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2 votes
0 answers
46 views

Diamonds on supercompact $\kappa$ after a $\kappa$-c.c. forcing

Let $\kappa$ be supercompact. Then the (supercompact) Laver diamond holds at $\kappa$: There is $f:\kappa\to V_\kappa$ such that for all $\lambda\geq \kappa$ and $x\in H(\lambda^+)$ there is $j:V\to M$...
Yujun Wei's user avatar
7 votes
1 answer
308 views

Proper Forcing Axiom for $|\mathbb{P}| \leq \mathfrak{c}$

Let $\mathsf{PFA}(\mathfrak{c})$ denote the Proper Forcing Axiom (PFA) restricted to posets $|\mathbb{P}| \leq \mathfrak{c}$. I think $\mathsf{PFA}(\mathfrak{c}) \implies \mathfrak{c} = \aleph_2$, but ...
Clement Yung's user avatar
  • 1,372
7 votes
0 answers
260 views

A version of determinacy for all sets

Under ZF + AD, some games are undetermined because of lack of choice. In fact, the axiom of choice is equivalent to determinacy of games of length 2. However, we can ask whether the lack of choice ...
Dmytro Taranovsky's user avatar
6 votes
1 answer
199 views

$L(\mathbb{R})$-absoluteness from a proper class of Woodins: source?

For a paper I'm writing I need to use (as a blackbox) the following theorem: if there is a proper class of Woodin cardinals and $G$ is set-generic, then $L(\mathbb{R})$ and $L(\mathbb{R})^{V[G]}$ are ...
Noah Schweber's user avatar
9 votes
0 answers
177 views

Inner model of "CH + large cardinals" that satisfies MM?

I've been told that if $V$ has CH and large cardinals, then there is an inner model in which MM holds. The sketch is as follows: Any $\Sigma^2_1$ sentence that can be forced is already true in such $V$...
sobach'e_pole's user avatar
4 votes
1 answer
140 views

Coherent sequence of ultrafilters in iterated forcing extensions

Remember that if $\kappa$ is strongly compact, then any ${<}\kappa$-complete filter extends to a ${<}\kappa$-complete ultrafilter. Let $\Bbb P_\delta=\langle\Bbb P_\alpha,\dot{\Bbb Q}_\alpha\mid ...
Tristan vd Vlugt's user avatar
9 votes
1 answer
252 views

Copy of $P(\omega)/\mathrm{fin}$ on $\omega_1$

$\newcommand{\fin}{\mathrm{fin}}$Under what hypotheses does there exist a uniform ideal $I$ on $\omega_1$ such that $P(\omega_1)/I \cong P(\omega)/\fin$? What is the consistency strength? It follows ...
Monroe Eskew's user avatar
  • 18.6k
6 votes
1 answer
227 views

Forcing $\neg\square_{\omega_1}$ from a Mahlo cardinal, reference

In Jensen's The fine structure of the constructible hierarchy, it is stated that Solovay proved the consistency of $\neg\square_{\omega_1}$ by collapsing a Mahlo cardinal to $\omega_2$. I was ...
Lorenzo's user avatar
  • 2,286
5 votes
0 answers
150 views

Consistency upper bounds for $\neg\square_{\aleph_\omega}$

In the introduction of Cummings and Friedman's $\square$ on the singular cardinals the following is written: Failure of $\square_\lambda$ for $\lambda$ singular is stronger and rather more ...
Lorenzo's user avatar
  • 2,286
4 votes
1 answer
148 views

Reference request: $\kappa^+$-saturated ideal from iterated Cohen forcing on measurable $\kappa$

In Kunen [1] the author makes the following note: Let $\kappa$ be measurable with normal measure $\mathscr{U}$ in a model of $\mathsf{GCH}$. Let $\mathbb{P}$ be an iteration of $\operatorname{Add}(\...
Calliope Ryan-Smith's user avatar
3 votes
0 answers
200 views

Weak extender models for supercompactness without choice

Assume ZFC and a supercompact cardinal $κ$. Is it consistent that there is a weak extender model $N⊨\text{ZF}$ for supercompactness of $κ$ such that the axiom of choice and well-ordering of $P_κ(λ)^N$...
Dmytro Taranovsky's user avatar
6 votes
0 answers
125 views

From HODs to corresponding models of AD

If $M$ is HOD of a model $N$ of $\text{AD}^+ + V=L(P(ℝ))$, what kind of forcing construction in $M$ gives back such an $N$? HODs for $\text{AD}^+ + V=L(P(ℝ))$ are conjectured (and under anti-large ...
Dmytro Taranovsky's user avatar
9 votes
0 answers
258 views

Naive way to violate $\mathsf{SCH}$ at $\aleph_\omega$

I asked this question on MSE and got a partial answer. Shamefully I still haven't figured out myself a full answer, so I would like to ask it here. The usual way to get the failure of $\mathsf{SCH}$ ...
new account's user avatar
5 votes
1 answer
196 views

Can a generic ultrafilter over $\mathrm{NS}^+_{\omega_1}$ witness $\omega_1$ is Ramsey-like?

