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Questions about the branch of algebra that deals with groups.

11 votes
Accepted

Does every cancellative duo semigroup embed into a group?

Let $S$ be a cancellative duo semigroup. Let $a,b\in S$ be arbitrary, and consider the element $x:=ba$. Clearly, $x\in Sa$ and by the duo property $x\in bS=Sb$. Thus, $S$ is right reversible, and s …
Pace Nielsen's user avatar
  • 18.7k
28 votes
2 answers
849 views

$A^2$ is isomorphic to $A^{(\omega)}$, but not $A$

Is there an abelian group $A$ with $A\not\cong A\oplus A\cong A\oplus A\oplus A\oplus\cdots$ (a direct sum of countably many copies of $A$)? Edited to add: As no answers are forthcoming, does anyone …
4 votes

Is orientability a miracle?

(Just a long comment that doesn't directly answer the bold question, but does [I hope] address an implicit question.) What I've found fascinating in thinking about your answer from that other thread …
LSpice's user avatar
  • 12.9k
15 votes

Conceptual reason why the sign of a permutation is well-defined?

There are already plenty of other great answers, but I figured I might as well give my own. My approach is to introduce students to permutations by taking plastic cups that have large numbers on them, …
Pace Nielsen's user avatar
  • 18.7k
11 votes

What is the standard 2-generating set of the symmetric group good for?

I've had occasions where I needed to know that some structure is "closed" under $S_n$. It is very convenient to only check that it is closed under those two, specific permutations. Afterwards, I can …
Pace Nielsen's user avatar
  • 18.7k
8 votes
1 answer
1k views

First isomorphism theorem for sets?

Let $f\colon S\to T$ be any function. There is the obvious refinement of $f$, by replacing the codomain $T$ with the image. Thus, every function factors into a surjection followed by an injection (a …
5 votes
Accepted

Integral monoid rings and Ore conditions

Let $s\in S$ and $r\in \mathbb{Z}[S]$. We can then write $r=\sum_{i=1}^{n}\alpha_i t_i$ for some $\alpha_{i}\in \mathbb{Z}$ and some $t_i\in S$. The left Ore condition on $S$ implies that there exist …
Pace Nielsen's user avatar
  • 18.7k
10 votes
Accepted

Is every finitely-presentable group a finite colimit of copies of $F_2$?

I believe the answer is yes. Assume, by way of contradiction, that some finitely presented group cannot be so expressed. Then we can choose such a group $G$ where for any generating set of the form …
YCor's user avatar
  • 63.9k
4 votes
Accepted

In the von Neumann–Bernays–Gödel axiomatic system, the Axiom of Transposition can be simplified

I believe that your intended question was something along the lines of whether or not the standard axioms can be simplified or reduced. This is in the spirit of Exercise 13.4 in Jech's "Set Theory", …
Pace Nielsen's user avatar
  • 18.7k
5 votes
0 answers
625 views

Unique product groups (and semigroups)

A group $G$ is called a u.p.-group (short for unique product group) if for all nonempty finite subsets $A,B\subseteq G$, there exists an element $g\in A \cdot B$ which can be uniquely written as a pro …
4 votes

Finding a compatible multiplication for a given group

First, let's deal with the case when $(G,+)$ is finitely generated. By the fundamental theorem of finitely generated abelian groups, let's go ahead and assume that $G$ is given to us in the form $\bi …
Pace Nielsen's user avatar
  • 18.7k
11 votes
2 answers
568 views

Identifying a group without 2-torsion

Suppose we have a finitely presented group $G$ with solvable word problem. (For instance, the command RWSGroup in Magma terminates giving us a finite [but possibly gigantic] rewrite system.) Is there …
3 votes

Jacobson radical of group algebra

More generally, let $k$ be any field, let $K/k$ be any separable algebraic extension, and let $R$ be any $k$-algebra. Then $J(K\otimes_k R)=K\otimes_k J(R)$. [See Theorem 5.17 in Lam's "First Course …
Pace Nielsen's user avatar
  • 18.7k
4 votes
Accepted

presentations of subalgebras

If we modify your first question only slightly, then the answer to the question is no, there is no algorithm. By Theorem 1 of the paper G. Baumslag, W. W. Boone and B. H. Neumann, Some unsolvable pro …
Pace Nielsen's user avatar
  • 18.7k
5 votes
Accepted

A Non-Commutative Nullstellensatz

Let $F$ be a field, and let $f_1,f_2,\ldots, f_k\in R:=F\langle\langle x,y\rangle\rangle$ with $k\in \mathbb{N}$. Order monomials in $R$ by degree, and then lexicographically. Since the question con …
Community's user avatar
  • 1

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