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Prime numbers, diophantine equations, diophantine approximations, analytic or algebraic number theory, arithmetic geometry, Galois theory, transcendental number theory, continued fractions

60 votes

Polynomial representing all nonnegative integers

The search turned up a 1981 paper by John S.Lew (in the Unsolved problems section) Polynomials in Two Variables Taking Distinct Integer Values at Lattice-Points which discusses related problems, and …
Martin Sleziak's user avatar
33 votes
5 answers
8k views

Why no abelian varieties over Z?

Motivation I learned about this question from a wonderful article Rational points on curves by Henri Darmon. He gives a list of statements (some are theorems, some conjectures) of the form the set $\ …
7 votes
1 answer
554 views

Hasse principle for a group

$\DeclareMathOperator\PSL{PSL}$In the paper Ono - "Hasse principle" for $\PSL_2 (\mathbb Z)$ and $\PSL_2(\mathbb F)$ there's a definition of a Hasse principle for a group $G$, but I don't completely g …
12 votes
3 answers
2k views

Order of the Tate-Shafarevich group

I thought that the order of the Tate-Shafarevich group should always be a square (it's also supposed to be finite, but for the purposes of this question let's assume we know this) but I don't seem to …
3 votes
7 answers
2k views

Bertrand's postulate [closed]

I believe there was an old conjecture that there's always a prime number between N and 2N. What's the history and how is this proven is the easiest/elementary/deepest ways?
8 votes
2 answers
3k views

What is the Beilinson regulator?

Trying to understand answer to this question. What is the (Beilinson) higher regulator of a number field?
21 votes

Statements in group theory which imply deep results in number theory

I'm sure you omitted this just because it's too classic: big part of group theory was invented to prove that most algebraic numbers cannot be constructed by radical extensions. It's still the best, …
David E Speyer's user avatar
14 votes
3 answers
1k views

Non-simply-connected smooth proper scheme over Z?

Source This question came up in the discussion between Kevin Buzzard and Minhyong Kim in the comments to Smooth proper scheme over Z. It was 2 weeks ago, so I took the liberty of posting it as commun …
27 votes
5 answers
5k views

Where stands functoriality in 2009?

Robert Langlands is famous in number theory for making famous and deep conjectures about very abstract things called automorphic forms, somewhere in the 60s. There's a very interesting article by Lan …
7 votes
1 answer
2k views

Polynomial representing prime numbers

Along the lines of Polynomial representing all nonnegative integers, but likely well-known question: is there a polynomial $f \in \mathbb Q[x_1, \dots, x_n]$ such that $f(\mathbb Z\times\mathbb Z\ …
2 votes
3 answers
1k views

What is the base change in number theory?

I'm somewhat familiar with base change in scheme theory: sometimes a property of a morphism X \to Y survives a base change f:Z\to Y, meaning that X \times_{Y} Z \to Z also has this property. Quest …
8 votes
2 answers
8k views

What does "supersingular" mean?

Are supersingular primes and supersingular elliptic curves related? (this was essentially a subquestion in my earlier question, but still looks sufficiently different to me to deserve a separate post …
10 votes

Why no abelian varieties over Z?

Comments by Anweshi The essential point is what Emerton mentioned, ie the analogy with Minkowski's theorem on number fields with ramification. The basic principle is that "arithmetic is geometry". Nu …
Anweshi's user avatar
  • 7,442
3 votes
2 answers
738 views

Nonnegative polynomial in two variables

What can be said about the polynomials $f\in\mathbb Q[x, y]$ which are nonnegative on $\mathbb R\times \mathbb R$? Motivation: this may lead to progress in the question about polynomial onto map …
1 vote

b^(n-1)=-1 mod n

That would be equivalent to $2(n-1) = k\varphi(n)$ and $n-1\ne k'\varphi(n)$ by Fermat's little theorem for composite numbers. The second condition is equivalent to being able to satisfy first with …
Ilya Nikokoshev's user avatar

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