Suppose that $\kappa$ is an appropriate large cardinal (preferably a Woodin cardinal, but possibly something stronger) and let $G$ be a $\operatorname{Col}(\omega_1,<\kappa)$-generic filter over $V$...
Hanul Jeon's user avatar
  • 3,042
12 votes
0 answers
213 views

Is $\kappa \rightarrow [\kappa]^2_3$ the same as $\kappa \rightarrow [\kappa]^2_2$ for inaccessible $\kappa$

The principle $\kappa \rightarrow [\kappa]^2_\alpha$ states that whenever we have a coloring $c:[\kappa]^2\rightarrow \alpha$ there is $H \subset \kappa$ of size $\kappa$ s.t. $|c"[H]^2|<\alpha$. ...
Jiachen Yuan's user avatar
7 votes
1 answer
262 views

Proof (or reference) about the cc-ness of termspace forcing

Recall that for $P$ a forcing order and $\dot{Q}$ a $P$-name for a forcing order, the termspace forcing $T(P,\dot{Q})$ consists of minimal-rank names for elements of $\dot{Q}$, ordered by $\dot{q}'\...
Hannes Jakob's user avatar
  • 1,799
4 votes
1 answer
226 views

Ramsey-like property with order condition

I wonder if there are regular cardinals $\lambda$ and $\kappa$ such that $\kappa < \lambda \leq 2^\kappa$ and such that, consistently, the following holds: Let $c: [\lambda]^2 \to \kappa$ be such ...
Matteo Casarosa's user avatar
14 votes
2 answers
678 views

Are there interesting examples of theorems proved using ‘height’ extensions?

It's well known that forcing is more than a tool for proving independence: We can prove theorems and formulate axioms in theories like $\mathsf{ZFC}$ by moving to forcing extensions (e.g. $\mathfrak{p}...
Neil Barton's user avatar
4 votes
1 answer
336 views

Which step is wrong in the following simplification of Silver's forcing?

Theorem: If M is a countable transitive model of ZFC, and $\kappa$ is a supercompact cardinal in M, and $2^\kappa=\kappa^+$. Then there exists a forcing extension M[G] such that $\kappa$ becomes a ...
Reflecting_Ordinal's user avatar
4 votes
0 answers
225 views

Complexity of $Σ_n$ theory of $H(ω_2)$ under MM$^{++}$

Complexity of $Σ_n$ theory of $H(ω_2)$ under MM$^{++}$ Under Woodin's $\mathbb{P}_\text{max}$ axiom (which is implied by MM$^{++}$), what is the complexity of the $Σ_n$ theory of $H(ω_2)$? Same ...
Dmytro Taranovsky's user avatar
3 votes
0 answers
249 views

Independence through forcing vs generic collapses

Are there known statements in $V_{ω+ω}$ independent through forcing after $\mathrm{Col}(ω,<κ_1)*\mathrm{Col}(κ_1,<κ_2)*\mathrm{Col}(κ_2,<κ_3)*...$ where $κ_1<κ_2<κ_3<...$ are ...
Dmytro Taranovsky's user avatar
6 votes
0 answers
318 views

Temporary destruction of measures in intermediate models

It is a well-known theorem that if $\kappa$ is measurable, then there is a generic extension in which $\kappa$ is no longer weakly compact, but we can force its weak compactness back and recover the ...
Asaf Karagila's user avatar
  • 39.7k
6 votes
0 answers
171 views

Preserving supercompactness in intermediate forcing extensions

Let $\kappa$ be supercompact in $V$. Let $\mathbb{P}$ be one of the standard forcing notions (or an iteration of such), and for simplicity assume that $\mathbb{P}$ is ${<}\kappa$-directed closed (e....
Johannes Schürz's user avatar
13 votes
1 answer
561 views

Iterating Neeman's forcing

In the paper, "Forcing with sequences of models of two types," (MR3201836), Neeman claims that, using a supercompact and a weakly compact above, one can force with his pure side conditions ...
Monroe Eskew's user avatar
  • 18.6k
6 votes
0 answers
206 views

