Skip to main content

All Questions

Filter by
Sorted by
Tagged with
3 votes
1 answer
746 views

Turing degrees of nonstandard models of PA

Since the theorems of (PA + "there is a nonstandard number") are recursively enumerable, by the Low Basis Theorem, WKL0's proof of the completeness theorem gives a nonstandard model of PA of [low ...
user avatar
6 votes
1 answer
988 views

Nonstandard models of PA of large cardinal size

It is easy to overlook the fact that the existence of a given large cardinal provides us with a true arithmetical statement that would otherwise be false if the large cardinal notion were not ...
Jason's user avatar
  • 2,762
11 votes
1 answer
2k views

Uncountable nonstandard models of PA

Standard techniques (no pun intended) can be used to show that countable nonstandard models of Peano Arithmetic are order isomorphic to $\mathbb{N} + \mathbb{Z} \cdot \mathbb{Q}$. Once we have used ...
Jason's user avatar
  • 2,762
2 votes
2 answers
262 views

FTA in first order setting

When I took model theory is an undergraduate, early on we wrestled with trying to state the fundamental theorem of arithmetic in the first order language of arithmetic. The problem was that we needed ...
Elmore's user avatar
  • 23
3 votes
0 answers
771 views

Why isn't Montgomery modular exponentiation considered for use in quantum factoring?

It is well known that modular exponentiation (the main part of an RSA operation) is computationally expensive, and as far as I understand things the technique of Montgomery modular exponentiation is ...
Steve Huntsman's user avatar
4 votes
1 answer
876 views

Derivability conditions for Robinson arithmetic

Two pieces of hearsay I have encountered about Robinson's Q: Q fails to satisfy the Löb derivability conditions; Pudlák criticised the Löb derivability conditions and suggested rival, weaker ...
Charles Stewart's user avatar
18 votes
3 answers
1k views

Computable nonstandard models for weak systems of arithmetic

By Tennenbaum's theorem, PA itself does not have any computable nonstandard models. The integer polynomials which are 0 or have a positive leading coefficient form a computable nonstandard model of ...
user avatar
5 votes
2 answers
983 views

finite or infinite many quadratic fields embedding into quaternion algebras?

Suppose $H$ is a indefinite quaternion algebra over $\mathbb{Q}$. Are there infinitely many quadratic fields that can be embedded into $H$?
TOM's user avatar
  • 709
14 votes
3 answers
2k views

Which recursively-defined predicates can be expressed in Presburger Arithmetic?

In Presburger Arithmetic there is no predicate that can express divisibility, else Presburger Arithmetic would be as expressive as Peano Arithmetic. Divisibility can be defined recursively, for ...
17 votes
3 answers
3k views

Gödel's Incompleteness Theorem and the complexity of arithmetic

In How complicated can structures be? Jouko Väänänen says: The guiding result of mathematical logic is the Incompleteness Theorem of Gödel, which says that the logical structure of number theory ...
Hans-Peter Stricker's user avatar
25 votes
2 answers
3k views

Is there a known natural model of Peano Arithmetic where Goodstein's theorem fails?

(I've previously asked this question on the sister site here, but got no responses). Goodstein's Theorem is the statement that every Goodstein sequence eventually hits 0. It turns out that this ...
Jason DeVito - on hiatus's user avatar
68 votes
4 answers
12k views

Nelson's program to show inconsistency of ZF

At the end of the paper Division by three by Peter G. Doyle and John H. Conway, the authors say: Not that we believe there really are any such things as infinite sets, or that the Zermelo-Fraenkel ...
Andreas Thom's user avatar
  • 25.5k
1 vote
1 answer
274 views

Natural number properties as uninterpreted functions in first order logic

Can we express the following property of natural numbers as FOL. The property given below is only indicative, I am more interested in knowing how the concepts such as "infinitely many X exists for so ...
Akshar Prabhu Desai's user avatar
8 votes
2 answers
1k views

Weakest subsystems of second order arithmetic for mathematical logic

It is known that to prove completeness of first-order logic for countable languages WKL0 is enough. But, is it the weakest subsystem where one can prove it? What about the incompleteness theorems? Is ...
Marc Alcobé García's user avatar
34 votes
8 answers
8k views

Arithmetic fixed point theorem

I want to understand the idea of the proof of the artihmetic fixed point theorem. The theorem is crucial in the proof of Gödel's first Incompletness theorem. First some notation: We work in $NT$, the ...
Martin Brandenburg's user avatar
12 votes
1 answer
1k views

How to locate the paper that established Robinson Arithmetic?

If I'm not mistaken, it was in his seminal paper “An Essentially Undecidable Axiom System”, published in Proceedings of the International Congress of Mathematicians (1950), 1952:729–730, where R.M. ...
Jose Brox's user avatar
  • 2,992
13 votes
7 answers
7k views

Are real numbers countable in constructive mathematics?

