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On the definition of regular (non-noetherian, commutative) rings

All rings are commutative with unit. A ring $R$ is called regular if it satisfies (Reg) Every finitely generated ideal of $R$ has finite projective dimension. Clearly this gives the usual ...
Laurent Moret-Bailly's user avatar
15 votes
0 answers
720 views

If a polynomial ring is a finite flat module over some subring, is that subring itself a polynomial ring?

A question motivated by If a polynomial ring is a free module over some subring, is that subring itself a polynomial ring? and If a polynomial ring is finite free over a subring, is the subring ...
Zhiyu's user avatar
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14 votes
0 answers
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Is there a slick proof of the fundamental theorem of dimension theory?

The fundamental theorem of dimension theory in commutative algebra states that given a module $M$ over a noetherian local ring $A$, we have $s(M)=\text{dim}(M)=d(M)$ (where $s(M)$ is the infimum of ...
display llvll's user avatar
13 votes
0 answers
474 views

Refinement of concept of support of a module

My rings are commutative and noetherian. The support of a module is usually defined to be the set of prime ideals of the ring such that localization at that prime does not make the module zero. This ...
Ben Wieland's user avatar
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5 votes
0 answers
288 views

Picard group of almost module category

I am very new to the world of almost mathematics and I am curious about the following: Fix an almost mathematics situation $(R,I)$ throughout. Very generally, the almost module category comes with a ...
QYB's user avatar
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5 votes
0 answers
232 views

Coherence of the monoid algebra of a non-finitely generated monoid

Let $P$ be an integral, sharp, finitely generated commutative monoid (say even torsion-free and saturated if you like), and consider the "rational cone" $P_\mathbb{Q}\subseteq P^{gp}\otimes_\mathbb{Z}...
Mattia Talpo's user avatar
  • 1,030
5 votes
0 answers
331 views

Extensions of maps between graded modules

Let $R$ be a connected graded ring (like $R=\mathbb R[x_1,\dots,x_d]$ with the usual grading) and let $N \subset R^{\oplus n}$ be a graded submodule, i.e. $$N= \bigoplus_{i \in \mathbb N} (N \cap R^{\...
Andreas Thom's user avatar
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4 votes
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218 views

derived symmetric powers of an ideal

Let $R$ be the polynomial algebra in $n$ variables over a field $F$ of characteristic $0$. Let $m$ be the ideal of the origin: $m=(x_1,...,x_n)$. We have a canonical map $Lsym^k(m)\to m^k$ from the ...
S. carmeli's user avatar
  • 4,189
4 votes
0 answers
74 views

self-cogenerator rings

Let $\mathbb{U}$ be a non-empty set (class) of objects of a category $C$. An object $B$ in $C$ is said to be cogenerated by $\mathbb{U}$ or $\mathbb{U}$-cogenerated if, for every pair of distinct ...
e.r's user avatar
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3 votes
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271 views

Explanation for devissage argument

Let $K$ be a local field of characteristic $0$ with the ring of integers $\mathcal{O}_K$ and uniformizer $\pi$. Let $k$ be the residue field of $K$ with $\text{card}(k)=q$. Let $\mathcal{O}_\mathcal{E}...
user89236's user avatar
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204 views

Yoneda extension and splittings

Let $X$ be a non-singular algebraic variety and $F$ be a coherent sheaf defined over $X$. Suppose that we have a locally free resolution $$0 \to L_n \xrightarrow{f_n} L_{n-1} \to ... \to L_0 \to F \to ...
Ron's user avatar
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3 votes
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240 views

Smallest non-vanishing index of Local-Cohomology and Ext functor, as in the definition of depth, for not necessarily affine schemes

Let $(Z,\mathcal O_Z)$ be a closed subscheme of a Noetherian scheme $(X,\mathcal O_X)$. Then there is an ideal sheaf $\mathcal J$ on $X$ such that $i_*(\mathcal O_Z) \cong \mathcal O_X/\mathcal J$ , ...
sdey's user avatar
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3 votes
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175 views

Geometric interpretation of homological quantities in Artinian local Gorenstein algebras

By corollary 3.5. of http://www.ams.org/journals/tran/2012-364-09/S0002-9947-2012-05430-4/S0002-9947-2012-05430-4.pdf the classification of local artinian Gorenstein algebras (all algebras here are ...
Mare's user avatar
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3 votes
0 answers
450 views

Ext groups of affine scheme

Let $A$ be a commutative ring. $\textbf{Spec}(A)$ is the the spectrum of $A$. $M$ and $N$ are $A$-modules. $\tilde{M}$ and $\tilde{N}$ are sheaves associated on $\textbf{Spec}(A)$ respectively. I ...
sife's user avatar
  • 491
2 votes
0 answers
124 views

Generalization of Koszul cohomology for wedge product with a fixed q-form: literature and references?

