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12 votes
1 answer
922 views

Does this algebra have finite global dimension ? (Human vs computer)

Usually computers can calculate the global dimension of a finite dimensional quiver algebra much faster than humans. But in this case a high end computer (calculating for 3 weeks) was not able to ...
4 votes
1 answer
303 views

Algebras derived equivalent to quasi-hereditary algebras

Let an algebra always be finite dimensional over a field and connected. It is well known that a quasi-hereditary algebra with $n$ simple modules has global dimension at most $2n-2$. Questions: 1. ...
4 votes
0 answers
84 views

Finitistic dimension via a bimodule

Let $A$ be a connected finite dimensional basic algebra. Question: Is there an indecomposable $A$-bimodule $W$ such that the finitistic dimension of $A$ is equal to the right projective dimension ...
13 votes
1 answer
745 views

Combinatorial inequality for dominant dimension

In the following I present a conjecture on Nakayama algebras that I have for nearly 2 years now. Since I was not able to solve it and it can be stated purely combinatorically, I thought it might be ...
5 votes
1 answer
243 views

Questions on group and Nakayama algebras from a book

Recall that a Nakayama algebra (also called serial algebras in the literature) is an algebra such that every indecomposable module has a unique composition series. In the book "Classical artinian ...
3 votes
1 answer
153 views

Finitistic dimension via reflexive modules

Recall that an $A$-module $M$ is reflexive in case the natural evaluation map $M \rightarrow M^{**}$ is an isomorphism, where $M^{*}=Hom_A(M,A)$. Question: Given a finite dimensional algebra $A$ ...
5 votes
1 answer
353 views

Existence of non-trivial reflexive modules

Recall that a module $M$ over a ring $R$ is reflexive in case the natural evaluation map $f_M:M \rightarrow M^{**}$ (where $M^{*}=Hom_R(M,R)$) is an isomorphism, where $f_M(m)=g$ with $g(h)=h(m)$, ...
3 votes
0 answers
67 views

Upper bound for embedding of submodules of projective modules

Assume we have a finite dimensional algebra $A$ with the following property: Every indecomposable submodule of a projective module embedds into $A^n$ for a fixed $n$. Is there a good method to ...
4 votes
1 answer
463 views

Global dimension of a graded algebra

Let $A= \bigoplus\limits_{n=0}^{\infty}{A_n}$ be an $\mathbb{N}$-graded algebra with semisimple $A_0$. Question: Do we have that the global dimension of $A$ is equal to $\sup \{i \geq 0 | Ext_A^i(...
4 votes
1 answer
685 views

Quadratic algebras and Koszul algebras

Let $A$ be a quadratic algebra and $B$ the Ext-algebra of $A$. In case $A$ is a Koszul algebra, we should have that the global dimension of $A$ plus one is equal to the Loewy length of $B$ (is there a ...
2 votes
0 answers
83 views

Length 2 modules over finite dimensional algebras

Given a finite dimensional algebra $A$ over an infinite field and two simple modules $S,T$. Question 1: Is there a useful (homological/computational) crtierion to decide when there are infinitely ...
3 votes
1 answer
189 views

Question on $\operatorname{Ext}$ in a local Frobenius algebra

Let $A$ be a finite dimensional local Frobenius algebra with simple module $k$ and an indecomposable non-projective module $M$ (that is also finite dimensional). Question: Is there an example of ...
3 votes
2 answers
214 views

History of an open problem on partial tilting modules

The following is an open problem: Given a partial tilting module $T$ over a finite dimensional algebra $A$ (that is $Ext_A^i(T,T)=0$ for all $i \geq 1$ and $pd(T) < \infty$), then $T$ is a tilting ...
2 votes
0 answers
164 views

On a conjecture about tilting modules

There is the following conjecture on tilting modules (see also History of an open problem on partial tilting modules): Given a partial tilting module $T$ over a finite dimensional algebra $A$ (that is ...
8 votes
0 answers
140 views

$n$-fold tensor products of $D(A)$ for finite dimensional algebras

Let $A$ be a finite dimensional quiver algebra over a field $K$ and let $D(-):=Hom_K(-,K)$ denote the natural duality (assume algebras are connected). Define $\psi_A:=sup \{ n \geq 1 | D(A)^{\otimes ...
1 vote
0 answers
141 views

Question on vanishing Hochschild cohomology

Recall that for an $K$-algebra $A$ with $A^e:=A^{op} \otimes_K A$ the Hochschild cohomology is defined as $HH^n(A,M):=Ext_{A^e}^n(A,M)$. Question: Is there a finite dimensional selfinjective ...
1 vote
1 answer
127 views

Gorenstein projective modules of a certain triangular matrix algebra

Let $B$ be a finite dimensional selfinjective algebra over a field $k$ with a finite dimensional non-projective $B$-module $M$ and $$A=\pmatrix{k&M\\0&B}.$$ A module $N$ over an algebra $C$ ...
6 votes
1 answer
420 views

