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Equivalence of triangulated categories defined by tilting objects

I asked this question on stack exchange (https://math.stackexchange.com/questions/4983535/equivalence-of-triangulated-categories-defined-by-tilting-objects), but got no responses, so I ask it here. ...
Sunny Sood's user avatar
11 votes
1 answer
513 views

When does derived tensor product commute with arbitrary products?

Let $R$ be a commutative Noetherian ring. Let $M$ be an $R$-module. It is well-known that $M$ is finitely generated if and only if the functor $M\otimes_R (-)$ preserves arbitrary products (for ...
uno's user avatar
  • 412
3 votes
0 answers
120 views

Derived tensor by perfect complex preserves exact triangle in singularity category?

Let $R$ be a commutative Noetherian ring. Let $\operatorname{D}_{sg}(R)$ be the singularity category of $R$, i.e., the Verdier localization of $D_b(\text{mod } R)$ by the thick subcategory of perfect ...
Snake Eyes's user avatar
1 vote
0 answers
126 views

full strong exceptional collection

I am wondering whether, if a triangulated category $\mathcal{D}$ has a full strong exceptional collection (infinite), it is triangle-equivalent to the bounded derived category of finitely generated ...
Paulo Rossi's user avatar
4 votes
1 answer
267 views

A particular morphism being zero in the singularity category

Let $R$ be a commutative Noetherian ring and $D^b(R)$ be the bounded derived category of finitely generated $R$-modules. Let $D_{sg}(R)$ be the singularity category, which is the Verdier localization $...
strat's user avatar
  • 361
3 votes
1 answer
129 views

Thick subcategory containment in bounded derived category vs. singularity category

Let $R$ be a commutative Noetherian ring, and $D^b(\operatorname{mod } R)$ the bounded derived category of the abelian category of finitely generated $R$-modules. Let me abbreviate this as $D^b(R)$. ...
Alex's user avatar
  • 480
6 votes
1 answer
233 views

Comparing stabilization of stable category modulo injectives and a Verdier localization

Let $\mathcal A$ be an abelian category with enough injectives. Let $\mathcal I$ be the collection of injective objects. Let $\mathcal A/\mathcal I$ be the quotient category whose objects are same as ...
Snake Eyes's user avatar
2 votes
0 answers
73 views

From exact triangles in the stable category of maximal Cohen--Macaulay modules to short exact sequences

Let $R$ be a local Gorenstein ring. Let $\underline{\text{CM}}(R)$ be the stable category of maximal Cohen--Macaulay modules, it is known to carry a triangulated structure. My question is: If $M\to N\...
Alex's user avatar
  • 480
2 votes
1 answer
146 views

Why is this map a split monomorphism?

I have a question regarding a lemma in the proof of Hopkins-Neeman Correspondence. It is the beginning part of Lemma 1.2 in the The Chromatic Tower for D(R) Let $Y$ be an object of the derived ...
Subham Jaiswal's user avatar
1 vote
0 answers
158 views

When is a functor of chain complexes triangulated?

Let $\textsf{A}, \textsf{B}$ be abelian categories. Let $F: \operatorname{Ch}(\textsf{A}) \to \operatorname{Ch}(\textsf{B})$ be an additive functor of chain complexes. If $F$ preserves chain ...
Jannik Pitt's user avatar
  • 1,474
3 votes
0 answers
106 views

Multiplication map by a ring element on an object vs. all its suspensions in singularity category

Let $R$ be a commutative Noetherian ring, consider the bounded derived category of finitely generated $R$-modules $D^b(R)$ and consider the singularity category $D_{sg}(R):=D^b(R)/D^{perf}(R)$. Let $r\...
uno's user avatar
  • 412
3 votes
1 answer
123 views

Vanishing of self-hom in Spanier–Whitehead stabilization category

$\DeclareMathOperator\Hom{Hom}\DeclareMathOperator\SW{SW}$Let $R$ be a commutative Noetherian ring. For $R$-modules $M,N$, let $\mathcal I_R(M,N)$ be the collection of all $f\in \text{Hom}_R(M,N)$ ...
Snake Eyes's user avatar
4 votes
1 answer
230 views

Decompose an unbounded (cochain) complex in the homotopy category

Let $\mathcal{A}$ be an abelian category, it is known that any complex $A^{\bullet}$ admits a distinguished triangle $$B^{\bullet}\rightarrow A^{\bullet}\rightarrow C^{\bullet}\rightarrow B^{\bullet}[...
user avatar
3 votes
2 answers
376 views

Is there an elementary reason that this colocalisation map of complexes is a quasi-isomorphism?

