating function is $$ \frac{5 - \sqrt{\frac{1-9x}{1-x}}}{4}. $$ Let $b(n)$ be $...
Notamathematician's user avatar
2 votes
2 answers
315 views

5 different ways to define the same family of integer sequences

Let ${n \brace k}$ be a Stirling number of the second kind. Let $A_n(x)$ be an Eulerian polynomial. Here $$ A_n(x) = \sum_{i=0}^{n}i!{n \brace i}(x-1)^{n-i}. $$ Let $a_1(n,p,q)$ be the family of ...
Notamathematician's user avatar
3 votes
1 answer
140 views

$R$-recursion for unsigned Genocchi numbers (of first kind) of even index

Let $G_n$ be A036968 (i.e., Genocchi numbers). Here $$ \frac{2t}{1+e^t}=\sum\limits_{n=0}^{\infty}G_n\frac{t^n}{n!}. $$ Also $$ t\tan\left(\frac{t}{2}\right)=\sum\limits_{n=1}^{\infty}(-1)^n G_{2n}\...
Notamathematician's user avatar
0 votes
0 answers
48 views

$R$-recursion for the A007165

Let $a(n)$ be A007165 i.e. number of $P$-graphs with $2n$ edges. Here ordinary generating function $A(x)$ satisfies $$ A(x) = \frac{(1 + xA(x))(1 + 2xA(x))}{1 + 2xA(x) - (xA(x))^2} $$ Let $$ R(n, q) = ...
Notamathematician's user avatar
1 vote
0 answers
49 views

$R$-recursion for the A036765

Let $a(n)$ be A036765 i.e. number of ordered rooted trees with $n$ non-root nodes and all outdegrees $\leqslant 3$. Here $$ a(n) = \frac{1}{n+1}\sum\limits_{j=0}^{\left\lfloor\frac{n}{2}\right\rfloor}\...
Notamathematician's user avatar
1 vote
1 answer
116 views

General case of the some $R$-recursions

Let $f(n)$ be an arbitrary function. Let $a(n)$ be an integer sequence such that its ordinary generating function satisfies $$ A(x)=\sum\limits_{i=0}^{\infty}\frac{x^i}{\prod\limits_{j=0}^{i}(1-f(j)x)...
Notamathematician's user avatar
1 vote
1 answer
99 views

$R$-recursion for the A307389

Let $a(n)$ be A307389 i.e. an integer sequence such that its exponential generating function $A(x)$ satisfies $$ A(x)=\exp\left(\frac{\exp(2x)-2\exp(x)+2x+1}{2}\right) $$ The sequence begins with $$ 1,...
Notamathematician's user avatar
3 votes
0 answers
70 views

$R$-recursion for the A249833 (similar to A235129)

Let $a(n)$ be A249833 i.e. an integer sequence such that its exponential generating function $A(x)$ satisfies $$ A(x) = 1 + \int A(x) + (A(x))^2\log A(x)\,dx $$ The sequence begins with $$ 1, 1, 2, 7, ...
Notamathematician's user avatar
2 votes
0 answers
103 views

$R$-recursion for the A235129

Let $a(n)$ be A235129 i.e. an integer sequence such that its exponential generating function $A(x)$ satisfies $$ A'(x) = 1 + A(x)\exp(A(x)) $$ The sequence begins with $$ 1, 1, 3, 12, 64, 424, 3358, ...
Notamathematician's user avatar
2 votes
1 answer
335 views

Combinatorial meaning of a binomial expansion

Let $F$ be a generating function $F(x) = \sum_{i=0}^\infty f_i x^i$, and suppose that we can do operations formally without worrying about convergence issues. Define the coefficients \begin{gather*} ...
Student's user avatar
  • 5,230
4 votes
0 answers
211 views

Sum $f(n_1,n_2,\ldots,n_k) 1^{n_1} 2^{n_2} \ldots k^{n_k}$ over partitions

Use the notation $(n_1,n_2,\ldots,n_k) \vdash n$ to denote that $(n_1,n_2,\ldots,n_k)$ is a partition of the positive integer $n$, that is, $n_1+n_2+\ldots+n_k = n$ and $n_1 \ge n_2 \ge \ldots \ge n_k ...
Dreamer's user avatar
  • 261
3 votes
1 answer
156 views

