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Non-commutative rings and algebras, non-associative algebras, universal algebra and lattice theory, linear algebra, semigroups. For questions specific to commutative algebra (that is, rings that are assumed both associative and commutative), rather use the tag ac.commutative-algebra.
3
votes
Non-commutative reduced rings of order $p^2$
A more conceptual path to essentially the same solution:
Lam, a first course in noncommutative rings, pag. 207: (12.7) Theorem. A nonzero ring $R$ is reduced iff $R$ is a subdirect product of domains …
6
votes
Accepted
Properly "transfinitely" Euclidean domains
Yes, they exist. Even if the problem is left open in the the papers of T. Motzkin and P. Samuel cited in Comparing different Euclidean algorithms on a Euclidean domain
the problem is solved in
J. …
1
vote
Does a BCL algebra define a partial order?
The paper you cite says
in theorem 2.1 3) that
Any a BCH-algebra is a BCL-algebra
The paper http://emis.library.cornell.edu/journals/NSJOM/Papers/25_1/NSJOM_25_1_075_082.pdf
gives in example 1 …
2
votes
Are there atomistic ortholattices which are not modular?
Examples are contained in a classical book about semimodular lattice theory: F. Maeda and S. Maeda "theory of symmetric lattices". See that book for details and refernces concerning what follows.
Let …
1
vote
Examples of cancellative normal semigroups
positive cone of (nonabelian) totally ordered groups (like the multiplicative group in Hilbert's ordered skew field to show that Pappus theorem is not provable in ordered affine geometry). More exampl …
7
votes
When does a planar ternary ring uniquely coordinitise a projective plane?
Too long for a comment.
Contrary to what wikipedia and the accepted answer say, the following paper proves that there are non-Moufang infinite projective planes where the collineation group is transit …
2
votes
A non-orthomodular orthocomplemented lattice identity?
You are interested in a ortholattice identity in two variables. Now, the word problem for free ortholattices and free orthomodular lattices is solvable; hence you can apply these algorithms to obtain …
3
votes
Universal constructions that factor through endomorphisms
From Hodges, model theory, section 9.3 Word-constructions pag. 431:
There is no agreed name for functors $\Gamma$ as defined above. To category theorists they are the left adjoints of forgetful funct …
1
vote
Metrics and completions on the direct limit of matrices of all sizes over arbitrary fields
It seems that you might like the (normalized) rank metric, producing the first algebraic examples of continuous geometries and their coordinatizing rings. See the original papers of von Neumann (1936 …
4
votes
An algebra of "integrals"
Since specific pre-determined axioms might have problems, to formalize the problem to give a reasonable value to integrals $\int_0^\infty f$ (with real $f$) where each $F(x)=\int_0^x f$ reasonably exi …
4
votes
Is there an intuitionistic generalized boolean algebra (of Stone)?
The general method to consider "unitless" order structures is the following:
suppose that $C$ is a class of structures such that on each structure $X$ in $C$ a natural order with bounds $0_X,1_X$ is …
1
vote
Integration on Compact Semirings
An easy answer along traditional lines is available iff the measure has "bounded variation" in a suitable sense.
To undestand this, first note that integration with values in Banach algebras (which …
2
votes
IBN for algebraic theories
A. Has the IBN property for algebraic theories in general been studied in the literature?
Yes, mostly by many polish authors. See Gr\"atzer, universal algebra, Chap. 5.
For example, at pag. 198 …
9
votes
Properties of rings that have an elegant description in terms of the associated category of ...
From http://en.wikipedia.org/wiki/Injective_module
Every submodule of every injective module is injective if and only if the ring is Artinian semisimple (Golan & Head 1991, p. 152); every factor modu …