Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 46140
1 vote
Accepted

Series reversion using something like continued fraction

We assume $F(0) \neq 0$, since otherwise we don't satisfy the assumptions for the series reversion. Let $G = G(0)$ be the fixpoint of the recurrence given: $$G(x) = F\left(\frac{x}{G(x)}\right)$$ Mult …
Peter Taylor's user avatar
  • 7,226
3 votes

A special class of weighted Motzkin paths

It's going to be useful to say that horizontal steps at height $0$ have weight $u$ so that we can derive a recurrence: therefore I shall consider $c_n(t, u)$ and look to specialise it to $u=1$ later. …
Peter Taylor's user avatar
  • 7,226
3 votes
Accepted

Fibonacci-Motzkin paths and J-type continued fractions

Grouping the terms of $F(z)$ by the height reached, we get $$F(z) = \frac{1}{(1 - z\gamma_0)} + \frac{z^2 \beta_1}{(1 - z\gamma_0) (1 - z\gamma_1)} + \frac{z^4 \beta_1 \beta_2}{(1 - z\gamma_0) (1 - z\ …
Peter Taylor's user avatar
  • 7,226