$q$-series and Stirling of the 1st kind

Denote the (unsigned) Stirling numbers of the $1^{st}$-kind by ${n \brack k}$ and define $$\mathbf{F}_a(q)=\sum_{m\geq1}\frac{q^{am}}{(1-q^m)^{2a}} \qquad \text{and} \qquad \mathbf{G}_b(q)=\sum_{m\...
T. Amdeberhan's user avatar
1 vote
0 answers
89 views

Suitable recursion for the A234289

Let $a(n)$ be A234289 i.e. integer sequence with exponential generating function $$ A(x)=1+A(x)^2\int \frac{1}{A(x)}\,dx $$ The sequence begins with $$ 1, 1, 3, 17, 147, 1729, 25827, 468593, 10012083, ...
Notamathematician's user avatar
1 vote
0 answers
80 views

Recursion for the A006014 using difference of binomial coefficients

Let $a(n)$ be A006014 i.e. $$ a(n)=na(n-1)+\sum\limits_{j=1}^{n-2}a(j)a(n-j-1), \\ a(1)=1 $$ Also generating function $A(x)$ satisfies $$ A(x) = x(1 + A(x) + A(x)^2 + xA'(x)) $$ Let $$ R(n,q)=\sum\...
Notamathematician's user avatar
4 votes
0 answers
118 views

Something (which might be called multi-continued fraction) for the A112487

Let $a(n)$ be A112487 i.e. an integer sequence with exponential generating function $$ A(x)=\exp\left(\int (A(x)+A(x)^2)\,dx\right), \\ A(0)=1 $$ However, the definition in the name of the sequence is ...
Notamathematician's user avatar
0 votes
0 answers
100 views

Recursion for the A266328 by analogy with non-standard recursion for factorials

Let $a(n)$ be A266328 i.e. an integer sequence with exponential generating function $$ A(x)=\exp\int B(x) \,dx $$ such that $$ B(x)=\exp(-x)\exp\int A(x) \,dx $$ where the constant of integration is ...
Notamathematician's user avatar
0 votes
0 answers
181 views

Expansion of continued fraction using recursion

Let $f(n)$ be an arbitrary function such that $f(n)\in\mathbb{Z}$. Let $a(n)$ be an integer sequence with generating function $\frac{1}{G(0)}$ where $$ G(j)=1-\frac{f(j)x}{G(j+1)} $$ Here we have $$ G(...
Notamathematician's user avatar
1 vote
1 answer
344 views

Products involving exponents of tribonacci numbers

The Fibonacci numbers $F_n$ can be given by $$\sum_{k\geq0}F_kx^k=\frac{x}{1-x-x^2}.$$ Among many many properties of this sequence, consider the following two results: (1) the coefficients of the ...
T. Amdeberhan's user avatar
0 votes
0 answers
73 views

Sequences that sum up to possible generalization of Euler or up/down numbers (A000111)

Let $a(n,m,k)$ be an integer sequence with e.g.f. $$A(x)=\operatorname{exp}\left(x + m\int\int (A(x))^k \, dx \, dx\right)$$ I don't know much about integrals, so here's a concrete example: $a(n,1,3)$...
Notamathematician's user avatar
1 vote
0 answers
93 views

Application of the series reversion

Let $f(n)$ be an arbitrary function such that $f(n)\in\mathbb{Z}$. Let $a(n)$ be an arbitrary integer sequence such that $a(0)=1$. Let $b(n)$ be an integer sequence such that $$b(2^m(2n+1))=\sum\...
Notamathematician's user avatar
0 votes
1 answer
195 views

Fibonacci and product polynomials

The motivation for my current question arises from this MO post by R. Stanley. Caveat. There's a slight alteration. With the convention $F_1=F_2=1$ for the Fibonacci numbers, define the polynomials $...
T. Amdeberhan's user avatar
4 votes
0 answers
414 views

