Skip to main content

All Questions

Filter by
Sorted by
Tagged with
1 vote
0 answers
112 views

Reference request for Leibniz rule and spectral sequences

Suppose $A_*$,$B_*$, and $C_*$ are chain complexes equipped with filtrations and a map $m:A_* \otimes B_* \to C_*$ respecting these filtrations. I am looking for a reference for the fact that the map $...
eeeeee's user avatar
  • 41
3 votes
0 answers
166 views

Edge map in derived categories

Let $\mathscr{A},\mathscr{B}$ be abelian categories, the first with enough projectives, together with a right-exact functor $F\colon \mathscr{A}\to\mathscr{B}$ (in my example, it is a tensor product, ...
Filippo Alberto Edoardo's user avatar
6 votes
0 answers
237 views

A Poincare dual spectral sequence for equivariant cohomology: extension to generalized cohomology?

This question is a follow-up to my previous question: "Rotated" version of the Atiyah-Hirzebruch spectral sequence In that question, I discussed two different spectral sequences for ...
Dominic Else's user avatar
2 votes
1 answer
273 views

Why only consider decreasing filtrations on cochain complexes?

When reading various literature on spectral sequences one always comes across two setups: A chain complex with an increasing filtration A cochain complex with a decreasing filtration My question is ...
user2520938's user avatar
  • 2,788
3 votes
1 answer
465 views

What bigrading is used in this spectral sequence?

I am reading this paper of Positselski and Vishik, in particular the main theorem: the cohomology algebra of a conilpotent algebra (i.e. the cohomology of its cobar construction) is Koszul if it ...
Pedro's user avatar
  • 1,554
16 votes
1 answer
808 views

"Rotated" version of the Atiyah-Hirzebruch spectral sequence

Let $G$ be a group, $X$ a topological space with $G$-action. For an Abelian group $A$, let $\mathcal{C}^n(X,A)$ be the group of $n$-cochains on $X$ with $A$ coefficients. We can treat this as a $G$-...
Dominic Else's user avatar
7 votes
0 answers
434 views

spectral sequence for a complex with two filtrations

Suppose $(C,d)$ is a chain complex: an abelian group with a map $d:C \to C$ such that $d^2 = 0$ (people like to assume $C$ is graded; if that helps - feel free to do so). A filtration is an ascending ...
Just Me's user avatar
  • 353
7 votes
1 answer
331 views

Does a filtered A_N algebra give rise to a multiplicative spectral sequence?

The question is pretty much in the title. It is a classical fact that a filtered dga gives rise to a multiplicative spectral sequence. It is claimed in Remark 4.1 of https://arxiv.org/pdf/1410.6728....
algebrachallenged's user avatar
3 votes
1 answer
260 views

Strong convergence of whole-plane spectral sequences

I am trying to understand strong convergence for whole-plane spectral sequences in the paper by J.Boardman: https://www.uio.no/studier/emner/matnat/math/MAT9580/v12/undervisningsmateriale/boardman-...
Steve's user avatar
  • 205
4 votes
0 answers
419 views

Cohomology of double complex with exact rows

Let $(C^{p,q},d_h,d_v)$ be an unbounded double complex of modules of some algebra $A$ in an abelien category. Let $d_h,d_v$ be the horizontal and vertical differential respectively. Suppose that (1) ...
Steve's user avatar
  • 205
5 votes
0 answers
543 views

Strong Convergence vs Conditional Convergence for Spectral Sequences (Is there a simple explanation?)

I am curious if there is a relatively simple explanation of what is the difference between strong convergence and conditional convergence for Spectral Sequences? (Hopefully a simpler explanation than ...
yoyostein's user avatar
  • 1,229
4 votes
1 answer
195 views

Can Bockstein Spectral Sequence detect multiple summands of the same power, in homology?

I understand that the differential $d^k$ of the Bockstein S.S. (mod p) is nonzero iff the homology $H_*(X;\mathbb{Z})$ has summand of the form $\mathbb{Z}/p^k$. How about for multiple summands in the ...
yoyostein's user avatar
  • 1,229
8 votes
1 answer
615 views

Functorial construction of ("pre"-)spectral sequences? (Or - what is the "higher structure" underlying spectral sequences?)