Calculating the Ext-algebra with a computer

Given a finite dimensional quiver algebra $A$ over an arbitrary field and a module $M$ of finite injective dimension or finite projective dimension. Let $B$ be the Ext algebra of $M$, that is $B:=\...
5 votes
0 answers
105 views

Derived invariant acyclic algebras

Call a connected quiver algebra $A=KQ/I$ (finite quiver Q and admissible ideal I) derived-invariant in case every quiver algebra derived equivalent to $A$ is even isomorphic to $A$. For example local ...
3 votes
0 answers
71 views

$\Omega^2(S) \cong \tau(S)$ for simple modules

Let $A$ be an Artin algebra with $\Omega^2(S) \cong \tau(S)$ for each simple module $S$. Is $A$ a quasi-Frobenius (=selfinjective) algebra? Here $\tau$ denotes the Auslander-Reiten translate, which is ...
6 votes
2 answers
768 views

Auslander-Reiten theory for Gorenstein algebras

In the paper "Cohen-Macauley and Gorenstein artin algebras", Auslander and Reiten have a short section about Auslander-Reiten theory in Gorenstein algebras (I always assume we have an artin algebra ...
2 votes
0 answers
55 views

$Ext_{A^e}^i(D(A),A)$ for finite dimensional algebras

Let $A$ be a finite dimensional non-semisimple algebra over a field $K$ with enveloping algebra $A^e=A^{op} \otimes_K A$. Let $D(A)=Hom_K(A,K)$. Question: Is there always a positive integer $i>...
9 votes
1 answer
593 views

Hochschild homology with coefficients in a certain bimodule

Let $A$ be a finite-dimensional $k$-algebra and $U$ and $V$ two finite-dimensional projective $A$-modules (maybe neither the finiteness nor projectivity has to play a role, but these requirements are ...
4 votes
1 answer
179 views

Reference for isomorphism $Ext_A^n(X,Y) \cong Ext_A^1(\Omega^{n-1}(X),Y)$

Let $A$ be a finite dimensional algebra and $X,Y$ indecomposable modules and $n \geq 2$. We know that $Ext_A^n(X,Y) \cong Ext_A^1(\Omega^{n-1}(X),Y)$. Now such an isomorphism should be given by ...
4 votes
2 answers
337 views

When is $\Omega^1$ an equivalence?

Let $C$ be an abelian category with enough projectives and $\underline{C}$ the stable category of $C$ that is obtained by factoring out projective modules. When is the functor $\Omega^1 : \underline{...
5 votes
0 answers
88 views

Cluster-tilting object for a local non-selfinjective algebra

Let $A$ be a non-selfinjective (which is equivalent to non-Gorenstein) local finite dimensional algebra. Is there a known example of such an $A$ having a cluster-tilting object? Id be surprised to ...
2 votes
0 answers
43 views

Projective dimensions of the terms in a minimal injective resolution of the regular module

Let $A$ be a finite dimensional algebra with finite global dimension and with minimal injective coresolution $I_i$ of the regular module $A$. The study of the projective dimensions of the $I_i$ is an ...
4 votes
0 answers
90 views

Number of hereditary modules of a hereditary algebra

Let $Q$ always denote a Dynkin quiver. Given a connected path algebra $A=kQ$ and a module $M$, is there a useful criterion on $M$ when $End_A(M)$ is again a connected quiver algebra? Call a module ...
6 votes
1 answer
361 views

How to check whether a module is an n-th syzygy

Given a finite dimensional algebra $A$, define $\Omega^{n}(mod-A)$ (modules here are always finite dimensional) to be the full subcategory of projective modules or modules $M$ such that $M \cong \...
3 votes
0 answers
213 views

Cohen-Macaulay Artin algebras

In http://link.springer.com/chapter/10.1007%2F978-3-0348-8658-1_8#page-1 Auslander and Reiten introduced Cohen-Macaulay Artin algebras as a generalisation of Gorenstein algebras. Let X be the full ...
5 votes
1 answer
151 views

Derived equivalences of Artin algebras with finitistic dimension zero

Let $A$ be an Artin algebra of finitistic dimension zero and $B$ an algebra derived equivalent to $A$. Does $B$ also have finitistic dimension zero? In case this is true, this might generalise the ...
1 vote
0 answers
47 views

Piecewise hereditary algebras of Dynkin type that are QF-3

Is there an easy classification of piecewise hereditary (which means derived equivalent to a hereditary algebra) algebras of Dynkin type that are Quasi-Frobenius-3 (meaning that the injective envelope ...
4 votes
0 answers
81 views

Sum of all projective dimensions of simple modules

Let $X_{n,t}$ be the set of all finite dimensional algebras (we can assume they are given by a connected quiver and admissible relations) that have global dimension equal to $n$ and $t$ simple modules....
4 votes
0 answers
135 views

