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Continuum theory, point-set topology, spaces with algebraic structure, foundations, dimension theory, local and global properties.
21
votes
Locally compact Hausdorff space that is not normal
Another nice elementary example is the rational sequence topology. For every irrational number $x$ we pick a sequence $q(x)_n$ of rational numbers, all different, that converge to $x$ (in the usual to …
1
vote
Does every Lindelof uniform space have a Lindelof completion?
this paper by Howes gives a characterization of uniform spaces with a Lindelöf completion, but the characterization uses the derived uniformity, and notions like preparacompactness. I don't see as yet …
23
votes
What is your favorite proof of Tychonoff's Theorem?
I like the proof from Alexander's subbase lemma. E.g. A proof here.
That lemma also gives the compactness criterion in ordered spaces (completeness implies compactness).
2
votes
Topological spaces that resemble the space of irrationals
As regards $\mathbb Q$ (your first remark), it is true that all countable metrisable spaces without isolated points are homeomorphic to $\mathbb Q$. If you want to omit metrisable, replace it by $\mat …
4
votes
Hurewicz theorem on mappings that lower dimension
In Engelking's Theory of Dimensions, Finite and Infinite, Thm 3.3.10 (p. 200) proves the more general result
If $f: X \to Y$ is a closed mapping from a normal space $X$ to a weakly paracompact normal …
3
votes
Accepted
The Tychonov cube $X^X$ of a compact space $X$ is a compact semigroup with the composition o...
To check that $f \to f \circ g$ is continuous in $f$ as a map $X^X \to X^X$ for a fixed $g \in X^X$: take a net $f_i \to f$ ($i \in I$, some directed set) in $X^X$ converging to $f \in X^X$. This mea …
72
votes
Is $\mathbb R^3$ the square of some topological space?
this blog post refers to some papers with proofs. I've heard Robert Fokkink explain his proof (which is, quoting from this post)
A linear map $\Bbb R^n \to \Bbb R^n$ can be understood to preserve or …
2
votes
Compact spaces whose compactness does not come from a product of compact spaces
For me the most basic compact spaces are $\{x_n: n \in \Bbb N\} \cup \{x\}$ when $x_n \to x$, (the countable cofinite space is a special case), of course all finite spaces, and all ordered topological …
2
votes
Accepted
Metrizability of topology of compact convergence
According to Engelking (exercise 3.4E, which is based on a paper by Arens):
If $C(X,\Bbb R)$ (with the compact-open topology and $X$ Tychonoff) is first countable, then $X$ is hemicompact.
A Hau …
8
votes
Accepted
Which compact metrizable spaces have continuous choice functions for non-empty closed sets?
It's an old (1981) theorem by Jan van Mill and Evert Wattel (see this paper) that a compact space has a continuous selection iff it is orderable. (So has a linear order whose order topology is the top …
5
votes
Accepted
A classification of $G_{\delta\sigma}$ zero-dimensional spaces?
This paper by Van Mill from 1981 gives a characterisation of $\Bbb Q \times \Bbb P$ (where $\Bbb P$ is a common notation for the irrationals) in Thm 5.3:
If $X$ is separable metrisable and zero-di …
3
votes
Is the lexicographic ordering on the unit square perfectly normal?
For a compact Hausdorff $X$ it is equivalent that $X$ is hereditarily Lindelöf or that $X$ is perfectly normal. Sketch: $X$ is hereditarily Lindelöf implies that every open set is an $F_\sigma$ (as $X …
0
votes
Accepted
A closed subset $B$ of the Hilbert cube such that $\operatorname{Int}(B) = \emptyset$ and $B...
$A=\{0\} \times [-1,1]^{\Bbb N}$ works as an example, e.g.
For more info on $Z$-sets in $Q$, see Infinite-dimensional Topology by Jan van Mill.
10
votes
Accepted
CCC + collectionwise normality => paracompact?
Yes, there is.
Let $I = \omega_1$ be the first uncountable ordinal, and let $P = \{0,1\}^I$ be the uncountable product of discrete spaces of 2 points. Let $S$, the so-called $\Sigma$-product be its s …
5
votes
Accepted
Is a cofinite topology for a set with cardinality between $\aleph_{0}$ and $2^{\aleph_{0}}$ ...
A continuous non-constant function from $[0,1]$ into $X$ with the cofinite topology exists iff $[0,1]$ has a partition into $\le |X|$ many disjoint closed non-empty subsets.
This question discusses …