Let $\mathcal{C}$ be a stable $\infty$-category. Let $Fun(\mathbb{Z},\mathcal{C})$ be the category of sequences of objects in $\mathcal{C}$. Where the category $\mathbb{Z}$ stands for the nerve of the ...
Saal Hardali's user avatar
  • 7,789
6 votes
1 answer
241 views

For which exact couples do associated spectral sequences degenerate at $E_1$?

It is well known that a bigraded exact couple of objects of an abelian category yields a spectral sequence (cf. https://ncatlab.org/nlab/show/exact+couple#SpectralSequencesFromExactCouples). My ...
Mikhail Bondarko's user avatar
8 votes
1 answer
363 views

Adams spectral sequence and short exact sequences. Some clarifications

as the title suggests I'm looking for some clarifications in the computations of the ext charts of some $A(1)$-modules arising as extensions of other modules. In particular, I've the following example ...
Luigi M's user avatar
  • 503
5 votes
0 answers
520 views

Spectral sequences coming from filtrations (Postnikov systems) in triangulated categories: references and convergence

Let $c^i: M^{\ge i+1}\to M^{\ge i}$ for $i\in \mathbb{Z}$ be an sequence of morphisms in a triangulated category $C$ and assume that $M^{\ge i}$ are equipped with compatible morphisms into an object $...
Mikhail Bondarko's user avatar
3 votes
0 answers
310 views

Functoriality of Leray homology spectral sequences of fibrations

Let $p\colon E\to B$ and $p'\colon E'\to B'$ be two fibrations. Assume for simplicity that $B,B'$ are simply connected. Let we have morphism of these fibrations, i.e. two continuous maps $$f\colon E\...
asv's user avatar
  • 21.8k
2 votes
0 answers
108 views

Relating inflation maps from spectral sequences in lower and higher dimensions

The spectral sequence has some nice property. Consider $ N \to G \overset{R}{\to} Q $ and $G/N=Q$. There is a spectral sequence $\{E^{p,q}_n, d_n\}$ with: (i) The differential is defined as a map $...
wonderich's user avatar
  • 10.5k
9 votes
1 answer
455 views

Is this sequence of Lie algebra cohomology a part of spectral sequence?

There is an exact sequence $$0 \to H^2(\mathfrak{g}, k) \to H^1(\mathfrak{g}, \mathfrak{g}^*) \to H^0(\mathfrak{g}, S^2\mathfrak{g}) \xrightarrow{d} H^3(\mathfrak{g}, k) \to H^2(\mathfrak{g}, \...
evgeny's user avatar
  • 1,980
7 votes
0 answers
374 views

Arbitrarily non-degenerate Hodge to de Rham spectral sequence

It is true that for any $n$ there exists a compact complex manifold which Frolicher spectral sequence does not degenerate at the $n$-th page(https://arxiv.org/pdf/0709.0481.pdf). Does the analogous ...
SashaP's user avatar
  • 7,377
5 votes
2 answers
651 views

Inflate a finite-group cocycle into coboundary in non-Abelian groups

Edit: In case that there is no solution for the original question, I modify to enrich the question. We like to ask a possible specific inflation a $H^3(Q, \mathbb{R} /\mathbb{Z})$ cocycle with a ...
miss-tery's user avatar
  • 755
0 votes
1 answer
143 views

Trivialize a cup-product 2-cocycle of $G$ in a larger group $J$

I like to ask a simple question: how to trivialize a cup-product 2-cocycle of $G$ into a 2-coboundary of $J$ in a larger group $J$. Let us take a nontrivial 2-cocycle $\omega_3^G(g_a, g_b) \in H^2(G,\...
miss-tery's user avatar
  • 755
2 votes
1 answer
264 views

Trivialize a cup-product 3-cocycle of $G$ in a larger group $J$

Inspired by this question, let us take a nontrivial 3-cocycle $\omega_3^G(g_a, g_b, g_c) \in H^3(G,\mathbb{R}/\mathbb{Z})$ in the cohomology group of $G$ with $U(1)=\mathbb{R}/\mathbb{Z}$ coefficient. ...
miss-tery's user avatar
  • 755
6 votes
1 answer
563 views

a question about Bockstein spectral sequence

I find the following theorem for Bockstein spectral sequence at http://pages.vassar.edu/mccleary/files/2011/04/MC10.fin_.pdf, page 459: Question. for a fixed $k$, if $\beta$ does not hit $H_k(X;\...
Shiquan Ren's user avatar
  • 1,990
10 votes
1 answer
657 views

