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Riemann surfaces(Riemannian surfaces) is one dimensional complex manifold. For questions about classical examples in complex analysis, complex geometry, surface topology.
15
votes
Area of a smooth complex projective curve
A much more general result is given by Mumford, in Projective varieties I, Theorem 5.22: the volume of any $r$-dimensional smooth projective variety in $\Bbb{P}^N$ (the area in your case) is its deg …
5
votes
Accepted
Existence of a holomorphic map between Riemann surfaces
I think this is what Picard says, translated in modern algebraic geometry language:
You have a curve $X$ with a map $\pi :X\rightarrow \mathbb{P}^1$.
Assume for simplicity that for each $z\in \mathbb{ …
1
vote
Accepted
operations on matrices preserving the property of being the Riemann matrix of a surface
No, this is not true. If $C$ is a general curve of genus $\geq 4$ with period matrix $\Omega$ and $p$ is a prime, $p\Omega$ is not the period matrix of a curve. This is proved (in an equivalent, more …
4
votes
Paths $tg_1+(1-t)g_0$ in the moduli space of Riemann surfaces
Answering your PS: as you point out, the complex structure $J_t$ is given in each coordinate chart by a matrix which depends real-analytically on $t$. Now you can find a neighborhood $U$ of $[0,1]$ i …
7
votes
Accepted
Branched covers of the sphere branched over few points
Let me post my comment as an answer. Take a Weierstrass point on $X$, that is, a point $P$ for which there exists a meromorphic function $f$ with a pole of order $k\leq g$ at $P$ (there always exist …
4
votes
Accepted
Extended Abel-Jacobi theorem
This is true. Given two points $a,b\in X$ with $u(a)$ and $u(b)\neq 0$, one can choose a path from $a$ to $b$ and a determination of $\log u$ along that path, so that $\exp\int^b_a d\log u=u(b)/u(a)$. …
10
votes
Accepted
Stable extensions by line bundles on Riemann surfaces
This never happens. Pick a point $p\in X$; the exact sequence $0\rightarrow L^{2}\rightarrow L^{2}(p)\rightarrow \mathbb{C}_p\rightarrow 0$ gives rise to an exact sequence $0\rightarrow \mathbb{C}\x …
3
votes
Accepted
Symplectic representation of modular group
For your last question: the map from the hyperelliptic modular group to $\operatorname{Sp}(2g,\mathbb{Z}) $ is not surjective as soon as $g\geq 3$. This was proved by V. Arnold,
A remark on the branc …
3
votes
Accepted
Jacobians of twisted coverings
They are not isogeneous in general. For an explicit example, take the case $n=0$ and $C$ hyperelliptic, so that we have a double covering $C\rightarrow \mathbb{P}^1$ branched along a subset $B$ of $\m …
14
votes
Accepted
Quotients of curves of genus $4$ by a free $\mathbb{Z}/ 3 \mathbb{Z}$-action
Yes. Start from a genus 2 curve $C_2$, and choose a point of order 3 in $JC_2$, giving rise to an étale $\mathbb{Z}/3$-covering $C_4\rightarrow C_2$.
Then $C_4$ cannot be hyperelliptic: a $g^1_2$ on …
6
votes
Accepted
Moduli of stable bundles - analytic approach
$\mathcal{M}$ is what is called a coarse moduli space. In concrete terms, this means the following:
1) As a set, $\mathcal{M}$ can be viewed as the set of isomorphism classes of stable bundles (of r …
5
votes
Rational functions on hyperelliptic Riemann surface
Yes (the answer was given, then deleted, by Francesco Polizzi). If $D$ and $D'$ are the divisors of zeroes (resp. poles) of a rational function, the linear system $|D|$ has dimension $r\geq 1$ and is …
2
votes
Finding an algebraic equation given divisors
If I understand correctly your question (?), you want a smooth curve $C$ of genus 5 and 3 holomorphic forms $\omega _i$ with the divisors you have written down, satisfying $\ (\omega_1^2 - \omega_2^2 …
1
vote
Any no-zero homomorphism of holomorphic vector bundles over a compact Riemann surface factor...
Let $V_2$ be the image of $f:V\rightarrow W$; it is a subsheaf of $W$, hence locally free. Let $W_2$ be the quotient of $W/V_2$ by its torsion subsheaf, and let $W_1$ be the kernel of the projection …
7
votes
Accepted
Image of the map induced on homology by a covering
No, this is already false if $\pi $ is a Galois covering (i.e. $Y\cong X/G$): the index is the order of the abelianized group $G_{ab}$. Indeed from the exact sequence
$$\pi _1(X)\rightarrow \pi _1(Y)\ …