Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 46104

Algebraic varieties, stacks, sheaves, schemes, moduli spaces, complex geometry, quantum cohomology.

3 votes

Does every finite map of smooth varieties birationally embed as a smooth hypersurface of 1d ...

I may have misunderstood something. However my impression is that, since you are asking $Y'$ smooth, the answer is negative. The simplest counterexamples are probably compact Riemann surfaces, since b …
Roberto Pignatelli's user avatar
2 votes

Classification of quartic surfaces

A fine classification of the quartic surfaces that are not normal is in Tohsuke URABE, "Classification of Non-normal Quartic Surfaces", TOKYO J. MATH. VOL. 9, No. 2, 1986, 265-295
Roberto Pignatelli's user avatar
2 votes

Fundamental group of a compact branched cover

Ciao Francesco. The more general version of this Theorem that I know is in Fox, Ralph H. Covering spaces with singularities 1957 A symposium in honor of S. Lefschetz pp. 243–257 Princeton University …
Roberto Pignatelli's user avatar
5 votes
0 answers
335 views

Deformations of a blow up

My question is related to this question, but I'm looking for something a bit more explicit. Let $S$ be a smooth surface over $\mathbb C$, fix a point $s\in S$ and take the blow up $\beta \colon S' \r …
Roberto Pignatelli's user avatar
1 vote
Accepted

The geometric genus under a generically finite to one rational map

Mohan' answer in the comments is correct: this is more a comment to his answer. If you are only interested in the inequality you do not need Riemann-Hurwitz formula as I will explain in the following …
Roberto Pignatelli's user avatar
4 votes
Accepted

equations for a bidouble cover

As abx note in the comments, you miswrote the equations. Still the singular point remains. The point is that the "reduced" data works well algebraically, as indeed you can deduce $L_3$ from the othe …
Roberto Pignatelli's user avatar
1 vote

Automorphisms of Cartesian products

This is true under the assumption you suggest, $X$ of general type, when $X$ is a curve. In the simplest case $r=2$, Corollary 3.9 of this paper of Catanese gives that $Aut(X^2)$ is the semidirect pr …
Roberto Pignatelli's user avatar
5 votes
Accepted

Will any two linearly equivalent ample divisors on an abelian variety intersect?

Of course not. If $L$ is very ample, $D_1$ and $D_2$ are two hyperplane sections for some embedding in a projective space. Therefore their intersection is at most codimension 2 in $X$, intersection o …
Roberto Pignatelli's user avatar
2 votes
Accepted

Global sections of coherent sheaves on determinantal hypersurfaces in $\mathbb{P}^n$

This is meant to be an integration to Yusuf answer. Consider a section $$ \stackrel{\rightarrow}{\alpha}= \begin{pmatrix} \alpha_1\\ \vdots\\ \alpha_r \end{pmatrix} \in {\mathbb C}^r\cong H^0({\math …
Roberto Pignatelli's user avatar
2 votes
Accepted

Pullback of line bundles and divisors from $Kum(C)$ to $Jac(C)$

1) is correct, 2) is not. Indeed, if $i(C)=C$, then the map $C \rightarrow C'$ is a double cover, and $f^*{\mathcal O}_Y(C')={\mathcal O}_X(C)$ since in a neighbourhood of a general point of $C$ the …
Roberto Pignatelli's user avatar
1 vote
Accepted

Relation between curves in a complete linear system contained in another

In the following I suppose that by "curve" in a linear system you mean "effective divisor" vithout any claim about being irreducible and/or reduced. 1) Curves in |L'| are exactly the pull-back of cur …
Roberto Pignatelli's user avatar
3 votes
Accepted

On surfaces with $p_g=0$, $q=1$, and $K^2=-3$

Xiao Gang is taking a configuration of six lines in the plane with 4 triple points $x,z_1,z_2,z_3$ and three double points $y_1,y_2,y_3$. He considers a general quartic through the seven points which …
Roberto Pignatelli's user avatar
4 votes

Isotrivial fibrations over $\mathbb P^1$

If the genus of the fibre is not 0, by Theorem 2.1 in Serrano's paper "Fibrations on algebraic surfaces" any isotrivial fibration is birational to $(A \times B)/G \rightarrow B/G$ where $G$ is a finit …
Roberto Pignatelli's user avatar
2 votes
Accepted

Is each rationally chain connected surface rational?

By the comments of abx you only need an answer to question $3$. You get easily an answer if you assume the results in the classical book of Beauville on algebraic surfaces. Namely, if $S$ is uniruled …
Roberto Pignatelli's user avatar
2 votes

Finding an algebraic equation given divisors

abx has already pointed out that your divisors are not the canonical divisors. Still, your (not-so-clear) question was maybe slighlty different, on "how to find the equation"? If I understand your qu …
Roberto Pignatelli's user avatar

15 30 50 per page