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Questions tagged [finite-fields]

A finite field is a field with a finite number of elements. For each prime power $q^k$, there is a unique (up to isomorphism) finite field with $q^k$ elements. Up to isomorphism, these are the only finite fields.

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Quadratic forms with the same roots over GF(2) for low rank problems

Let $Q_1(x)=x^TA_1x$ and $Q_2(x)=x^TA_2x$ with $x\in GF(2)^n$, $A_i\in GF(2)^{n\times n}, i \in \{1, 2\}$. If $rank(A_1)=rank(A_2)=2$, is it possible that $Q_1(x)$ and $Q_2(x)$ can have the same roots ...
Fabio Dias's user avatar
5 votes
1 answer
432 views

Number of roots of a quadratic form over GF(2)

If $Q(x) = x^T A x$ with $x \in GF(2)^n$ and $A \in GF(2)^{n \times n}$, is there a way to find how many roots $Q(x)$ has based on any properties of $A$ (e.g., rank, etc.)?
Fabio Dias's user avatar
4 votes
0 answers
108 views

Differential duality: Triangular codes vs. VT codes / Single-substitution vs. Single-deletion

Here is the introduction to my problem: Codes correcting single-deletion. Let $q$ and $n$ be non-negative integers, and let $\mathbf{x}= \left ( x_{1}, x_{2}, \ldots, x_{n} \right )\in\mathbb{Z}_{q}^{...
winogradd_15's user avatar
0 votes
0 answers
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Solution modulo $9$ of certain linear equation implies triviality modulo $3$

Question: Let $k \geq 2$ and $r \geq 4$ be two natural numbers. We are given eight integers $\nu_{ij} \geq 0$ for every $1 \leq i \leq k$ and $1 \leq j \leq r$ such that the following two conditions ...
HumbleStudent's user avatar
-1 votes
0 answers
73 views

Why is there in theory no morphism/isogenies when enlarging a prime field sharing a common suborder/subgroup? [closed]

Simple question : I have a prime field having modulus $p$ where $p−1$ contains $O$ as prime factor, and I have a larger prime field $q$ also having $O$ as its suborder/subgroup. Why are there no ...
user2284570's user avatar