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28
votes
Does Physics need non-analytic smooth functions?
A strong argument is given above on the heat equation; let me be more specific. The heat equation, one of the most basic in PDE and mathematical physics, already known to Fourier, is
$$
L=\frac{\parti …
10
votes
Accepted
Analyticity of $f*g$ with $f$ and $g$ smooth on $\mathbb{R}$ and analytic on $\mathbb{R}^*$
The answer to your question is negative. Take the smooth function $\chi$ defined by
$$
\chi(t)=H(t) e^{-t^{-1}-t^2}, \quad H=\mathbf 1_{(0,+\infty)}.
$$
This function is in $L^1(\mathbb R)$, $C^\infty …
3
votes
Analyticity of the solutions of PDE
Take the Lewy operator $\mathcal L$ in $\mathbb R^3_{x,y,t}$
$$
\mathcal L=\partial_x+i\partial_y+i(x+iy)\partial_t.
$$
There exists a set $S$ of second category in $C^\infty(\mathbb R^3)$ such that f …
2
votes
Smoothness of the radius of convergence
You have the explicit Hadamard formula
$$
\frac{1}{R(x)}=\limsup_n\vert a_n(x)\vert^{1/n}=\inf_n\bigl(\sup_{k\ge n}\vert a_k(x)\vert^{1/k}\bigr),
$$
triggering semi-continuity properties for $1/R$: se …
1
vote
1
answer
489
views
Composition algebra of Gevrey function for $s<1$
Let $g,f$ be real-valued functions defined on the real line. Let $s$ be a real number.
Assuming that $g,f$ are both in the Gevrey class $G^{s}$, it is true that $g\circ f$ belongs to $G^{s}$ if $s\ge …