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Knot theory is dealing with embedding of curves in manifolds of dimension 3. A knot is a single circle embedded in the affine space of dimension 3 as a smooth curve not crossing itself. Many knot invariants are known and can be used to distinguish knots.

10 votes
Accepted

Counting knots with fixed number of crossings

There are some known exponential bounds on the number. For example, if kn is the number of prime knots with n crossings, then Welsh proved in "On the number of knots and links" (MR1218230) that …
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9 votes

Prime decomposition for knots in manifolds

This was addressed in Miyazaki, Conjugation and the prime decomposition of knots in closed, oriented 3-manifolds, using the definition of connected sum suggested by Ryan Budney in the comments. The m …
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6 votes
Accepted

Surgery along an arc connecting the components of a $2$-component link gives the unknot

One source of restrictions is the Montesinos trick: if you take the branched double cover of $L$, then a small neighborhood of the framed arc lifts to a solid torus because it intersects $L$ in two sm …
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2 votes

{0,1} Maslov potentials on Legendrian knots

I don't have anything close to a complete answer, but for many $tb$-maximizing knots we can get some obstructions from Legendrian contact homology. The generators for the DGA $A(K)$ associated to a g …
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4 votes
Accepted

Why Tristram-Levine signature jumps at the zeros of alexander polynomial?

If $A$ is a Seifert matrix for $K$ and $\omega \in \mathbb{C}$ has norm 1, then the Tristram-Levine signature $\sigma_\omega(K)$ is the signature of the matrix $(1-\omega)A + (1-\bar{\omega})A^T = ( …
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3 votes
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Does tangle closure determine the triviality of the tangle?

The branched double covers $\Sigma(NS(T))$ and $\Sigma(D_+(T))$ are both $S^3$ by assumption, and they're each built by gluing $\Sigma(T)$ to the branched double cover of a different rational tangle ( …
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13 votes
Accepted

Knot theory question: bridge number vs. min generators of fundamental group of complement

The (p,q) torus knot has a presentation with two generators, namely $\langle x,y \mid x^p = y^q\rangle$, but if $p,q>2$ then it's non-alternating and so it must have bridge index greater than 2.
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6 votes

Sliceness of knots

Both $6_1$ and $3_1 \# m(3_1)$ are smoothly slice (as is the unknot), and I claim that all other knots of at most seven crossings are not integrally slice. This will follow from two claims: first, if …
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9 votes
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Which knot complements are double branched covers?

The complements of strongly invertible knots can always be realized as branched double covers of tangles. Torus knots are strongly invertible, so their complements actually do arise in this way. For …
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8 votes
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Are there spaces in which there are no fibered knots?

The answer for knots is still "no", because if you have an open book decomposition with disconnected binding then you can stabilize it (see section 2 of Etnyre's lecture notes) by attaching a handle t …
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11 votes
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Is every quasipositive knot strongly quasipositive?

As pointed out by Hedden, Livingston showed that strongly quasipositive knots have $g(K) = g_4(K) = \tau(K)$, where $g_4$ is the smooth slice genus and $\tau$ is the Ozsváth-Szabó concordance invarian …
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5 votes
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Distinct knots with same $A$-polynomial

The torus knots $T_{7,15}$ and $T_{3,35}$ have the same A-polynomials. In general, if $p,q>1$ are coprime and odd then $T_{p,q}$ has A-polynomial $(L-1)(LM^{pq}+1)(LM^{pq}-1)$, which only depends on t …
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18 votes

Is Murasugi's conjecture still open?

It's actually a conjecture of Fox, sometimes known as the trapezoidal conjecture: the absolute values of the coefficients of $\Delta_K(t)$ are nonincreasing if K is an alternating knot. I think the o …
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13 votes
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$0$-surgeries on trefoil and figure-eight

If you're happy bringing in heavy machinery then you could compute some sort of Floer homology, like the 'hat' version of Heegaard Floer homology: this has rank 2 for $S^3_0(3_1)$ and rank 4 for $S^3_ …
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16 votes
Accepted

What is Floer homology of a knot?

I can say something about this for Heegaard Floer homology. Given a 3-manifold Y, you can take a Heegaard splitting, i.e. a decomposition of Y into two genus g handlebodies joined along their boundar …
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