Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options answers only not deleted user 763

A Hilbert space $H$ is a real or complex vector space endowed with an inner product such that $H$ is a complete metric space when endowed with the norm induced by this inner product.

1 vote

Range of a Certain Linear Operator

This looks a bit like it could be a H/W exercise, but having started to type something up I might as well give most of it. I'm assuming all your functions are real-valued, since otherwise your form is …
Yemon Choi's user avatar
  • 25.8k
2 votes

Is there a use for a Hilbert space that uses a different norm than the one induced by the in...

Firstly, a Hilbert space is complete: the $l^1$-norm is defined on a dense subspace of $l^2$ but not on the whole space. Secondly, if you can equip $l^2$ with another norm, then either this norm is in …
Yemon Choi's user avatar
  • 25.8k
8 votes
Accepted

is a non-invertible operator a boundary point of the group of invertible operators?

This is true if $0$ belongs to the boundary of the spectrum of $T$ (more or less from the definition of the spectrum) but fails in general. The unilateral left shift $S: \ell^2({\mathbb N})\to\ell^2({ …
Yemon Choi's user avatar
  • 25.8k
3 votes

Bounded operators leaving dense subspace invariant

The following is based on a copy of some old handwritten notes; I haven't had time to refresh my memory on all the details. I will try to fill in these details in the next day or so. $\newcommand{\Nat …
Yemon Choi's user avatar
  • 25.8k
1 vote

Simultaneous time-frequency concentration of orthonormal sequences?

The Fourier transform on $L^2({\mathbb R})$ has an complete set of eigenvectors (that is, there is an o.n. basis of $L^2({\mathbb R})$ consisting of eigenfunctions for the FT, and they are all in the …
Yemon Choi's user avatar
  • 25.8k
1 vote

Abelianization of GL(H)

I agree with Eric's belief, albeit for a "cheat" reason: if the abelianization were non-trivial then you'd get a notion of determinant for GL, and that seems unlikely to me. For what it's worth, acco …
Yemon Choi's user avatar
  • 25.8k
4 votes

A homeomorphism between the unit interval $[0,1]$ and a linearly independent subset of a Hil...

In a different direction from Yves Cornulier's suggestion: how about something based on Cauchy kernels as elements of Hardy space? I'm writing this off the top of my head so I might not be taking the …
Yemon Choi's user avatar
  • 25.8k
7 votes
Accepted

Fell's trick for Lie groups

Fell absorption works for all locally compact groups and all strongly continuous unitary representations; the intertwining map that you give in the discrete case can be generalized to $$ W: L^2(G)\ot …
Yemon Choi's user avatar
  • 25.8k
2 votes
Accepted

A reproducing kernel Hilbert space

A useful test case for RKHS (which is not like the interesting examples, but does satisfy the definitions) is $\Omega={\mathbb N}$ and $H=\ell^2({\mathbb N})$. Note that $\hat{k_n}$ is just the usual …
Yemon Choi's user avatar
  • 25.8k
7 votes
Accepted

When are finite-dimensional representations on Hilbert spaces completely reducible?

I don't know about Q1 off the top of my head, but I think that for Q2 you are unlikely to get a good answer. Of course I may have a different view from you as to what "mild" adjectives are reasonable …
Yemon Choi's user avatar
  • 25.8k
8 votes

Matrices Representing Bounded Operators and Absolute Values

As requested, I've moved my comments to an answer. The question is equivalent to the following: Suppose that a doubly-infinite matrix $A=(A_{ij})_{i,j\in {\bf Z}}$ represents a bounded hermitian …
Yemon Choi's user avatar
  • 25.8k
6 votes
Accepted

What is the orthonormal basis for the Bergman space on the disk?

Assuming that we normalize so that the area of the unit disc is $\pi$, take $f_n(z) = \sqrt{\frac{n+1}{\pi}} z^n$ for $n=0,1,2,\dots$ to get an orthonormal basis.
3 votes

Approximately complemented subspaces

Iosif Pinelis has given a direct argument, but if you are studying approximate complementation in more general Banach spaces then the following argument might be of interest. In Zhang's original pape …
Yemon Choi's user avatar
  • 25.8k