A fact about triangulated categories is that (exact) localisation functors and so-called colocalisation functors come in pairs, making an exact localisation triangle. I've tried to come up with less ...
Justin Bloom's user avatar
1 vote
1 answer
149 views

Finitely generated module, which is a virtually small complex, embeds into a module of finite projective dimension?

Let $R$ be a commutative Noetherian ring, and let $\text{mod } R$ denote the abelian category of finitely generated $R$-module. Consider the bounded derived category $D^b(\text{mod } R) $ which is a ...
feder's user avatar
  • 73
4 votes
0 answers
114 views

Classification of 2-periodic triangulated categories

Let $T$ be an algebraic triangulated (k-linear over a field, Hom-finite, idempotent-complete) category. Call $T$ 2-periodic if $\Omega^2(X) \cong X$ for all $X \in T$. Question 1: Is there a ...
Mare's user avatar
  • 26.5k
2 votes
0 answers
101 views

Find a Morita equivalent finite cell DG category

I am trying to understand the following statement: Suppose that $\mathcal{E}$ is a pre-triangulated proper DG category with a full exceptional collection. Then $\mathcal{E}$ is Morita equivalent to a ...
Harold Finch's user avatar
3 votes
1 answer
597 views

Yoneda Ext theorem and extensions

Consider the category of chain complexes over a ring $R$. We can show that $\text{Ext}^1(M, N)$ classifies extensions using the triangulated category structure: the homotopy kernel of a map $N \...
user avatar
5 votes
0 answers
190 views

On the not so clear relationship between torsion theories and localization for a newcomer

Given an hereditary torsion theory $(\mathcal{T}, \mathcal{F})$ on an abelian category $\mathcal{A}$, how we can relate this to a localization (i.e Ore localization). This is mentioned with not so ...
Køb's user avatar
  • 83
9 votes
1 answer
615 views

Any news about equivalences of periodic triangulated or $\infty$-categories?

There is a very old question (October 2009) Equivalence of derived categories which is not Fourier-Mukai which has been bumped by improving links to the literature in one of the answers and attracted ...
მამუკა ჯიბლაძე's user avatar
4 votes
1 answer
362 views

Bousfield localization of triangulated categories:equivalent conditions

In these notes on pages 60-64 Daniel Murfet proves the equivalence of 6 conditions of what it means for the Verdier quotient to be Bousfield localization. I, however, do not understand certain steps ...
Jxt921's user avatar
  • 1,115
9 votes
0 answers
499 views

3x3 lemma in triangulated categories

I am currently reading Le Stum's Rigid Cohomology and have encountered the following passage (proof of Proposition 5.2.16): The deduction made here seems to be purely "triangulated category-...
Wojowu's user avatar
  • 28.2k
1 vote
1 answer
360 views

Computing Ext groups in a functor stable $\infty$-category

Let $I$ be a small category and $\mathcal{D}=D^b_\infty(\mathbb{Z})$ the bounded derived $\infty$-category of abelian groups. Consider the $\infty$-category $\mathcal{C}:=\mathrm{Fun}(I,\mathcal{D})$. ...
Adrien MORIN's user avatar
2 votes
0 answers
112 views

Cone of a morphism of complexes that are concentrated in degree $0$ and $1$

Let $R$ be a ring and $f:A\to A'$ and $g:B\to B'$ be morphisms of $R$-modules. Let $h:C_{\bullet}\to C_{\bullet}'$ be a morphism of $R$-module complexes fitting in a morphism of distinguished ...
Stabilo's user avatar
  • 1,479
3 votes
1 answer
125 views

Smallness condition for augmented algebras

I'm not sure this question is research level question. Sorry in advance. Hypothesis $k$ is a commutative ring. $A$ is an augmented $k$-algebra. $A^e$ is defined as the $k$-algebra $A\otimes_{k}A^{op}$...
Let's user avatar
  • 511
1 vote
1 answer
872 views

Homotopy equivalences and Mapping Cones

Edit: Version 2: Suppose that $A,B,C$ are chain complexes and $f: A \rightarrow B$ is a chain map. Suppose that there is a homotopy equivalence $$ \text{Cone}(f: A \rightarrow B) \simeq C.$$ The chain ...
physician's user avatar
4 votes
1 answer
333 views

Does localization at quasi-isomorphisms imply homotopy invariance?

