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6 votes
1 answer
588 views

A numerical matrix of power sum polynomials

Let $p_i=x_1^i+x_2^i+\cdots+x_m^i=\sum_{k=1}^mx_k^i$ be the power sum polynomials. Then, the determinant of the $m\times m$ Hankel matrix $M_m=(p_{i+j-2})$, for $1\leq i,j\leq m$, has a neat ...
T. Amdeberhan's user avatar
2 votes
1 answer
358 views

q-polynomials in terms of a basis

Consider the polynomials $$f_n(q)=\prod_{j=1}^n(1+q^j) \qquad \text{and} \qquad g_m(q)=1+q+q^2+\cdots+q^m.$$ I'll list a few examples to motivate my question. Direct calculations show that $$f_1=g_1, \...
T. Amdeberhan's user avatar
5 votes
1 answer
396 views

Characteristic polynomial of a simple matrix: Chebyshev?

In my recent MO question, Darij Grinberg mentioned a closely related (structure-wise) determinant, that is, $$\det\left(x_{\min\{i,j\}}\right)_{i,j}^{1,m}=x_1(x_2-x_1)(x_3-x_2)\cdots(x_m-x_{m-1}).$$ ...
T. Amdeberhan's user avatar
4 votes
1 answer
313 views

A determinant of perfect square polynomials

Usually, I like working with determinants related to the Vandermonde matrix, i.e. $$\det(x_j^{i-1})=\prod_{i<j}(x_j-x_i).$$ However, I run into some unusual matrix and its determinant. Define the $(...
T. Amdeberhan's user avatar
3 votes
1 answer
165 views

The inverse of a symbolic matrix (with reciprocal binomials) has Laurent entries

Recalling the $q$-binomials (Gaussian polynomials). Let $[n]_q!=\prod_{j=1}^n\frac{1-q^j}{1-q}$ and $\binom{n}k_q=\frac{[n]_q!}{[k]_q!\cdot[n-k]_q!}$. Now, consider the $n\times n$ matrix $\mathbf{M}...
T. Amdeberhan's user avatar
3 votes
0 answers
207 views

On a variation of the Vandermonde matrix

The ubiquitous Vandermonde matrix, of entries $(x_i^{j-1})_{i,j}^{1,n}$, and its determinant $$\prod_{i<j}^{1,n}(x_j-x_i)$$ have found many utilities in Combinatorics and Physics, among other ...
T. Amdeberhan's user avatar
1 vote
1 answer
204 views

Interpret this matrix and its determinant

Let $n\geq1$ be an integer. Take the matrix $M(n)$, with entries, $M_{i,j}(n)=\sin\left(\frac{(i+j)\pi}2\right)$ if $i\neq j$ and $M_{i,i}(n)=x_i$. I wish to ask (this question has been modified from ...
T. Amdeberhan's user avatar
3 votes
1 answer
156 views

How can I show $\{\mathbf{x}: \dim (\ker M_1(\mathbf{x}) \cap \ker M_2(\mathbf{x})) \geq C \}$ is an affine variety?

Let $M_1(\mathbf{x})$ and $M_2(\mathbf{x})$ be $m$ by $m$ matrices with each entry a homogeneous form in $\mathbb{C}[x_1, \ldots, x_n]$. I would like to show that $$ \{ \mathbf{x} \in \mathbb{A}^n_{\...
Johnny T.'s user avatar
  • 3,625
5 votes
1 answer
213 views

Matrix-valued periodic Fibonacci polynomials

Consider the Fibonacci polynomials $f_n(x)$, defined by the recursion $f_n(x)=xf_{n-1}(x)-f_{n-2}(x)$ with initial values $f_0(x)=0$ and $f_1(x)=1$. It is well known that the values of these ...
Johann Cigler's user avatar
3 votes
1 answer
779 views

Lower bound of the expectation of the product of inner products of random vectors

I encountered the following value in my research: Let $n,m$ be some integer. Suppose $\alpha_1,\dots,\alpha_m$ are unit vectors in $\mathbb{R}^n$. Denote $$ L = \mathop{\mathrm{E}}_x[ \prod_{1\...
Lwins's user avatar
  • 1,551
10 votes
1 answer
520 views

Homogeneous polynomials, mixed determinants, positive definiteness

Are there $n\times n$ real matrices $A_{1}, \ldots, A_{n}$ such that the $n$-homogeneous polynomial $$ f(x_{1}, \ldots, x_{n}) = \det(x_{1} A_{1}+\cdots +x_{n} A_{n}) $$ never vanishes on $\...
Paata Ivanishvili's user avatar
1 vote
1 answer
152 views

Positive solutions to simultaneous real quadratic equations

I have a system of $n$ quadratic equations with $n$ unknowns. It can be written as $diag(x)Ax=1$ $x$ is an $n$-vector, $A$ is $n\times n$, real, symmetric and positive definite, the diagonal ...
Andy's user avatar
  • 13
-4 votes
2 answers
6k views

Factorizing polynomials of several variables (in a different perespective)

I am looking for factorization of polynomials of several variables in the way outlined below. Consider a second degree polynomial of two variables over the complex numbers. "P(x,y) = Ax^2 + Bxy + Cy^...