Explicit formula for tournament sequence

I am looking for an explicit formula for a sequence. The sequence is generated as follows: There is a tournament with $10$ teams. In the beginning, all teams have a 0-0 win-loss record. The teams are ...
Jackson's user avatar
  • 41
2 votes
0 answers
110 views

Asking for a generating function for an arithmetic sequence

For fixed integer $n\geq1$, let $c_m(n)$ be the number of divisors $d$ of $m$ such that $n<d\leq 2n$. Here is an experimental generating function for which I ask: QUESTION. Is this true? $$\sum_{m\...
T. Amdeberhan's user avatar
1 vote
1 answer
155 views

Log-concavity of sequence related to overpartitions

The number $p_1(n)$ of overpartitions of $n$ is generated by $$\sum_{n\geq0}p_1(n)\,q^n=\prod_{k=1}^{\infty}\frac{1+q^k}{1-q^k}.$$ Let $t\in\mathbb{N}$. Now, extend this to construct a family of ...
T. Amdeberhan's user avatar
7 votes
0 answers
174 views

A diagonal generating function for Fibonacci: Part II

In my earlier MO question, I mentioned although we have for the Fibonacci numbers that $$F_n=[x^n]\left(\frac1{1-x-x^2}\right),$$ is there a function $F(x)$ such that $F_n=[x^n]\left(F(x)\right)^n$? ...
T. Amdeberhan's user avatar
14 votes
7 answers
3k views

A special type of generating function for Fibonacci

Notation. Let $[x^n]G(x)$ be the coefficient of $x^n$ in the Taylor series of $G(x)$. Consider the sequence of central binomial coefficients $\binom{2n}n$. Then there two ways to recover them: $$\...
T. Amdeberhan's user avatar
5 votes
1 answer
204 views

Collapsed partitions and generating functions

Given $n\in\Bbb{N}$, the number of (unrestricted) integer partitions of $n$ are given by $$\sum_{n\geq0}p(n)x^n=\prod_{j\geq1}\frac1{1-x^j}.$$ Define the collapsed partitions of $n$ to be the ...
T. Amdeberhan's user avatar
17 votes
1 answer
756 views

Congruences Ramanujan-style

Let $t\in\Bbb{N}$ and consider the sequences $p_t(n)$ defined by $$\sum_{n\geq0}p_t(n)x^n=\prod_{i\geq1}\frac1{(1-x^i)^t}=(x;x)_{\infty}^{-t}.$$ The numbers $p_t(n)$ can be regarded as enumerating ...
T. Amdeberhan's user avatar
15 votes
0 answers
767 views

Wherefore art thou a Borcherds Product?

This question essentially asks how can one recognize (or rule out) that a generating function of combinatorial origin may be given as a Borcherds type product. I'll start with a motivational example: ...
Gjergji Zaimi's user avatar
1 vote
1 answer
235 views

partition theory: meet the COP

Recall that $(a;q)_0:=1,\,(a;q)_n=(1-a)(1-aq)(1-aq^2)\cdots(1-aq^{n-1})$ and $(a;q)_{\infty}=(1-a)(1-aq)(1-aq^2)\cdots$. Let's introduce the following (generalized) concept. A colored overpartition (...
T. Amdeberhan's user avatar
8 votes
1 answer
368 views

generalizing Wilf's conjecture: Uppuluri-Carpenter numbers

The complementary Bell numbers have the exponential generating function $$\sum_{n\geq0}\tilde{B}_nx^n=e^{1-e^x}.$$ Herb Wilf conjectured that $\tilde{B}_n=0$ only for $n=2$. By now, there are a few ...
T. Amdeberhan's user avatar
5 votes
0 answers
170 views

operation on Ord., Exp., Dri. generating functions

The ordinary, exponential and Dirichlet generating functions for a sequence $\{a_n\}_{n\geq0}$ are given (at least on the formal side), respectively, by $$F(x)=\sum_{n\geq0}a_nx^n, \qquad E(x)=\sum_{n\...
T. Amdeberhan's user avatar
4 votes
0 answers
312 views

