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A Sobolev space is a vector space of functions equipped with a norm that is a combination of Lp-norms of the function itself and its derivatives up to a given order.
0
votes
Fractional-order Rellich–Kondrashov Theorem
I've since come across the article
Amann, Herbert. Compact embeddings of vector-valued Sobolev and Besov spaces. Dedicated to the memory of Branko Najman. Glas. Mat. Ser. III 35(55) (2000), no. 1, …
2
votes
Accepted
An acting condition for a superposition operator from $H^1(\Omega)$ to $H^1(\Omega)$
The following is stated in the paper
Moshe Marcus and Victor J. Mizel, MR 531975 Complete characterization of functions which act, via superposition, on Sobolev spaces, Trans. Amer. Math. Soc. 251 (1 …
1
vote
2
answers
2k
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Fractional-order Rellich–Kondrashov Theorem
The following is known:
Let $s \in (0,1)$ and $p \in [1,\infty)$ be such that $sp < n$. Let $q \in [1, p^*_{n,s})$ with $p^*_{n,s} = np/(n-sp)$, $\Omega \subset \mathbb R^n$ be a bounded extension …
1
vote
Sobolev spaces based on $L^p$ with $0<p<1$
The paper (and this comment on it)
Peetre, Jaak. A remark on Sobolev spaces. The case $0<p<1$. Collection of articles dedicated to G. G. Lorentz on the occasion of his sixty-fifth birthday, III. J …
2
votes
Does strong convergence in $W_p^1$ imply strong convergence of derivatives of absolute value...
Yes, this is correct; in fact, you could replace the map $|\cdot|$ with an arbitrary (uniformly) Lipschitz map $f$ (with $f(0) = 0$ if $G$ is unbounded) [1].
[1] Marcus, Moshe; Mizel, Victor J. Every …
9
votes
1
answer
1k
views
Noncompactness of the Sobolev embedding in the critical exponent case
Let $\Omega \subset \mathbb R^n$ be a bounded domain with a Lipschitz boundary and $n > p \ge 1$.
It is well known that up to the critical exponent $p^* = pn/(n − p)$, i.e. $q < p^*$, the Sobolev-to- …