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Complex, contact, Riemannian, pseudo-Riemannian and Finsler geometry, relativity, gauge theory, global analysis.
5
votes
0
answers
174
views
Space of piecewise geodesic paths
It is well-known that for any Riemannian manifold $M$, the spaces
$$H_x(M) = \Bigl\{ \gamma \in AC\big([0, 1], M\big) ~\Big|~ \gamma(0) = x, \int_0^T|\dot{\gamma}(s)|^2 \mathrm{d}s < \infty\Bigr\}$$
a …
3
votes
Dual connections for Information Geometry
If you have any manifold $M$ and a vector bundle $\mathcal{V}$ over $M$, then associated to any connection $\nabla$ on $\mathcal{V}$, there is indeed a dual connection $\nabla^*$ on the dual bundle $\ …
2
votes
0
answers
132
views
Exact vs. closed b-metric
This is a crosspost from Stackexchange, where the question did not find any attention. This is probably due to the length of this post, but I did my best to organize it as well as I could. I am thankf …
2
votes
Accepted
When do curves exist in infinite-dimensional submanifolds?
Take $V = L^2(M)$ with its usual Hilbert space topology and $W = C^\infty(M)$. Take $X = \mathrm{span}\{f\}$ for some non-smooth function. Then $X \cap W = \{0\}$, hence the kinematic tangent space of …
6
votes
Accepted
Making the identification $\tau M\approx TM\oplus (TM\odot TM)$
Given a connection on the tangent bundle, you can define the second covariant derivative $\nabla^2f$ by
$$ \nabla^2f[X, Y] := \partial_X\partial_Y f - \partial_{\nabla_X Y} f.$$
Then $\nabla^2f$ is a …
2
votes
0
answers
68
views
Hess-Schrader-Uhlenbrock inequality for non-symmetric operators
Let $M$ be a (compact, let's say) Riemannian manifold, $\mathcal{V}$ a vector bundle over $M$ with covariant derivative $\nabla$ and a fiber metric. Let $L = - \mathrm{tr}(\nabla^2) + V$ with some pot …
0
votes
1
answer
233
views
What is the Newtonian Capacity of a subset of $S^n$?
In their paper "Conformally flat Manifolds, Kleinian Groups and Scalar Curvature", Schoen and Yau repeatedly use the term "Newtonian capacity" for a subset of $S^n$.
I know the following definition: …
1
vote
0
answers
128
views
Volume growth of balls implies volume growth of spheres?
Suppose I have a complete, non-compact Riemannian manifold $M$ such that the volume of balls around a fixed point $p \in M$ satisfies
$$\mathrm{vol}(B_R(p)) \leq v(R)$$
for some function $v$. Can we t …
1
vote
Asymptotic of the heat kernel
You just need to check that
$$ \int_M H_k(x, y) \mathrm{d}y = 1 + O(t^{k+1})$$
for all $x \in M$ and for all $k$. For example, this follows directly from the method of stationary phase (just take a ge …
3
votes
Accepted
The first eigenvalue of the Schrödinger operator is simple.
Roughly, the trick is not to view $L$ as an operator on $L^2$, but on $C^0$
I will use the following version of Krein-Rutmann which is proven in "Du, Yihong: Order Structure and Topological Methods i …
5
votes
Why are there so many smooth functions?
Here is a somewhat different answer:
Smooth functions always admit asymptotic expansions in each point, convergent or not. One difference between analytic functions and smooth functions is, of course …
5
votes
0
answers
183
views
Converse of Hamilton's Maximum Principle?
The famous maximum principle of Hamilton states the following. Let $C$ be a convex $O(n)$-invariant subset of the space of algebraic curvature operators. Then if it is invariant under the ODE
$$ \dot{ …
3
votes
1
answer
2k
views
Linearization of a vector field
In a paper that I was reading, I stumbled across the following theorem:
Let $X$ be a vector field with $$X=
> a^ix^i\partial_{x^i} +
> \mathcal{O}(|x|^2),$$ where $x$ is
some chart and $a^i>0$. …
1
vote
2
answers
282
views
Number of geodesics of certain length
Let $M$ be a Riemannian manifold, and let $x, y \in M$ be non-conjugate points.
Let $r, R>0$ be two numbers. I am looking for a bound on the number of geodesics between $x$ and $y$ of Length between …
6
votes
0
answers
2k
views
Second derivative of Riemannian Exponential Map
Let $M$ be a Riemannian manifold. Let us look at the Riemannian exponential function $\exp_x: T_x M \supset \mathcal{D} \longrightarrow M$.
The derivative of the exponential map can be expressed in T …