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8
votes
0
answers
217
views
Attractors of arithmetically small points
Consider the "points" to be in $\mathbb{G}_m(\mathbb{C}) = \mathbb{C}^{\times}$. By a sequence of "arithmetically small points" is meant a sequence of pairwise different algebraic points $\beta$ that, …
13
votes
0
answers
582
views
Should the number of small solutions in Roth's theorem be bounded uniformly, assuming the ta...
Consider, on the one hand, algebraic integers $\alpha$ and their rational approximants to within a varying exponent $\kappa > 2$; and on the other hand, smooth projective geometrically irreducible cur …
17
votes
1
answer
702
views
Is there a bounded sequence of points in the plane with pairwise distances at least $1/\sqrt...
Previously I have mentioned the following problem in an addition to the list of Contest problems with connections to deeper mathematics.
Is there an infinite bounded sequence $(P_n) \subset \mathbb{ …
6
votes
0
answers
134
views
Diophantine approximation in $\mathbb{G}_m^r$ with approximants restricted to a finiteley ge...
Faltings, in the same paper (Diophantine approximation on abelian varieties, Ann. Math. 1991) in which he proved his famous ``big theorem,'' proved also that at any place $v$ of a number field $K$ and …
8
votes
Accepted
approximate two different real numbers to order $\frac{1}{z^{3/2}}$
With the constant $1$, this is Minkowski's higher dimensional extension of Dirichlet's approximation theorem:
If $\alpha_1, \ldots,\alpha_n$ are real numbers, then there are rationals $p_i/q$ with $| …
9
votes
Accepted
Is the infimum of Salem numbers > 1?
I believe it is the general opinion, at least among those working in diophantine approximations, that the extreme case of Salem numbers (the question of the title) would be just as difficult as the fu …
13
votes
0
answers
309
views
Diophantine approximation in the Julia set
Let $f : \mathbb{CP}^1 \to \mathbb{CP}^1$ be a rational map of degree $q > 1$; or just a quadratic binomial $z^2 + c$, if one prefers. The Julia set $J_f$ is the closure of the repelling periodic poin …
3
votes
0
answers
149
views
Metric extensions of Littlewood's conjecture
Littlewood's conjecture on simultaneous rational approximation to a pair of real numbers,
$$
\liminf_{n \in \mathbb{N}} \, n \cdot \mathrm{dist}(n\alpha,\mathbb{Z}) \cdot \mathrm{dist}(n\beta, \mathbb …
13
votes
Estimate number of solutions in the Roth's theorem
For a fixed $\alpha$, the number $N_{\alpha}(\epsilon)$ is bounded by a polynomial function of $1/\epsilon$. The proof of this requires either Faltings's product theorem, or Esnault and Viehweg's mult …
3
votes
0
answers
100
views
Independence of number fields generated by roots of Littlewood polynomials
Let $\mathcal{R}_d \subset \bar{\mathbb{Q}}$ be the set of all roots of degree $d$ polynomials with $\{-1,0,1\}$ coefficients and
$$
c(d) := \min_{\substack{ \alpha, \beta \in \mathcal{R}_d \\ \alpha^ …
8
votes
Accepted
On the irrationality measure of $\sum_{n=1}^\infty a^{-b^n}$
This result is due originally to K. Mahler, and holds true more generally with any algebraic $a$ having $|a| > 1$ (so that the series converges absolutely). I can recommend Masser's lecture in the CIM …
3
votes
Counting algebraic points of bounded height
This is true. Choose any linear subspace $Z$ (over $K$) of dimension $n- d-1$ and disjoint from $X$, and take $\pi : \mathbb{P}_K^n \setminus Z \to \mathbb{P}_K^d$ the corresponding linear projection. …