All Questions
Tagged with mg.metric-geometry alexandrov-geometry
171 questions
4
votes
1
answer
385
views
Extend the Wilking Connectiveity Theorem to Alexandrov spaces
In the conference "on Manifolds with Non-negative Sectional Curvature" held in 2007,
Problem 6 is:
Extend the Wilking Connectivity Theorem to Alexandrov spaces, i.e. if $X$ is a positively curved ...
- 689
11
votes
4
answers
734
views
Source for: Geodesics in CAT(0) spaces
I am seeking a good introductory reference that could lead to an understanding of
the properties of geodesics in
complete CAT(0) metric spaces.
I am especially interested in learning the differences ...
- 151k
10
votes
0
answers
387
views
Is it overkill to invoke Kirszbraun theorem to prove the following fact ?
Given a small enough convex triangle $(abc)$ in a (smooth or Alexandrov) surface $(X,d)$ of curvature greater than $-1$, let $(\overline{abc})$ be its comparison triangle in $\mathbb{H}^2$. Then there ...
- 4,123
10
votes
1
answer
935
views
Smoothability of compact Alexandrov surfaces with curvature bounded from below
Let $(X,d)$ be compact metric space of curvature greater than $-1$ (in the sense of comparison triangles), assume that its Hausdorff dimension is $2$. Then a result of Perelman says that $X$ is a 2-...
- 4,123
5
votes
1
answer
357
views
Flat sector in a proper cocompact CAT(0) space
Let $X$ be a complete CAT(0) space with a proper and cocompact group action by isometries, and suppose there are $\xi, \xi' \in \partial X$ with $\angle (\xi, \xi') < \pi$. Using proposition 9.5 (3)...
- 53
15
votes
2
answers
1k
views
infinite dimensional CAT(0) groups
Usually a CAT(0) group is defined to be a group acting properly isometrically and cocompactly on a CAT(0) space, but I would like to consider only those groups that act properly, isometrically and ...
- 11.1k
6
votes
1
answer
768
views
Examples of CAT(0)-groups
My question is the following:
Let M be a simply connected Riemannian manifold whose sectional curvatures
are all nonpositive and let G be a group. Suppose that G acts in M properly discontinuous and
...
- 235
3
votes
3
answers
485
views
Is this the CAT(0) metric on an affine building?
Let $R$ be a discrete valuation ring qith quotient field $Q$ and let $t\in R$ be a generator of the unique maximal ideal in $R$. Let $V$ be a finite-dimensional $Q$-vector space. Then one can consider ...
- 11.1k
9
votes
1
answer
734
views
Metric spheres in CAT(0) manifolds
Let $X$ be a topological manifold of dimension $n$, equipped with a compatible CAT(0) metric.
Are sufficiently small metric spheres in $X$ homeomorphic to metric spheres in Euclidean space $\mathbb{E}^...
- 687
10
votes
1
answer
933
views
Metrically singular Alexandrov space.
Perelman's stability theorem shows in particular that a finite dimensional compact Alexandrov space $(X,d)$ such that $X$ is not a topological manifold cannot be approximated in the Gromov-Hausdorf ...
- 4,123
9
votes
1
answer
1k
views
Rigidity of triangle comparison in Alexandrov spaces
For $CAT(\kappa)$ spaces $X$ we have following rigidity result: if equality holds in any of the comparison distances between a triangle $\Delta$ in $X$ and the corresponding comparison triangle $\...
- 265
15
votes
0
answers
753
views
Are all these groups CAT(0) groups?
Given a geodesic metric space $X$ together with a choice of midpoints
$m:X\times X\rightarrow X$ (i.e. $d(m(x,y),x)=d(m(x,y),y)=d(x,y)/2$).
Assume furthermore, that the following nonpositive curvature ...
- 11.1k
6
votes
1
answer
323
views
Stability of midpoints in CAT(0) spaces
Given a CAT(0) space $X$ and a compact, convex subset $A$ of $X$. One can define its midpoint $m(A)$ as the point, at which the following function attains its minimum.
$f:A\rightarrow \mathbb{R}\qquad ...
- 11.1k
7
votes
1
answer
2k
views
Details of Perelman's example about soul of Alexandrov space
Reading Perelman's preprint(1991) Alexandrov space II now. Got confused about the last section 6.4, which contains an example which indicate that the statement ".... manifold is diffeomorphic to the ...
- 1,101
11
votes
1
answer
1k
views
In a locally CAT(k) space, does uniqueness of geodesics imply the lack of conjugate points?
A complete, simply connected Riemannian manifold has no conjugate points if and only if every geodesic is length-minimizing. I just realized that I don't know whether the same is true for a locally ...
- 32.4k
3
votes
1
answer
325
views
Is Level set of Regular functions in Alexandrov spaces again an Alex. space?
Let $X^n$ be an Alexandrov space, and $f: X^n\to \mathbb R^k$ a regular map, does the level set necessary be an Alexandrov space?
In my mind, the intrinsic metric on the level set is 'comparable' to ...
- 1,101
4
votes
2
answers
2k
views
Are isometries the only geodesic preserving maps in a CAT(0)-space?
Given any CAT(0) space $X$, we can define a map $s:X\times X\times [0;1]\rightarrow X$, such that $s(x,y,-)$ is the constant speed geodesic from $x$ to $y$ . Any isometry $f$ of $X$ is compatible with ...
- 11.1k
4
votes
2
answers
863
views
Soul theorem for non-negativly curved open Alexandrov manifolds?
Alexandrov manifold means Alexandrov space which happens to be a manifold, i.e. the space of directions is homeomorphic to shpere. Sorry for introducing this new term.
For such a open manifold does ...
- 1,101
6
votes
2
answers
365
views
Why is GL(n,C)/U(n) a CAT(0) space?
The title says it all. In one of his answers to the question "Convex hull in CAT(0)" (I don't have the points to post a link, if someone doesn't mind link-ifying this that would be cool), Greg ...
- 2,869
7
votes
2
answers
1k
views
Example of non-closed convex hull in a CAT(0) space
this is related to this question but is simpler, and hopefully is well-known. There are a number of references that say that the convex hull of a collection of points in a CAT(0) space need not be ...
- 4,462
28
votes
8
answers
5k
views
Convex hull in CAT(0)
Let $X$ be complete $\mathop{CAT}(0)$-space and $K\subset X$ be a compact subset.
Is it true that convex hull of $K$ is compact?
Comments:
Convex hull of $K$ = intersection of all closed convex sets ...
- 45k