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Complex, contact, Riemannian, pseudo-Riemannian and Finsler geometry, relativity, gauge theory, global analysis.
6
votes
Accepted
Pseudoholomorphic vector fields
I can give you a partial answer- a reformulation of your question. Perhaps others will then be able to give a counterexample. (I think it is not true in general.) Let's start from the beginning.
A ma …
4
votes
Accepted
$L^2$ Hodge cohomology of ALE manifolds
I believe you can find this in the papers of Lockhart and McOwen. Specifically, check
Lockhart, Robert B.; McOwen, Robert C. Elliptic differential operators on noncompact manifolds. Ann. Scuola Norm. …
2
votes
norm of $n$-th covariant derivative of smooth function
If $A$ is any section of a vector bundle $E$ over a smooth manifold $M$ and if $\nabla$ is any covariant derivative on $E$, then $\nabla A$ is a section of $T^*M \otimes E$, and this has a natural (po …
1
vote
Accepted
Hodge decomposition of a symplectic form.
Using the additional information that the OP provided in the comments to Yael Fregier's answer, I can elaborate as follows:
I still don't know what "special complex manifold" means, but in any case, …
4
votes
Accepted
Paper about Sasaki-Einstein manifolds
Well, now there is a great textbook for Sasaki-Einstein geometry, by Boyer-Galicki: Sasakian Geometry.
Here is a link to the book at Oxford University Press, DOI: 10.1093/acprof:oso/9780198564959.001. …
10
votes
Exterior derivative on almost complex manifolds
Just to follow up on Eric's correct answer: when you have an almost complex structure $J$, you can decompose $1$-forms into type $(1,0)$ and $(0,1)$. Locally, you can find a local basis $e^1, \ldots, …
9
votes
Flux through a Mobius strip
David Speyer already explained it very well. But if you want more details of the explicit calculations, you can look here:
http://www.math.uwaterloo.ca/~karigian/teaching/multivariable-calculus/moebi …
4
votes
Accepted
How else can we describe the volume of a lagrangian submanifold in a Kahler manifold?
This is probably closer in spirit to what you're looking for than what you've received in the comments. If $(V^{2m}, J, \omega, g)$ is Calabi-Yau (which for me means that $J$ is integrable, and the fi …
23
votes
2
answers
6k
views
Why are they called isothermal coordinates?
On a Riemannian manifold, a coordinate system is called "isothermal" if the Riemannian metric in those coordinates is conformal to the Euclidean metric:
$$g_{ij} = e^{f} \delta_{ij}$$
My question is …
22
votes
4
answers
5k
views
What is the best way explain to undergraduates that all 1-dimensional manifolds are orientable?
Let's suppose that $M$ is a connected $1$-dimensional smooth manifold (Haussdorf and paracompact). We know that there are exactly two types, up to diffeomorphism (even up to homeomorphism), namely $\m …
8
votes
reference for Noether's theorem
Another excellent book that does a proper job with Noether's Theorem is Peter Olver's Applications of Lie Groups to Differential Equations.
5
votes
Can a metric conformal to a Kahler metric be Kahler?
The paper by Apostolov, Calderbank, and Gauduchon that Francesco mentions find different Kaehler structures whose associated Riemannian metrics are conformal to each other. But they correspond to diff …
6
votes
book on calabi yau manifolds
I would also add the following book:
Dominic Joyce, Compact Manifolds with Special Holonomy
The early parts of the book include an introduction to the Riemannian geometry of Calabi-Yau manifolds. It …
1
vote
local kählerforms on complex manifold
(I decided to repost multiple comments as an answer. It's partly an answer if I understand the OP correctly.)
I think the OP does not necessarily want to conclude that these "local" forms are the res …
5
votes
Hyper-complex and quaternionic Kähler Geometry
[First paragraph has been edited, after Vitali's comments below.] According to one convention, hyperKahler manifolds are not actually quaternionic-Kahler. This is the case if you define hyperKahler as …