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Questions about the branch of combinatorics called graph theory (not to be used for questions concerning the graph of a function). This tag can be further specialized via using it in combination with more specialized tags such as extremal-graph-theory, spectral-graph-theory, algebraic-graph-theory, topological-graph-theory, random-graphs, graph-colorings and several others.

35 votes
Accepted

Graph containing all trees?

See Chung and Graham, On Universal Graphs for Spanning Trees. They prove that the number of edges is $\Theta(n\log n)$.
David Eppstein's user avatar
21 votes
Accepted

Combinatorial proof that large-girth graphs are sparse?

It's known more specifically that any graph with girth ≥ 5 has $O(n^{3/2})$ edges — see e.g. Wikipedia on the Zarankiewicz problem. Here's a combinatorial proof. Suppose that graph $G$ has $\ge kn^{3 …
David Eppstein's user avatar
17 votes

Efficient way of determining isomorphism

A meta-answer: knowing that the answer is yes, for any NP search problem (regardless of completeness), does not help much in finding the answer. The reason is that, if you had an algorithm A that foun …
David Eppstein's user avatar
16 votes

Is this a well known NP-complete problem?

The shortest (in terms of weight) path, constrained to have exactly n (or at most n) edges, can be found in polynomial time. For instance, given your graph $G=(V,E)$ make an expanded graph $H$ that ha …
David Eppstein's user avatar
15 votes

Generalizations of Planar Graphs

There are many generalizations, but one of my favorites is "neighborhood systems": intersection graphs of systems of balls in a Euclidean space of bounded dimension, with the property that any point o …
David Eppstein's user avatar
15 votes

Looking for cubic, bipartite graphs with girth at least six and no cycles of length 8.

Sure, form a torus graph by cutting a big parallelogram out of the tiling of the plane by regular hexagons and gluing opposite sides together. Any short cycle has length 6 (one hex) or length ≥ 10 (tw …
David Eppstein's user avatar
13 votes

Reasons for the importance of planarity and colorability?

A few reasons for the importance of planarity having little to do with the need for maps: A matroid is both graphic and co-graphic if and only if it is the graphic matroid of a planar graph Planar g …
13 votes
Accepted

Graphs of Tangent Spheres

The number of edges in such a graph is linear in the number of vertices, and they can be split into two equal-sized subgraphs by the removal of $O(n^{\frac{d-1}{d}})$ vertices. See e.g. A determinist …
David Eppstein's user avatar
13 votes
Accepted

What (fun) results in graph theory should undergraduates learn?

Planar graph duality and its consequences, e.g. that a connected planar graph is Eulerian iff its dual is bipartite, or Hamiltonian iff its dual can be partitioned into two induced trees. The emergen …
12 votes
Accepted

Proof of Bondy and Chvátal Theorem

Let $G=G_0, G_1, G_2$, etc. be a sequence of graphs where each $G_i$ is formed by performing a single closure step to $G_{i-1}$ — that is, add an edge $uv$ to $G_i$ when $u$ and $v$ together have at …
David Eppstein's user avatar
11 votes

A question on representation of graphs

It's important to clarify what definition of "cycle" you have in mind. In algebraic-graph-theory contexts like this one, the natural definition is that it's a set of edges with even degree at each ver …
David Eppstein's user avatar
11 votes
Accepted

Graphs in which every spanning tree is an independency tree

A graph G has all spanning trees independency if and only if G does not contain two adjacent vertices v and w, neither of degree one, such that the graph G' formed by removing v and w and all their in …
David Eppstein's user avatar
11 votes
Accepted

Algorithms on graphs of bounded degeneracy/arboricity

Bounded degeneracy or arboricity just means that the graph is sparse (number of edges is proportional to number of vertices in all subgraphs). Some ideas that have been used for fast algorithms on th …
David Eppstein's user avatar
11 votes
Accepted

Finding a cycle of fixed length in a bipartite graph

Finding a cycle of length 2k in an arbitrary graph is the same thing as finding a cycle of length 4k in the bipartite graph formed by subdividing every edge. So in general even cycles of fixed length …
David Eppstein's user avatar
11 votes
Accepted

Graphs with many triangles but few complete graphs on 4 vertices

Your statement may be true for large enough values of $c$, but it is not true for all constants $c>0$. Specifically, for small enough values of $c$, form a counterexample $G$ consisting of the disjoi …
David Eppstein's user avatar

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