Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options answers only not deleted user 22277

Continuum theory, point-set topology, spaces with algebraic structure, foundations, dimension theory, local and global properties.

1 vote

Can we describe open cover compactness of a space in how the space relates to other spaces?

The Sierpinski topology allows us to reformulate open sets an thus any topological property in terms of continuous functions. The Sierpinski topology is the topology on $\{0,1\}$ where the sets $\empt …
Joseph Van Name's user avatar
20 votes

Why are extremally disconnected spaces so hard to give examples of?

We can always get non-principal ultrafilters on sets from non-discrete extremally disconnected spaces. Let $X$ be a topological space. Let $\text{Clo}(X)$ denote the Boolean algebra of clopen subsets …
Joseph Van Name's user avatar
2 votes

Description of atomless complete Boolean algebras with a countable $\pi$-base

Yes. The complete atomless Boolean algebra with a countable $\pi$-base is unique up to isomorphism. For a proof, we observe that if $B$ has a countable $\pi$-base $A$, then the Boolean algebra $C$ gen …
Joseph Van Name's user avatar
11 votes

Non-trivial convergent sequence in Stone-Čech compactification of $\mathbb{N}$

Let me give a fairly direct proof. Assume $R=(\mathcal{U}_{n})_{n}$ is a sequence of distinct ultrafilters on some set $X$. Since every infinite Hausdorff space has an infinite discrete subspace, ther …
umim.cist's user avatar
2 votes

Compact-open Topology for Partial Maps?

There is a way to promote function space topologies so that convergence of nets behaves the way that one would expect it to behave. There are probably other ways of getting a topology for spaces of pa …
Joseph Van Name's user avatar
5 votes

Does there exist a topological space $X$ such that $X^2$ and $[0,1]$ are homeomorphic?

I can think of a few proofs of the fact that there is no space $X$ with $[0,1]$ homeomorphic to $X^2$. There are probably more proofs in addition to the proofs in the other answers. Proof 1-1: Suppose …
Joseph Van Name's user avatar
7 votes
Accepted

Convergent filters generated by (not necessarily countable) chains

Topological spaces where each point has a totally ordered local basis are known as $\textit{well-based}$ spaces. The notion of a well-based space is a generalization of the notion of a first countable …
Joseph Van Name's user avatar
2 votes

Topological characterisations of properties of posets

Recall that an Alexandrov space is a topological space where the intersection of arbitrary collection of open sets is open. Alexandrov duality states that the category of Alexandrov spaces is equivale …
Joseph Van Name's user avatar
2 votes
Accepted

Homeomorphisms of the projective cover of the Cantor set

I claim that every autohomeomorphism of $M$ is conjugate to an extension of an autohomeomorphism of the Cantor space. Let $B$ be the Stone space of the Cantor space. Let $\overline{B}$ denote its Bool …
Joseph Van Name's user avatar
2 votes
Accepted

Polish space isometric to its hyperspace

It is much easier to deal with zero dimensional spaces and ultrametrics than connected metrics. $\omega^\omega$ with the standard ultrametric is isometrically isomorphic to its own hyperspace. In part …
Joseph Van Name's user avatar
3 votes

Strongly zero-dimensional topological spaces and a simillar condition

What you call a strongly zero-dimensional space is commonly known as an ultranormal space. An ultranormal space is a Hausdorff space where for every pair of disjoint closed sets $C,D$ there is a clope …
PatrickR's user avatar
  • 351
2 votes

Simple proof that downward intersections of simply connected compact sets are simply connected

Several commenters observed that the topologist's sine curve is a non-path connected subspace of $\mathbb{R}^2$ that can be written as an intersection of countably many simply connected spaces. One ca …
LSpice's user avatar
  • 12.9k
4 votes
Accepted

A question about regular closed sets

The answer to both of these questions is Yes. And this result can generalize to point-free topology and I consider this result to be more natural in the context of point-free topology. The following o …
Mehmet Onat's user avatar
  • 1,367
5 votes

Homeomorphic extension of a discrete function

Yes. We can always extend a permutation $f:\{0,1\}^n\rightarrow\{0,1\}^n$ to a homeomorphism $F:[0,1]^n\rightarrow[0,1]^n$ whenever $n\geq 3$ or $n=1$. Proposition: Suppose that $X$ is a connected reg …
Joseph Van Name's user avatar
10 votes

Does every locally compact Hausdorff space admit a locally finite open covering by relativel...

The condition that you are referring to when coupled with local compactness is precisely paracompactness. Not every locally compact space is paracompact as the example of Arthur Fischer illustrates an …
Steven Clontz's user avatar

1
2 3 4 5
11
15 30 50 per page