Cap product on Leray-Serre spectral sequences

Let $\ p:X\to B\ $ be a fibration of spaces with fiber $F$. Then there are homological and cohomological Leray-Serre spectral sequences $E^{r}_{pq}$ and $E_r^{pq}$ that converge to $H_*(X)$ and $H^*(...
Sergei Ivanov's user avatar
6 votes
0 answers
366 views

Transgression map spectral sequence of Ext

Let $X$ be a scheme over $k$ and $p:\ X \to Spec(k)$ the structure morphism. If $M$ is an étale sheaf of abelian groups over $Spec(k)$ I have a Grothendieck spectral sequence $$E^{p,q}_2=Ext^p_k(M,R^...
user136725's user avatar
17 votes
2 answers
1k views

Grothendieck spectral sequence when one of the functors is contravariant

Let $f \colon X \rightarrow S$ be a morphism of schemes. I am interested in computing the cohomology groups of $$ \mathbf{R}\mathscr{H}om(\mathbf{R}f_* \mathcal{O}_X, \mathcal{O}_S) $$ in terms of $\...
Lisa S.'s user avatar
  • 2,663
2 votes
0 answers
216 views

completion and convergence of spectral sequence

I would like to understand the connection between $p$-adic completion and the strong convergence of a spectral sequence. Precisely, suppose $E^2_{s,t}\implies G_{s+t}$ is a first quadrant strongly ...
user83492's user avatar
12 votes
3 answers
1k views

Lyndon–Hochschild–Serre spectral sequence for a non-normal subgroup

Is there an analogue of the Lyndon–Hochschild–Serre spectral sequence for a non-normal subgroup? What can you say about it? Can you describe $E^{p, q}_1$ ? What is about $E^{p, q}_2$? What is the best ...
quinque's user avatar
  • 385
2 votes
0 answers
1k views

What is a Beilinson spectral sequence?

I'm writing to ask just a question. I would like to understand better what is the Beilinson's spectral sequence and how it can be used. Is there any useful and clear reference you advice to someone ...
Lucke's user avatar
  • 21
1 vote
0 answers
184 views

A naturality question concerning the universal coefficient spectral sequence

I am reading Hillman's book "algebraic invariants of links" and on page 20 he mentions the following universal coefficient spectral sequence. Let X be a connected finite CW complex.Let $H$ be a ...
Anthony Conway's user avatar
6 votes
1 answer
2k views

cohomology version of Cartan-Leray spectral sequence that deduces cup product

On page 338, A User's Guide to Spectral Sequences. 2nd Edition, by John McCleary, Theorem 8.9, there is a Cartan-Leray spectral sequence for homology: If $X$ is a connected pace on which the group $\...
Shiquan Ren's user avatar
  • 1,990
6 votes
1 answer
458 views

Spectral sequence of a bicomplex equipped with a group action

Let $(A_1^\bullet,\partial_1)$ and $(A_2^\bullet,\partial_2)$ be complexes of $\mathbb{C}$-vector spaces. We suppose that $(A_1^\bullet,\partial_1)$ and $(A_2^\bullet,\partial_2)$ are equipped with ...
Yeping Zhang's user avatar
2 votes
0 answers
747 views

What is the abutment filtration of the second spectral sequence of hypercohomology?

I have been recently learning about spectral sequences, following mainly Illusie's notes and EGA, and I am about to write some expository notes, but there are still some points that I was not able to ...
Nuno's user avatar
  • 142
10 votes
0 answers
813 views

On functoriality of the Leray spectral sequence

The Leray spectral sequence is functorial in the following sense: given a commutative square of spaces, $$\begin{matrix} A & \to & B \\ \downarrow & & \downarrow \\ C & \to & D ...
Dan Petersen's user avatar
  • 40.2k
6 votes
2 answers
502 views

Interpretations of differentials in hypercohomology spectral sequences as Yoneda products

I would like to know whether the differentials in a particular hypercohomology spectral sequence can each be interpreted, in some natural way, as Yoneda products between extension groups. More ...
Christopher Drupieski's user avatar
12 votes
2 answers
523 views

A question on some computation of group cohomologies

Let $G=H\times J$, where $H\cong J\cong C_2$ (cyclic group of order 2). Let $M \cong \mathbb{Z}$ be a $G$-module via "trivial $H$-action and negation $J$-action". My question is "What are the group ...
Callum P Dunne's user avatar
9 votes
2 answers
1k views

H^d[U(1)^n,U(1)] of the Borel cohomology and Chern-Simons theory

Firstly I apologize that I am a physicist, with a relatively unrigorous math training. My approach of the problem can be Feynman style. Below $Z$ is the integer $\mathbb{Z}$, and $U(1)$ Abelian group ...
wonderich's user avatar
  • 10.5k
5 votes
0 answers
675 views

Do exact functors commute with spectral sequences ?

