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A Banach space is a complete normed vector space: A vector space equipped with a norm such that every Cauchy sequence converges.
7
votes
1
answer
191
views
Projective tensor product of injective operators
I've seen claims that it is known that for a pair of bounded injective linear operators $T\colon X\to Y, S\colon W\to V$, their tensor product $T\otimes S\colon X \otimes_\pi W\to Y \otimes_\pi V$ nee …
9
votes
0
answers
1k
views
Weak compactness in $\mathcal{F}(X)$
Let $(X,0)$ be a pointed metric space and let $\mathcal{F}(X)$ be the natural predual of ${\rm Lip}_0(X)$, the space of Lipschitz functions on $X$ that map $0$ to $0$; here $\mathcal{F}(X)$ is really …
15
votes
2
answers
923
views
Distinguishing topologically weak topologies of Banach spaces
Are the weak topologies of $\ell_1$ and $L_1$ homeomorphic?
Strangely may it sound, the question seeks contrasts between norm and weak topologies of Banach spaces from the non-linear point of view. …
7
votes
0
answers
123
views
The bidual of the space of divergence-free vector fields
Consider the Banach space $L_1(\mathbb R^n, \mathbb R^n)$ of integrable vector fields $(n>1$) together with its subspace $N$ formed by those vectors fields whose divergence (computed in the distributi …
6
votes
0
answers
99
views
Is every separable Banach space with the MAP 1-complemented in a space with a monotone basis?
The question, already phrased in the title, looks like a classical problem from Banach space theory from the 1970s. Hence, my question is more of a reference request in its nature.
Can every separ …
10
votes
0
answers
264
views
Are biduals of spaces of differentiable functions on hypercubes Grothendieck?
Consider the space $E_n = C^1([0,1]^n)$ of continuously differentiable functions with the usual norm
$$\max\{ \|f\|_\infty, \|f^\prime_{x_1}\|_\infty, \ldots, \|f^\prime_{x_n}\|_\infty\}.$$ making it …
7
votes
0
answers
200
views
Equivalent strictly convex norms in spaces of small density
Can one construct in ZFC a Banach space of density character $\omega_1$ that does not have an equivalent strictly convex norm?
Maybe one may apply some kind of a Löwenheim–Skolem-type argument to …
10
votes
0
answers
250
views
Do sufficiently large Banach spaces admit non-compact operators with not too large range?
As in the title,
does there exist a cardinal number $\lambda$ such that for every Banach space $X$ of density/cardinality at least $\lambda$ there exists a non-compact bounded, linear operator $T\ …
5
votes
0
answers
115
views
An elementary inequality in normed spaces - the original reference sought
The following inequality is an elementary exercise in convexity: let $x,y$ be non-zero vectors in a normed space with $\|x\|, \|y\|\leqslant 1$. Suppose that $\|x-y\| \geqslant 1$. Then
$$\left\|\fra …
15
votes
1
answer
679
views
Open bilinear maps that are not uniformly open
A map $f\colon X\to Y$ between metric spaces is uniformly open whenever for each $\varepsilon >0$ there is $\delta >0$ such that for any $x\in X$ one has
$$B_Y\big(f(x),\delta\big)\subseteq f\big(B_X …
5
votes
0
answers
137
views
Banach spaces complemented in their ultrapowers
By the principle of local reflexivity, the second dual $X^{**}$ of a Banach space $X$ is complemented in some ultrapower $X^U$ of $X$. Even when $X$ is separable, the index set of $U$ cannot be expect …
7
votes
1
answer
498
views
Is $L_q(X^*)$ complemented in $(L_p(X))^*$?
Let $X$ be a Banach space and let $p\in (1,\infty)$. If $q$ denotes the conjugate exponent to $p$, then $L_q(X^*)$ is easily seen to be isometric to a subspace of $(L_p(X))^*$ via the map $$f\mapsto \ …
5
votes
2
answers
295
views
Well-complemented copies of $\ell_p^n$
This must be surely known but I couldn't locate this problem in the literature. It popped out in a priori unrelated approximation problem but if true, would help me greatly.
Let $p\in (1,\infty)$.
I …
7
votes
0
answers
554
views
The Banach space of bounded functions with countable support
Let $X$ be a set of cardinality $\aleph_1$ and consider the Banach space $\ell_\infty^c(X)$ of all scalar-valued bounded functions on $X$ which are non-zero only for countably many elements of $X$ end …
8
votes
1
answer
330
views
Tokarev's theorem on Banach lattices which are Grothendieck spaces
When browsing the literature, I have found the following theorem of E. Tokarev:
Let $X$ be a Banach lattice with weakly sequentially complete dual space. Then for any Banach space $Y$, every uncondit …