Usually, the derived category of some abelian category $A$ (I'm happy already with $A$-mod) is defined first taking chain complexes up to homotopy, and then localize at quasi-isomorphisms. My question ...
Marco Farinati's user avatar
8 votes
2 answers
2k views

idea and intuition behind triangulated category

I have some trouble in understanding the significance of some axiom of triangulated category. If someone could explain to me each axiom with some intuition, and explain to me the intuition behind the ...
Amos Kaminski's user avatar
16 votes
0 answers
631 views

The Octahedral Axiom in group theory

$\require{AMScd}$Here are two results about groups: (The third isomorphism theorem) Suppose that I have $A \triangleleft B \triangleleft C$ and $A \triangleleft C$. Then $C/B \cong (C/A)/(B/A)$. ...
David E Speyer's user avatar
32 votes
3 answers
4k views

Replacing triangulated categories with something better

Gelfand and Manin in their 1988 book on homological algebra write that the non-functoriality of cones means that "something is going wrong in the axioms of a triangulated category. Unfortunately at ...
Hugh Thomas's user avatar
  • 6,282
12 votes
0 answers
688 views

Kontsevich's derived noncommutative geometry and Rosenberg's noncommutative 'spaces'

It appears to me (though I may be wrong) that the common opinion is that the main difference between derived noncommutative geometry and Rosenberg's noncommutative 'spaces' is that Rosenberg's version ...
Doelt_k's user avatar
  • 439
4 votes
2 answers
352 views

Are hearts of all $t$-structures on smashing triangulated categories closed with respect to coproducts (also)?

Let $T$ be a triangulated category closed with respect to (small) coproducts, and $t$ be (an arbitrary!) a $t$-structure on $T$. I have noted that the heart $\underline{Ht}$ of $t$ is closed with ...
Mikhail Bondarko's user avatar
3 votes
0 answers
156 views

Weak generators of the right-bounded derived category of a finite-dimensional algebra

The setup: Let $A$ be a finite-dimensional $k$-algebra over some field $k$. Let $\mathcal{B} = Hot^-(Proj \, A)$ denote the homotopy category of cochain complexes of (possibly infinitely generated) ...
Wayne's user avatar
  • 61
4 votes
2 answers
337 views

When is $\Omega^1$ an equivalence?

Let $C$ be an abelian category with enough projectives and $\underline{C}$ the stable category of $C$ that is obtained by factoring out projective modules. When is the functor $\Omega^1 : \underline{...
Mare's user avatar
  • 26.5k
4 votes
0 answers
258 views

Generators of unbounded derived categories of (quasi-)coherent sheaves

An object $T$ in a triangulated category $\mathcal{D}$ is called a generator if $T^\perp=0$, which means that for any nonzero $X$ in $\mathcal{D}$, there are $i\in\mathbb{Z}$ and a nonzero morphism $T[...
Andrea's user avatar
  • 263
10 votes
1 answer
342 views

Vanishing natural transformation exact triangle

This question is a follow-up to this question I asked some time ago. Let $X$ be a smooth projective variety of dimension $n$ over $\mathbb{C}$. Let $\omega \in H^{n}(X,K_X)$, $\omega \neq 0$. Let $$A ...
Libli's user avatar
  • 7,300
1 vote
1 answer
186 views

Comparing self-equivalences of a triangulated category and automorphisms of its Grothendieck group

There is a homomorphism from the group of (isomorphism classes of) self-equivalences of a triangulated category to the automorphism group of its Grothendieck group. Is this homomorphism surjective? If ...
მამუკა ჯიბლაძე's user avatar
1 vote
1 answer
197 views

Generating $K^b(\mathrm{proj})$ as a triangulated category from a full subcategory

Let $K^b(\mathrm{proj}\, A)$ be the bounded homotopy category of chain complexes over $\mathrm{proj}\, A$. In Rickard's paper 'Derived categories and stable equivalence', he defines a tilting complex ...
Iteraf's user avatar
  • 482
1 vote
0 answers
54 views

Extending a natural transformation using a distinguished triangle

$\require{AMScd}$ Let $\mathcal{T}$ be a triangulated category, and $\mathcal{S}$ a full subcategory of $\mathcal{T}$ (which is not triangulated). Let $F, G: \mathcal{T} \to \mathcal{T}$ be two ...
Injective's user avatar
6 votes
1 answer
377 views

Subcategories of the Verdier quotient?