Collapse successor of singular while preseving supercompactness

Suppose $\kappa$ is a supercompact cardinal. Is it possible to find a forcing which collapses $\kappa^{+\omega+1}$ to $\kappa^{+\omega}$ (all those $\kappa^{+n}$'s are preserved) while the ...
Jiachen Yuan's user avatar
5 votes
1 answer
265 views

Consistency strength of lifting through a lot of collapsing

What is the consistency strength of the following situation? $j : V \to M$ is an elementary embedding definable from parameters in $V$, with critical point $\kappa$. $\mathbb P$ is a forcing that ...
Monroe Eskew's user avatar
  • 18.6k
22 votes
1 answer
938 views

How badly can the GCH fail globally?

It's known that we can have global failures of GCH---for example, where $\forall \lambda(2^\lambda = \lambda^{++})$---given suitable large cardinal axioms. My question is whether we can have global ...
Sam Roberts's user avatar
  • 1,198
6 votes
1 answer
230 views

Can we recover an inner model of CH after forgetting some generic information?

Suppose $\kappa$ is an inaccessible cardinal. Let $G \times H$ be $\mathrm{Col}(\omega_1,{<}\kappa) \times \mathrm{Add}(\omega,\kappa)$-generic over $V$. Let $X \subseteq \kappa$ be $\mathrm{Add}(...
Monroe Eskew's user avatar
  • 18.6k
6 votes
0 answers
344 views

Inner models with all sets generic

Question: Under large cardinal axioms, what is the intersection of all inner models $M$ of ZFC such that every set in $V$ is set-generic over $M$? Every set belongs to a generic extension of HOD, and ...
Dmytro Taranovsky's user avatar
5 votes
0 answers
276 views

Absoluteness and the scale property for $Π^2_2$ or $Σ^2_2$

Under the diamond principle $◊$ and large cardinal axioms, which of the two pointclasses $Π^2_2$ or $Σ^2_2$ is expected to have the scale property? Because conditional $Σ^2_2$ absoluteness under $◊$ ...
Dmytro Taranovsky's user avatar
11 votes
0 answers
490 views

$\Sigma^2_1$ and the Continuum Hypothesis

This is a follow up to Will Brian's answer to this recent question. In particular, quoting Brian: "In fact, Paul Larson has pointed out to me that the statement "$\phi$ and $\phi^{-1}$ are conjugate"...
Todd Eisworth's user avatar
6 votes
1 answer
419 views

When does "sufficient genericity" actually suffice?

Fix a forcing notion $\mathbb{P}$. Say that a formula $\varphi(x)$ with parameters is $\mathbb{P}$-enforceable if there is some countable set $\mathcal{D}$ of dense sets in $\mathbb{P}$ such that for ...
Noah Schweber's user avatar
6 votes
1 answer
242 views

Generic saturation of inner models

Say that an inner model $M$ of $V$ is generically saturated if for every forcing notion $\Bbb P\in M$, either there is an $M$-generic for $\Bbb P$ in $V$, or forcing with $\Bbb P$ over $V$ collapses ...
Asaf Karagila's user avatar
  • 39.7k
3 votes
1 answer
237 views

Radin forcing preserving large cardinals

I'm wondering if there are any known result for the maximum large cardinal strength which can be preserved by Radin forcing? For instance, with any large cardinal hypothesis in the ground model, can ...
Jiachen Yuan's user avatar
5 votes
0 answers
304 views

Symmetry between V and HOD

Is it consistent that the set of ordinal definable real numbers is countable, but for every $y∈\mathrm{OD}∩ℝ$, every true $Σ_2^{V,y}$ statement holds in $\mathrm{HOD}$? Note that $Σ_2^V$ is the best ...
Dmytro Taranovsky's user avatar
10 votes
0 answers
561 views

stationary reflection in $[\kappa]^\omega$

It is well-known that the following reflection principle is consistent relative to a supercompact: For all $\kappa \geq \omega_2$ and all stationary $S \subseteq [\kappa]^\omega$, there is $X \...
Monroe Eskew's user avatar
  • 18.6k
2 votes
1 answer
276 views

A variant of Radin forcing

Suppose $\kappa$ is a large cardinal (strong cardinal seems to be enough). Is there a forcing notion $\mathbb{R}$ with the following properties: $(1)$ Forcing with $\mathbb{R}$ adds a club $C$ into $\...
Mohammad Golshani's user avatar
5 votes
1 answer
694 views

What are examples of non-equivalent virtualizations of a large cardinal?