Let $F: \mathcal{A} \to \mathcal{B}$ be an exact covariant functor of abelian categories and let $$\mathscr{C}: A \to A \to B \to A$$ be an exact couple in $\mathcal{A}$ with corresponding spectral ...
Ralph's user avatar
  • 16.2k
0 votes
1 answer
799 views

Spectral sequence for composition of global sections and tensor product of sheaves

Hi all, on the forum page http://www.groupsrv.com/science/about506648.html one can read the following (i cut out nonimportant parts): Question: Does anyone know any condition (non trivial) that ...
Joachim's user avatar
  • 469
10 votes
3 answers
2k views

Serre Spectral Sequence of Representations

Suppose that $G$ is a group acting on a fibre bundle $(F,E,B)$ by bundle automorphisms. In this case, the action automorphisms $E\to E$ give the integral homology $H_\ast(E;\mathbb{Z})$ the structure ...
Peter Crooks's user avatar
  • 4,920
2 votes
0 answers
477 views

Morphisms of Spectral Sequences and alternating products

Let $E_{a,b}^{r}, F_{a,b}^{r}$ be two (co)homologica first quadrant spectral sequences of vector spaces over a field $K$, and $f : E \to F$ be a morphism of spectral sequences. Assume that morphisms $...
2 votes
1 answer
186 views

Can I bound the degree of a contracting homotopy in an exact filtered complex?

Suppose that I have given you a bigraded vector space $V = \bigoplus_{i,j} V_{i,j}$. The first grading is a "homological" $\mathbb Z$-grading, and the second is an independent $\mathbb Z$-grading. ...
Theo Johnson-Freyd's user avatar
6 votes
1 answer
855 views

What kind of spectral sequences come from double complexes?

Given a double complex in the first quadrant, one can derive from it a (homological or cohomological) spectral sequence converging to the (co)homology of the total complex of the double complex. My ...
Hiro's user avatar
  • 945
6 votes
1 answer
1k views

Unbounded complexes, resolutions and computation of derived functors

Hey guys, let $F: \mathcal{A} \rightarrow \mathcal{B}$ be a left exact functor between abelian categories with enough injectives, let $K \in Kom(\mathcal{A})$ be an unbounded complex, I've heard that ...
Mario Carrasco's user avatar
7 votes
2 answers
2k views

isomorphic spectral sequences => quasi-isomorphic filtered chain complexes?

Let $(C,\partial)$ and $(C',\partial')$ be chain complexes of $R$-modules where $R$ is a (commutative) ring. Let $F$ and $F'$ be finite filtrations of $C$ and $C'$ respectively, i.e., $$\varnothing = ...
Vidit Nanda's user avatar
  • 15.5k
7 votes
2 answers
4k views

Conditions for the restriction $H^i(G,A)\to H^i(H,A)$ being surjective

I was wondering what the condition is for the restriction map (in group cohomology) $H^i(G,A)\to H^i(H,A)$ to be surjective. I am a little confused about when maps between cohomology groups are ...
Earthliŋ's user avatar
  • 1,211
4 votes
2 answers
1k views

Tracking spectral sequence differentials

I read a number of posts here on MO, but haven't quite found an answer to the question of where the differentials in a spectral sequence come from. I came across a differential $d^{0,1}$ on the $E_2$-...
Earthliŋ's user avatar
  • 1,211
12 votes
4 answers
1k views

Triply graded spectral sequence?

As we know, most of the spectral sequences are doubly graded. However, this "doubly graded" condition is not a part of the formal definition of spectral sequence. Is there any useful triply (quadruply,...
Zuriel's user avatar
  • 1,108
5 votes
1 answer
1k views

Inverse limit of spectral sequences

I find myself in the following situation: I have a sequence of first quadrant spectral sequences, let's call them $ E(n)_{p,q}^* $, each convergent to $E(n)_{p,q}^\infty$, with spectral sequence ...
Pablo Zadunaisky's user avatar