Unexpected result related to open question whether $\sum x^{n^3}$ can satisfy an ADE

In Stanley EC2, it is an open question whether $\sum b_nx^{n^3}$ can satisfy an ADE. Stanley remarks that if this is true then it leads to a "completely unexpected result about representing integers ...
Math Helper's user avatar
2 votes
1 answer
160 views

An inequality on partitions into distinct bounded parts

Let $P(n,m)$ denote the set of all positive integer partitions of $n$ into parts that are pairwise distinct and bounded by $m$. Let $p(n,m) = |P(n,m)|$. After some numerical experiments it appears $...
user94267's user avatar
  • 305
3 votes
1 answer
349 views

Generating function for numbers divisible by some primes

Consider the first $k$ primes $p_1 = 2, p_2 = 3, \dots, p_k$. Let $A_k$ be the set of numbers that are divisible by at least one $p_i$. We can represent this set as a generating function: $$G_k(x) = \...
Danny Nguyen's user avatar
3 votes
2 answers
609 views

Closed formula for the generating function of the sequence of powers

Does anyone know of a closed formula for the function $f_k(x)=\sum_{n=1}^{\infty}{n^k x^n}$ ? That is, the generating function of the sequence $1^k,2^k,3^k...$. It is not hard to see that $f_k(x)=\...
user85783's user avatar
14 votes
1 answer
755 views

Generating function of the Thue-Morse sequence

Let $T$ be the generating function of the Thue-Morse sequence; thus, $T(x)=x+x^2+x^4+x^7+\dotsb$. It is known that $T$ satisfies the nice congruence $$ (1+x)^3 T^2(x) + (1+x)^2 T(x) + x \equiv 0 \...
Seva's user avatar
  • 23k
2 votes
1 answer
400 views

An infinite product: combinatorial interpretation

It is an undergraduate exercise to show that the generating function for the sequence of unrestricted integer partitions $p(n)$ is the celebrated infinite product $$\prod_{k=1}^{\infty}\frac{1}{1-x^k}...
Johnny Cage's user avatar
  • 1,561
5 votes
2 answers
3k views

Number of 1 in binary representation of n

Let $1(n)$ be the number of digits $1$ in binary representation of number $n$. For example, $13=1101_2$ so $1(13)=3\\$ Is there explicit form of $\,\,\sum{1(i)x^i} $? I checked OEIS and didn't find ...
Radmir's user avatar
  • 443
2 votes
2 answers
894 views

Proving generating functions equality

What do you use to prove the following equality (and possibly more general ones of the kind)? \begin{align*}\sum_{r,s,t} \frac{q^{r^2+rs+s^2+st+t^2}}{(q)_r (q)_s (q)_t} z_1^{r+s} z_2^{s+t} = \sum_{a,...
Andrew's user avatar
  • 21
5 votes
1 answer
442 views

Generating function related to 2-residues of partitions

Question Express the following power series in two commuting variables $x,y$ as an infinite product, or a short sum of infinite products: $$ \frac{P(xy)^2}{(1-x)}\sum_{k=-\infty}^\infty(2k+1)x^{k^2}y^...
John Murray's user avatar
  • 1,090
8 votes
2 answers
4k views

What are the best known bounds on the number of partitions of $n$ into exactly $k$ distinct parts?

For example, if $n = 10$ and $k = 3$, then the legal partitions are $$10 = 7 + 2 + 1 = 6 + 3 + 1 = 5 + 4 + 1 = 5 + 3 + 2$$ so the answer is $4$. By choosing $k$ random elements of $\{1,\ldots,2n/k\}$, ...
Rob's user avatar
  • 195
11 votes
3 answers
659 views

Identifying the generating function $ G(a,z) = \sum_{n=0}^{\infty} a^n z^{(n+1)(n+2)/2}. $

I have computed a generating function for a problem involving a particular series, and would like to know if anyone has any references or a categorisation for it? It's $$ G(a,z) = \sum_{n=0}^{\infty} ...
Granger's user avatar
  • 347