This is a follow up to my previous question concerning virtual large cardinals, that are generally weaker axioms of infinity obtained from ordinary large cardinals through the so-called virtualization ...
Morteza Azad's user avatar
2 votes
1 answer
652 views

On the Actual Potential of Virtual Large Cardinals

Virtual large cardinals belong to a relatively new breed of strong axioms of infinity. They often appear as statements of the following form: Definition. Suppose $A$ is a large cardinal property ...
Morteza Azad's user avatar
11 votes
2 answers
377 views

Does $0^{\#}$ imply the failure of upward directedness in the set generic universe over $L$?

Question 1. Suppose that $0^{\#}$ exists. Are there set generic filters $g,h$ over $L$ ($g,h \in V$) such that for any $f$ ($\in V$) which is generic over $L$ we have that $L[g] \cup L[h] \not \...
Stefan Mesken's user avatar
2 votes
1 answer
390 views

Strong Total Failures vs. Weak Instances of the Generalized Continuum Hypothesis

The exponentiation operator inflicts a subtle information loss on the transfinite numerical equations, pretty similar to the case of $a^2=b^2 \nRightarrow a=b$ in real numbers. In fact, for the ...
Morteza Azad's user avatar
9 votes
2 answers
527 views

Does Easton forcing preserve measurable cardinals?

The question is in the title. For Easton's theorem see Wikipedia. Loosely speaking we can use forcing to manipulate the powerset function on regular cardinals as much as we like given we satisfy the ...
Ioannis Souldatos's user avatar
6 votes
1 answer
571 views

fake and weak cardinals

Suppose $\lambda$ is a successor of a singular cardinal. We will say $\lambda$ fake if there is a transitive set $M$ such that $\lambda \subseteq M$ satisfying $\mathrm{ZFC}^-$ (ZFC without powerset) ...
Monroe Eskew's user avatar
  • 18.6k
5 votes
1 answer
522 views

How to kill a $\Sigma_{n+1}$-correct cardinal softly ($n>1$)?

A cardinal $\kappa$ is $\Sigma_n$-correct iff $V_\kappa \prec_n V$. For n>1, how to force a $\Sigma_{n+1}$-correct cardinal to be $\Sigma_{n}$-correct but not $\Sigma_{n+1}$-correct? For $n=1$, we ...
Jinglun Cai's user avatar
7 votes
0 answers
197 views

Query about iterated collapse forcing

I have heard it said that it is possible to use Woodin's iterated collapse forcing to prove that the theory $\textsf{ZF}$+"there exists a non-trivial elementary embedding $j:V_{\lambda+2} \rightarrow ...
Rupert's user avatar
  • 2,125
5 votes
1 answer
379 views

Prikry forcing and Cohen generic

Let $\kappa$ be a measurable cardinal and let $\mathcal{U}$ be a normal measure on $\kappa$. Let $\mathbb{P}$ be the standard Prikry forcing using $\mathcal{U}$. Let $\mathbb{Q} = \text{Add}(\kappa, 1)...
Yair Hayut's user avatar
  • 5,112
5 votes
1 answer
401 views

Can Woodin's fast function forcing kill Shelah cardinals?

Definition 1. An uncountable cardinal $\kappa$ is Shelah if for every function $f:\kappa\rightarrow \kappa$ there exists a transitive class $M$ and a non-trivial elementary embedding $j:V\rightarrow M$...
Morteza Azad's user avatar
14 votes
0 answers
353 views

The failure of GCH al $\aleph_\omega$ by nice forcing

There are several ways to force $GCH$ below $\aleph_\omega$ and $2^{\aleph_\omega}> \aleph_{\omega+1},$ say: 1) The Gitik-Magidor's extender based forcing, see Prikry type Forcings. 2) Woodin's ...
Mohammad Golshani's user avatar
0 votes
1 answer
887 views

Forcing the existence of a weakly inaccessible cardinal in some strong set theory

Does the fact that, assuming the consistency of $ZFC$, no proof that the consistency of "$ZFC$ implies the consistency of '$ZFC$ + There exists a weakly inaccessible cardinal'" can be formulated in $...
Thomas Benjamin's user avatar
7 votes
1 answer
299 views

Consistency of Rado's conjecture with not CH

Rado's conjecture (one of many equivalent formulations) states: any non-special tree has a non-special subtree of cardinality $\aleph_1$. "Special" means a tree can be decomposed into countably many ...
Jing Zhang's user avatar
  • 3,038