Question on syzygies

Given a finite dimensional algebra $A$ over a field $K$ with $\Omega^i(D(A)) \cong \Omega^{i+1}(D(A))$ for some $i \geq 1$, where $D(A)=\operatorname{Hom}_K(A,K)$. Do we then also have $\Omega^{-i}(A)...
5 votes
0 answers
253 views

Tannakian theory for Lie algebras

Let $G$ be a reductive (just in case) linear algebraic group over $\mathbb{C}$ and let $\mathfrak{g}$ be the Lie algebra of $G$. Consider the category $\operatorname{Rep}(G)$ of finite dimensional ...
10 votes
1 answer
400 views

Derived equivalences of Dyck paths

Call two Dyck paths $D_1$ and $D_2$ derived equivalent in case their corresponding Nakayama algebras are derived equivalent (The Dyck path of a Nakayama algebra with a linear quiver is just the top ...
3 votes
0 answers
136 views

Can a acyclic quiver algebra be derived equivalent to a non-acyclic quiver algebra?

Can a quiver algebra with acyclic quiver be derived equivalent to a quiver algebra with non-acyclic quiver? (I moved this question from another thread Derived equivalences of Dyck paths , where the ...
1 vote
0 answers
117 views

Derived equivalences and the Coxeter polynomial

Let $A$ be a quiver algebra with an acyclic quiver and primitive idempotents $e_i$. The Cartan matrix $C_A$ of $A$ is defined as the matrix with entries $dim(e_i A e_j)$ and the Coxeter matrix $\phi_A$...
2 votes
0 answers
201 views

Homological conjecture for finite dimensional algebras

In the theory of finite dimensional algebras there are many homological conjectures. When working over an algebraically closed field it is well known that any such algebra is Morita equivalent to a ...
2 votes
1 answer
206 views

Extensions of lattices

Let $G$ be a finite group and $\phi:M\to N$ be a surjective homomorphism of $G$-lattices (i.e. finitely generated $\mathbb{Z}[G]$-modules, free as $\mathbb Z$-modules), with kernel $K$. For every $n\...
3 votes
1 answer
211 views

Coinduced modules in the BGG category $\mathcal O$ over complex semisimple Lie algebras

For a given finite-dimensional complex semisimple Lie algebera $\mathfrak g$, we fix Cartan $\mathfrak h$ and Borel subalgebras $\mathfrak b$, then we have the BGG category $\mathcal O$. As usual, we ...
1 vote
0 answers
77 views

n-Gorenstein algebras and tilting modules

Let $\Lambda$ be an artin algebra over a commutative artinian ring $R$. $\Lambda$ is said to be $n$-Gorenstein, for some natural number $n$, provided it have finite self-injective dimension at most $n$...
5 votes
0 answers
380 views

A tensor product for dg-categories

For a finite group denote by $\mathbf{Ch}^G$ the dg-category of $G$-representations in chain complexes over a field. Is there a tensor product $\otimes$ of dg-categories (similar to the Deligne ...
3 votes
0 answers
68 views

Derived invariant algebras and cluster tilting objects

This question is perhaps a little stupid as I have barely any evidence for it, but another thread just reminded me about it so maybe someone has an idea or counterexample for this. Let $A$ be a ...
0 votes
0 answers
116 views

A question on the paper "The classification of algebras by dominant dimension"

I'm reading the paper "the classification of algebras by dominant dimension" by Bruno J.Mueller, the link is here http://cms.math.ca/10.4153/CJM-1968-037-9. In the proof of lemma 3 on page 402, there ...
2 votes
0 answers
74 views

Units in the (stable) center of a Frobenius algebra [duplicate]

Let $A$ be a Frobenius algebra with center $Z(A)$ and $I\subset Z(A)$ the ideal of elements in the image of some $A$-bimodule map $A\rightarrow A\otimes A\rightarrow A$, where the second map is ...
3 votes
1 answer
252 views

Higher Extension Group Question

Suppose we have an associative unital ring $R$, and we have an $R$-module $M$ with a length 3 socle filtration, i.e. write $$soc(M) \text{ for the socle of } M,$$ $$soc^2(M) \text{ for the preimage ...
3 votes
1 answer
163 views

Identity for $Ext^1$ for special algebras

Let $A$ be a finite dimensional algebra and assume all modules are also finite dimensional. A module $M$ is said to have dominant dimension at least $n$ in case the term $I_i$ for $i=0,1,...,n-1$ are ...
2 votes
0 answers
207 views

Does the first Tachikawa conjecture imply the Nakayama conjecture?

Let $A$ be a non-selfinjective algebra with dominant dimension at least one and $Af$ a minimal faithful projective-injective left $A$-module (but we use right modules in the following). The Nakayama ...
3 votes
1 answer
258 views

Invertible bimodules which are isomorphic in the stable module category

I'm in the following situation. I have a self-injective finite-dimensional basic algebra $\Lambda$ (hence Frobenius) over a perfect field and two finite-dimensional invertible $\Lambda$-bimodules $M$ ...

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