We are talking about ordinary reals in constructive mathematics. Let represent each real number by infinite converging series: $$r = [\;(a_0,b_0),(a_1,b_1),...,(a_i,b_i),...\;]$$ $$where\quad a_i \...
25 votes
3 answers
3k views

Composite pairs of the form n!-1 and n!+1

It's well known that the numbers of the form $n!\pm1$ are not always prime. Indeed, Wilson's Theorem guarantees that $(p-2)!-1$ and $(p-1)!+1$ are composite for every prime number $p > 5$. Is ...
François G. Dorais's user avatar
16 votes
3 answers
19k views

Non-computable but easily described arithmetical functions

I have read about the existence of functions of the kind described in the title in several places, but never seen an instance of them. Sorry if this is too much an elementary question to be posted ...
Marc Alcobé García's user avatar
42 votes
7 answers
3k views

How would one even begin to try to prove that a simple number-theoretic statement is undecidable?

This question is closely related to this one: Knuth's intuition that Goldbach might be unprovable. It stems from my ignorance about non-standard models of arithmetic. In a comment on the other ...
gowers's user avatar
  • 29k
9 votes
4 answers
3k views

Incompleteness and nonstandard models of arithmetic

The following are a collection of doubts, some of which shall have concrete answers while others may have not. Any kind of help will be welcome. Reading Peter Smith's "Gödel Without (Too Many) Tears",...
Marc Alcobé García's user avatar
8 votes
1 answer
2k views

models of PA which are isomorphic but not elementarily equivalent?

On page 164 of his book Models of Peano Arithmetic, Kaye states Friedman's Theorem: Let $M{\vDash}PA$ be nonstandard and countable, let $a\in M$ and let $n\in {\mathbb N}$. Then there is a proper ...
Adam's user avatar
  • 3,267
2 votes
2 answers
980 views

What is cardinality of the set of true undecidable minimal sentences in a formal theory of aritmetic

Let T be a true theory of arithmetic to which the incompleteness theorems apply. Consider two sentences in the language of T to be equivalent if they are provably equivalent over T. How many ...
Halfdan Faber's user avatar
10 votes
4 answers
5k views

Historically first uses of mathematical induction

I'm interested in find out what were some of the first uses of mathematical induction in the literature. I am aware that in order to define addition and multiplication axiomatically, mathematical ...
user avatar
10 votes
2 answers
1k views

A question about open induction

An old theorem of A. J. Wilkie (Some results and problems on weak systems of arithmetic, Logic Colloquium '77) asserts that a discretely ordered ring $R$ can be extended to a model of open induction ...
Sidney Raffer's user avatar
13 votes
3 answers
1k views

Reducing ACA₀ proof to First Order PA

According to the Wikipedia ACA0 is a conservative extension of First Order logic + PA. http://en.wikipedia.org/wiki/Reverse_Mathematics First of all I have a few questions about the proof: a - What ...
Lucas K.'s user avatar
  • 1,659
17 votes
7 answers
2k views

Non-constructive proofs of decidability?

Are there examples of sets of natural numbers that are proven to be decidable but by non-constructive proofs only?
3 votes
3 answers
2k views

"Interesting" properties of sets of natural numbers

On Wikipedia, there is a list of properties of sets of reals, which are in some sense "interesting": just have a look. I could not find a comparable list of properties of sets of natural numbers (...
1 vote
1 answer
365 views

Naturally definable sets of natural numbers (3)

[This shall be the last of a series of questions, see Naturally definable sets of natural numbers (2)] I cannot explain why I have been so stubborn not to see the most straight-forward definition for ...
Hans-Peter Stricker's user avatar
-1 votes
1 answer
679 views

Naturally definable sets of natural numbers (2): Can the circle be broken?

(follow-up to: Naturally definable sets of natural numbers) Every formula $\Psi(x)$ in the first-order language of Peano arithmetic defines a set of natural numbers. Some of these sets are finite, ...
Hans-Peter Stricker's user avatar
4 votes
2 answers
292 views

Goedelizability and decidability of a property of Peano formulas

Sorry for not knowing the answers to these elementary questions: Is the property of formulas of the first-order language of Peano arithmetic of "defining a finite set of natural numbers" goedelizable?...
Hans-Peter Stricker's user avatar
-1 votes
3 answers
1k views

Naturally definable sets of natural numbers

(This is a follow-up question from over there: Natural models of graphs.) (And it has a follow-up question over there: Naturally definable sets of natural numbers (2): Can the circle be broken?) ...
Hans-Peter Stricker's user avatar
26 votes
3 answers
7k views

Presburger Arithmetic

Presburger arithmetic apparently proves its own consistency. Does anyone have a reference to an exposition of this? It's not clear to me how to encode the statement "Presburger arithmetic is ...
Brendan Cordy's user avatar
27 votes
5 answers
4k views

What is induction up to $\varepsilon_0$?

This is a question asked out of curiosity, and because I can't understand the Wikipedia page. I have often been told that PA cannot prove the validity of induction up to $\varepsilon_0$, which has ...
David E Speyer's user avatar

1
3 4 5 6
7