Let $\mathcal T$ be a triangulated category and $\mathcal C$ a thick triangulated subcategory. We consider the Verdier quotient $\mathcal T/\mathcal C$. Is there a bijective correspondence between ...
Triangulated's user avatar
1 vote
0 answers
100 views

Are mapping cones in the bounded homotopy category of chain complexes isomorphic?

Let $A$ be an additive category. Suppose we have distinguished triangles $$X \rightarrow Y \rightarrow Z \rightarrow X[1]$$ and $$X \rightarrow Y \rightarrow Z' \rightarrow X[1]$$ in the bounded ...
Iteraf's user avatar
  • 482
1 vote
1 answer
158 views

How to get that one module is tilting iff the other one is?

Let $A$ be an algebra over a field k. $D$ is the standard duality functor. A module $_AM$ is called a generator if $add(A) \subseteq add(M)$, a cogenerator if $add(D(A)) \subseteq add(M)$. $M$ is n-...
Xiaosong Peng's user avatar
5 votes
0 answers
520 views

Spectral sequences coming from filtrations (Postnikov systems) in triangulated categories: references and convergence

Let $c^i: M^{\ge i+1}\to M^{\ge i}$ for $i\in \mathbb{Z}$ be an sequence of morphisms in a triangulated category $C$ and assume that $M^{\ge i}$ are equipped with compatible morphisms into an object $...
Mikhail Bondarko's user avatar
4 votes
1 answer
314 views

A characterization of distinguished triangles in triangulated categories.

Let $\mathscr{D}$ be a triangulated category. Let $$X \longrightarrow Y \longrightarrow Z \longrightarrow X[1]$$ be a triangle (not necessarily distinguished). We call it special if for each $E \in \...
user104320's user avatar
9 votes
0 answers
499 views

On the definition of triangulated categories

Triangulated categories were introduced in the 1960s by Grothendieck and Verdier in order to develop homological algebra in the framework of derived categories. An example of a triangulated category ...
ACL's user avatar
  • 12.9k
5 votes
2 answers
998 views

On various relations between "additional axioms" for AB4 and Grothendieck abelian categories

Let $A$ be an abelian category that has a generator and satisfies the AB4 axiom. I would like to understand (better) the relations between various additional "restrictions" on $A$. So here is my list ...
Mikhail Bondarko's user avatar
5 votes
1 answer
370 views

Which triangulated categories are subcategories of compact objects "somewhere"?

Let $T$ be a small triangulated category. Under which conditions there exists a triangulated category $B$ closed with respect to (small) coproducts such that $T$ fully embedds into the subcategory of ...
Mikhail Bondarko's user avatar
3 votes
2 answers
304 views

Examples of $1$-Calabi-Yau triangulated categories

Can you give me examples of $1$-Calabi-Yau triangulated categories $D$ different from the bounded derived category of coherent sheaves on an elliptic curve? I would like moreover the numerical ...
user97971's user avatar
25 votes
2 answers
1k views

Complete the following sequence: point, triangle, octahedron, . . . in a dg-category

Let $\mathcal C$ be a pre-triangulated dg-category (or a stable $\infty$-category, if you wish). An object $X$ in $\mathcal C$ gives a "point": $$X$$ A morphism $X\xrightarrow f Y$ in $\mathcal C$ ...
John Pardon's user avatar
  • 18.7k
6 votes
1 answer
274 views

Switching left and right adjoints in recollement situations

In Fascieaux pervers, Beilinson, Bernstein and Deligne define a recollement situation as a triple of triangulated categories $\mathcal{D}_U,\mathcal{D}_F$ and $\mathcal{D}$, together with functors $$ ...
domenico fiorenza's user avatar