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The representation of functions (or objects which are in some generalize the notion of function) as constant linear combinations of sines and cosines at integer multiples of a given frequency, as Fourier transforms or as Fourier integrals.

11 votes
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Fourier Coefficients and Hölder Continuity

There is an excellent characterization of Hölder spaces via the Fourier transform, using Besov spaces. Let $\alpha\in (0,1)$: a function $u$ defined on $\mathbb R^n$ belongs to $L^\infty\cap C^\alpha$ …
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3 votes

Is there a function that is not absolutely integrable in [−π,π] so that its Fourier Series E...

All $2π$ periodic distributions are temperate and since all temperate distributions have a Fourier transform, you have plenty of examples. Note that the previous statements prove the power of abstract …
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4 votes
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Fourier Transform: Smoothness and Decay

Your space is some sort of Besov space, containing $B^{2+\epsilon}_{1,\infty}$. Using a Littlewood-Paley decomposition $1=\sum_\nu\varphi_\nu(\xi)$ with $\varphi_0\in C^\infty_c$, $\varphi_\nu(\xi) …
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2 votes

convolution algebra on a compact surface in $\mathbb{R}^3$

The Schwartz space itself, $\mathscr S(\mathbb R^n)$, can be viewed as a subspace of smooth functions defined on the sphere $\mathbb S^n$, the unit sphere of $\mathbb R^{n+1}.$ We recall that $$ \math …
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1 vote
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A question which belongs to a class of Zygmund functions

The standard Zygmund class (with $\epsilon=0$) is the Besov space $ B^1_{\infty,\infty}, $ that is using a Littlewood-Paley decomposition $$ 1=\sum_{\nu\ge 0}\varphi_\nu(\xi),\quad \varphi_\nu(\xi) =\ …
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3 votes
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Asymptotics of a one-parameter family of Schwartz functions

$$ I(\tau)=\int_{\mathbb R}e^{-\pi\frac{\tau}{\pi} x^2}e^{-2i\pi \tau x (1-\frac{1}{2i\pi})}dx= (\frac{\pi}{\tau})^{1/2}e^{-\pi\frac{\pi}{\tau} \tau^2 (1-\frac{1}{2i\pi})^2}= (\frac{\pi}{\tau})^{1/2}e …
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3 votes
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Fourier transform of a differential operator

Let me change slightly your notations and consider the quadratic form in $\mathbb R_{\xi,\eta}^2$ $$ Q(\xi,\eta)=\alpha \xi ^2+2\gamma \xi \eta+\beta \eta^2, $$ where $\alpha, \beta$ are real paramete …
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3 votes
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Decay of oscillatory integral for non-analytic phase function

Let me fix $\delta=1$ for simplicity. Let us use a Van der Corput method. We have for $\epsilon\in (0,1)$ to be chosen later, with $\phi(x)= e^{-x^{-2}}, $ noting that $\phi'(x)=\phi(x) 2 x^{-3}$ $$ I …
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0 votes
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119 views

Wigner distribution

The Wigner distribution of $u\in L^2(\mathbb R)$ is defined as a function $W(u)$ on $\mathbb R^2$ given by $$ W(u)(x,\xi)=\int_\mathbb R u\left(x+\tfrac z2\right) \overline{u\left(x-\tfrac z2\right)} …
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3 votes
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Fourier analysis and fractional calculus

Too long for a comment. Your spelling of the name of the mathematician Joseph Fourier is incorrect. Also your formula is almost impossible to read: your fractional derivative on the lhs is the Fourier …
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1 vote

Logarithm of the Fourier transform?

Let us start with the identity $F^4=I$. As a result, we have formally \begin{align} \ln F&=\ln(I+F-I)=\sum_{k\ge 1}\frac{(-1)^{k-1}(F-I)^k}{k} \\&= \sum_{1\le k\le 3}\frac{(-1)^{k-1}(F-I)^k}{k}+ \sum_ …
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2 votes
0 answers
274 views

Hilbert transform

Let $\mathscr H$ be the Hilbert transform, that is the Fourier multiplier by $\text{sign } \xi$: $$ (\mathscr H u)(x)=\int_{\mathbb R} e^{2iπ x\xi }(\text{sign } \xi) \hat u(\xi) d\xi. $$ The Hilbert …
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1 vote

Relation between inverse Fourier transform of dyadic bump function and its regularity

I suggest a mild modification of your question. In the first place, let us set $ \psi_k(t)=\psi_1(t2^{-k}). $ Let us also replace $\sqrt{1+\vert \xi\vert^2}$ by $\vert \xi\vert$. We get $$ \int_{\math …
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1 vote

Inverse Fourier transform of an $L^2$ function as limit on balls

Let me reformulate your question: you consider the Fourier multiplier $ L_m=\mathbf 1_{B_m}(D) $ defined by the formula $$ (\mathbf 1_{B_m}(D)f)(x)=\int e^{2iπ x\xi}\mathbf 1_{B_m}(\xi) \hat f(\xi) d\ …
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2 votes
0 answers
125 views

Fourier multiplier on $L^1$

On the Wikipedia page, one can read that an iff condition for L1 boundedness of the Fourier multiplier m(D) is that $$ \hat m\quad\text{ is a Borel measure with finite total mass. } $$ There is no ref …
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