Let $A$ be a commutative ring. For an odd positive integer $q$ and an integer $p$ in the range $1 \leq p \leq q$, consider the cochain complex: $0 \to \Lambda^p(A^N) \to \Lambda^{p+q}(A^N) \to \cdots \...
user47660's user avatar
2 votes
0 answers
128 views

On the generalization of a Cech-to-sheaf type spectral sequence

Let $(X,O_{X})$ be a ringed space and $\mathcal{F^{\bullet}}$ be a bounded below complex of $O_{X}$-modules on $(X,O_{X})$. On [Stacks Project 20.25.1][1] it is shown that there is a weakly convergent ...
FPV's user avatar
  • 541
2 votes
0 answers
173 views

de Rham cohomology of a specific ring

I'm running into a certain algebraic de Rham cohomology computation I could use some help with. Specifically, what is the algebraic de Rham cohomology of: $$ \mathbb{C}[x_1,\dots,x_n,y_1,\dots,y_n,(r^...
freeRmodule's user avatar
  • 1,077
2 votes
0 answers
833 views

Applications of Jordan-Holder theorem in an abelian category

The Jordan-Holder theorem says that any chain of subobjects of a finite length object can be refined to a composition series, and that any composition series has the same length. This theorem holds ...
less's user avatar
  • 129
2 votes
0 answers
325 views

A question on direct limits of rings, and descent of ideals

Motivated by an étale cohomology calculation I am going to do, here is a question that should have positive and not too hard answer. Let $A$ be a ring, $A_0$ a ring such that $A_0$ is equipped with ...
user avatar
2 votes
0 answers
868 views

depth of ideal in polynomial ring

Let $R$ be a Noetherian local ring. Then the "depth" of an ideal $I$ measures the maximal length of regular sequence inside $I$. And $depth (R/I)$ measures the maximal length of regular sequence in ...
dongrugose's user avatar
1 vote
0 answers
132 views

A question concerning cancellation of ideals

I am working on a number theory project, and at one stage, I encounter a commutative algebra problem. Vaguely speaking, my hope is to show that two ideals are equal. Now I shall explain the data I am ...
BenjaminY's user avatar
1 vote
0 answers
111 views

Kunneth formula for hypercohomology

Let $A_{\bullet}$ and $B_{\bullet}$ be two bounded complexes of sheaves over a variety $X$. Is there a Kunneth-like formula for the hypercohomology of the tensor product $A_{\bullet}\otimes B_{\bullet}...
S.D.'s user avatar
  • 494
1 vote
0 answers
140 views

On finite dimensional commutative algebras and regular sequences

Let $\mathbb{C}[u]:= \mathbb{C}[u_1,...,u_n]$ the algebra of polynomial functions on $\mathbb{C}^n$. I consider two ideals $I$, and $J$, where $I$ is the ideal generated by the polynomials vanishing ...
BrianT's user avatar
  • 1,227
1 vote
0 answers
74 views

On some finiteness properties of cohomological algebras of complex tori

Denote by $A := \mathbb{C}[u,u^{-1}]$, $u = (u_1,...,u_n)$, the algebra of polynomial functions on the complex torus $(\mathbb{C} \setminus \{ 0 \})^n$, which we consider as a $\mathbb{C}[u]$-module. ...
BrianT's user avatar
  • 1,227
1 vote
0 answers
113 views

Reference request. The adjunction $\hom_{CDGA}(\Omega^\bullet(A),B^\bullet)\cong\hom_{CA}(A,B^0)$

We have the adjunction $$\hom_{CDGA}(\Omega^\bullet(A),B^\bullet)\cong\hom_{CA}(A,B^0)$$ where $CDGA$ is the category of commutative diffferential graded algebras and $CA$ is the category of ...
Fallen Apart's user avatar
  • 1,615
1 vote
0 answers
135 views

Relation of primary decomposition of two ideals

I have a simple question: Let $R=\mathbb{C} \lbrace t,u \rbrace$ be the ring of formal series in two variables. Let $I,J \subset R$ ideals of heigth one, and $I \subset J$. What is the relation of the ...
Otoniel Silva's user avatar
0 votes
0 answers
168 views

Theorems related to Chevalley's theorem

Recently I have read Chevalley's theorem of a complete local ring which basically says that if $(R,\mathfrak{m})$ is a complete local ring and if $\{b_n\}$ be a sequence of ideals such that $b_n \...
Kishor Kumar's user avatar
0 votes
0 answers
132 views

Example of a periodic free resolution over a hypersurface

I'm reading "HOMOLOGICAL ALGEBRA ON A COMPLETE INTERSECTION, WITH AN APPLICATION TO GROUP REPRESENTATIONS" by David Eisenbud I'm wondering what would be a nice example illustrating Theorem 6....
It'sMe's user avatar
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