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Ways to decompose a torus for finite element method so that each cell contains a complete revolution of the major radius

I've got a finite element problem involving paths around the interior of a torus. For this particular problem I think I could make things more computationally efficient if each cell in the mesh made ...
altie's user avatar
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109 views

finiteness of the dimensions of cohomologies of open subsets of a compact manifold

Let $M$ be a compact differentiable manifold which can be covered by two open subsets $U$ and $V$. Then $H_{\text{dR}}^n(M)$ is finite-dimensional for all $n$. But how about $U$, $V$ and $U\cap V$? ...
Alberto Jermaine's user avatar
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Degree of sequence of mappings

If $f_n$ is a sequence of smooth orientation preserning mappings of degree one between open annuli $A(1,r):=\{x: 1< |x| < r \}$ and $A(1,r_n)$, $r>1$ and $r_n>1$, on the Euclidean space $\...
Marijan's user avatar
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Is the cap product bilinear?

This is probably a stupid question, so I apologize in advance. On p. 239 of Hatcher's book, he defines the cap product $C_k(X;R)\times C^l(X;R)\to C_{k-l}(X;R)$ for $k\geq l$, which he claims is $R$-...
Mr-Cups's user avatar
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635 views

Do homotopic non-intersecting simple closed curves separate the surface?

Let $C_1$ and $C_2$ be two simple closed curves on an orientable compact surface $S$, such that: They are homotopic to each other. They are set-theoretically disjoint. Is $S\setminus(C_1 \cup C_2)$ ...
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How to compute the Betti numbers of S-D for a surface S and a divisor D?

Let S be a projective non-singular surface and D a Cartier divisor which has a smooth representative. Can the Betti numbers of S-D be represented by the Betti numbers of S and D? In a paper $b_i(S-D)=...
rose's user avatar
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Finding a ribbon graph for a mapping class group action

Turaev defines TQFT $(T, \tau)$ in his book "Quantum invariants of knots and 3-manifolds". He uses it to define an action of a mapping class group of a d-surface $\Sigma$. This action $\epsilon$ is ...
Link S's user avatar
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236 views

Topological K-theory of Bohr compactification of real numbers

I am interested in the K-theory of the Bohr compactification $\mathbb{R}_B$ of the real numbers. Do we have $K_0(C(\mathbb{R}_B))$ isomorphic to $K_1(C(\mathbb{R}_B))$ ? More generally, what do we ...
Oliver's user avatar
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308 views

A modified version of K-theory for manifolds ?

If $X$ is a compact smooth manifold, $K^{0}(X)$ can be defined as the algebraic $K_{0}$-group of $C^{\infty}(X)$. In order to do that we use the following equivalence relation: we say that two ...
S.Z.'s user avatar
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Euler characteristic of a subset of cartesian product induced by a group action

let $X$ be a CW-complex on which a finite group $G$ acts. define $$F=\{ (x,gx)\;|\; x\in X ,g \in G \}$$ i want to compute the Euler characteristic of $F$. I wrote $$F=\cup_{g\in G}{F_g}\;\;,\;\; ...
student's user avatar
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Is $GL_{S^1}(H)$ (for $H$ Hilbert space ) path-connected?

Due to the negative answer to my last question I want to know if at least the following is true: Let H be an infinite dimensional separable complex Hilbert space with $S^1$-action. Let $\text{Gl}_{S^...
J Fabian Meier's user avatar
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185 views

the boundary homomorphism $[\Sigma S^{n-1},X]\to[S^n,X]$ is identity?

Given a Puppe sequence $\cdots \to S^{n-1} \to Y \to S^n(\simeq Y/S^{n-1}) \to \Sigma S^{n-1} \to \cdots$, where $Y=S^{n-1}\cup_{2\iota} e^n$ where $\iota:S^{n-1}\to S^{n-1}$ is identity, we have a ...
Jino's user avatar
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Meaning of Regular Neighborhood for Homology Basis Curves in $S_{g,2}$

I have been trying to understand the meaning of the expression "regular neighborhood" in the context described below, but I'm stuck: We have a collection of curves $c_i$ for $i=1,2,..,n$ embedded in ...
Gary's user avatar
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142 views

Homomorphism between the set of n-flats in $R^m$ to some manifold

I am unaware of what the formal definition of "limit" is for a sequence of flats, but for the purpose of this question her is the definition of limit that I am using: Consider a sequence $s_1, s_2, ...
yrudoy's user avatar
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