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Algebraic varieties, stacks, sheaves, schemes, moduli spaces, complex geometry, quantum cohomology.

18 votes
1 answer
810 views

Cohomology of real analytic coherent sheaves

Let $M$ be a real analytic variety (if someone is concerned about distinction between "real analytic spaces" and "real analytic varieties" in real analytic geometry, let's assume that $M$ is both "va …
Misha Verbitsky's user avatar
13 votes
Accepted

Action of automorphisms of a $K3$ surface on its $(-2)$-curves

The group of symplectomorphisms $Aut(X)$ of a K3 is the group $O(\Lambda)$ of automorphisms of its period lattice $\Lambda=H^{1,1}(M,{\Bbb Z})$. For each (-2)-cohomology class $\eta\in H^{1,1}(M,{\B …
Misha Verbitsky's user avatar
13 votes
1 answer
642 views

Does a resolution of a rational singularity have rationally connected fibers?

A rational singularity is a singularity of a complex variety $X$ such that for any resolution $\pi:\; \tilde X\rightarrow X$ the higher direct images $R^i\pi_*(O_{\tilde X})$ vanish for all $i>0$. Sup …
Misha Verbitsky's user avatar
12 votes
Accepted

Deformations of Kähler manifolds where Hodge decomposition fails?

This is known, for projective (even Moishezon) manifolds as shown by Dan Popovici in his paper http://arxiv.org/abs/1003.3605 For general Kaehler manifold, this is conjectured. Popovici has proved t …
Misha Verbitsky's user avatar
9 votes
Accepted

Different occurences of the word 'period' in algebraic geometry

The second and the third are pretty much equivalent. Indeed, "the period" in XIX century sense is essentially the same as the discrepancy between the branches of a multi-valued function, obtained as a …
Misha Verbitsky's user avatar
8 votes

moduli spaces are kahler?

The corresponding Kahler metric is called "Weil-Petersson metric"; it is often constructed using infinite-dimensional determinants of the corresponding Laplace operators. The standard reference is a s …
Misha Verbitsky's user avatar
8 votes
Accepted

What is the moduli of an algebraic torus

There is just no definition of the moduli for complex structures on non-compact manifolds, but by any reasonable definition, it would be (generally) very bad space, certainly infinite-dimensional. For …
Misha Verbitsky's user avatar
8 votes

Coincide between Chern-connection and Levi-Civita connection

It is easier to prove this result for 1-forms, instead of vector fields. On (1,0)-forms, $\nabla^{0,1}=\bar\partial$ because the Levi-Civita connection is torsion-free, hence $\bigwedge(\nabla(\eta))= …
Misha Verbitsky's user avatar
8 votes
Accepted

Proper family deformation retracts onto special fiber

Here is the reference: Persson, Ulf, On degenerations of algebraic surfaces, Mem. Amer. Math. Soc. 11 (1977), no. 189. Clemens, C. H. Degeneration of Kähler manifolds. Duke Math. J. 44 (1977), no. …
Misha Verbitsky's user avatar
8 votes
2 answers
901 views

Gorenstein varieties: why the two definitions are equivalent?

There are two definitions of Gorenstein singularities in the literature. Using Grothendieck's (or Serre's) duality, one defines the "dualizing sheaf" an object $\hat K_M$ of derived category of cohere …
Misha Verbitsky's user avatar
7 votes
Accepted

Finiteness of De Rham cohomology of smooth quasi-projective varieties

I think there are proofs which are much easier. For example, you can try to compute the cohomology using the Morse theory. For that you need existence of Morse functions having finitely many critical …
Misha Verbitsky's user avatar
7 votes
Accepted

Is the generic deformation of a symplectic variety affine?

Being "affine" in this case does not make much sense, because the hyperkaehler deformation is a complex manifold, without a fixed algebraic structure. Simpson produced an example of a hyperkaehler …
Misha Verbitsky's user avatar
7 votes
Accepted

"Simple" Kahler manifolds

A generic deformation of a Hilbert scheme of K3 and a generic torus have no subvarieties, hence they are "simple" in the above sense. For a torus it's well known, for a Hilbert scheme of K3 it's in my …
Misha Verbitsky's user avatar
7 votes

Complex manifolds whose tangent and cotangent bundles are isomorphic as complex vector bundles

There are many such examples, for instance, all complex nilmanifolds (and most complex solvmanifolds) have tangent bundle which is topologically trivial. The Hopf manifolds also have topologically tri …
Misha Verbitsky's user avatar
7 votes
0 answers
250 views

K3 surfaces with no −2 curves

I seem to remember that a K3 surface with big Picard rank always has smooth rational curves. This question is equivalent to the following question about integral quadratic lattices. Let us call a vect …
Misha Verbitsky's user avatar

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